Laravel问题试图获取非对象的属性“id”

Posted 2023-03-14

【中文标题】Laravel问题试图获取非对象的属性“id”

【英文标题】：Laravel issue Trying to get property 'id' of non-object

【发布时间】：2019-03-27 22:08:44

【问题描述】：

我在这里尝试使用 foreach 循环来循环供应商名称，但出现以下错误

<tbody style="font-size:small">

                    @foreach($material as $material)

                    <tr class="odd" role="row">

!! Form::open(['route'=>'materialsupplier.store','class'=>'form-horizontal p-t-20']) !!
                        <td> $material->name <input type="hidden" value=" $material->id " name="mat_id"></td>
                        <td></td>
                        <td>
                            <div class="form-group $errors->has('sup_id') ? ' has-error' : '' ">

                                <div >
                                    <select class="form-control js-cities" name="sup_id">
                                        <option value="" selected disabled>Select Supplier</option>
                                        @foreach ($supplier as $supplier)
                                         <option value=" $supplier->id">$supplier->company_name</option>
                                        @endforeach
                                    </select>
                                </div>
                            </div>
                        </td>
                        <td>
  Form::submit('Save',['class'=>'far fa-trash-alt btn btn-info btn-sm btn-rounded m-b-1 m-l-5']) 
                           </td>  
                        !! Form::close() !!      
                    </tr>
                    @endforeach
                </tbody>

之后我像这样修改了我的代码

<select class="form-control js-cities" name="sup_id">
 <option value="" selected disabled>Select Supplier</option>
    @foreach ($supplier as $supplier)
     <option value=" $supplier">$supplier</option>
     @endforeach
  </select>

输出

控制器

public function index()
    
       $material = Material::all();
       $supplier = Supplier::all();

   return view('materialMgmt.material_suppliyer.create')->withMaterial($material)->withSupplier($supplier);
    

如何避免出现此错误？

【问题讨论】：

首先，数组表达式和值同名！请更改它：@foreach($material as $material) 和 @foreach ($supplier as $supplier)

谢谢您，先生，您的建议对我帮助很大

【参考方案1】：

我将代码更改如下，它的工作原理

<select class="form-control js-cities" name="sup_id">
      <option value="" selected disabled>Select Supplier</option>
             @foreach ($supplier as $sup)
             <option value=" $sup->id">$sup->company_name</option>
             @endforeach
 </select>

FatemehNB 先生，感谢您的建议。