在scala中将spark决策树模型调试字符串转换为嵌套JSON
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【中文标题】在scala中将spark决策树模型调试字符串转换为嵌套JSON【英文标题】:Convert spark decision tree model debug string to nested JSON in scala 【发布时间】:2017-06-19 06:10:37 【问题描述】:类似于引用here的树json解析,我正在尝试在scala中实现决策树的简单可视化。它与 databricks 笔记本中可用的显示方法完全相同。
我是 scala 的新手,正在努力使逻辑正确。我知道我们必须进行递归调用来构建孩子并在显示最终预测值时中断。我在这里尝试了使用下面提到的输入模型调试字符串的代码
def getStatmentType(x: String): (String, String) =
val ifPattern = "If+".r
val ifelsePattern = "Else+".r
var t = ifPattern.findFirstIn(x.toString)
if(t != None)
("If", (x.toString).replace("If",""))
else
var ts = ifelsePattern.findFirstIn(x.toString)
if(ts != None) ("Else", (x.toString).replace("Else", ""))
else ("None", (x.toString).replace("(", "").replace(")",""))
def delete[A](test:List[A])(i: Int) = test.take(i) ++ test.drop((i+1))
def BuildJson(tree:List[String]):List[Map[String, Any]] =
var block:List[Map[String, Any]] = List()
var lines:List[String] = tree
loop.breakable
while (lines.length > 0)
println("here")
var (cond, name) = getStatmentType(lines(0))
println("initial" + cond)
if (cond == "If")
println("if" + cond)
// lines = lines.tail
lines = delete(lines)(0)
block = block :+ Map("if-name" -> name, "children" -> BuildJson(lines))
println("After pop Else State"+lines(0))
val (p_cond, p_name) = getStatmentType(lines(0))
// println(p_cond + " = "+ p_name+ "\n")
cond = p_cond
name = p_name
println(cond + " after="+ name+ "\n")
if (cond == "Else")
println("else" + cond)
lines = lines.tail
block = block :+ Map("else-name" -> name, "children" -> BuildJson(lines))
else if( cond == "None")
println(cond + "NONE")
lines = delete(lines)(0)
block = block :+ Map("predict" -> name)
else
println("Finaly Break")
println("While loop--" +lines)
loop.break()
block
def treeJson1(str: String):JsValue =
val str = "If (feature 0 in 1.0,2.0,3.0,4.0,5.0,6.0,7.0,8.0,10.0,11.0,12.0,13.0)\n If (feature 0 in 6.0)\n Predict: 17.0\n Else (feature 0 not in 6.0)\n Predict: 6.0\n Else (feature 0 not in 1.0,2.0,3.0,4.0,5.0,6.0,7.0,8.0,10.0,11.0,12.0,13.0)\n Predict: 20.0"
val x = str.replace(" ","")
val xs = x.split("\n").toList
var js = BuildJson(xs)
println(MapReader.mapToJson(js))
Json.toJson("")
预期输出:
[
'name': 'Root',
'children': [
'name': 'feature 0 in 1.0,2.0,3.0,4.0,5.0,6.0,7.0,8.0,10.0,11.0,12.0,13.0',
'children': [
'name': 'feature 0 in 6.0',
'children': [
'name': 'Predict: 17.0'
]
,
'name': 'feature 0 not in 6.0',
'children': [
'name': 'Predict: 6.0'
]
]
,
'name': 'feature 0 not in 1.0,2.0,3.0,4.0,5.0,6.0,7.0,8.0,10.0,11.0,12.0,13.0',
'children': [
'name': 'Predict: 20.0'
]
]
【问题讨论】:
【参考方案1】:您不需要解析调试字符串,而是可以从模型的根节点解析。 参考enter link description here
【讨论】:
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