我的表格视图已创建，但数组未显示在表格视图中，控制台中的所有数据都来了。请帮我解决 json 解析

Posted 2023-03-12

【中文标题】我的表格视图已创建，但数组未显示在表格视图中，控制台中的所有数据都来了。请帮我解决 json 解析

【英文标题】：my table view is created but array is not showing in table view,in console all the data are coming.please help me to solve json parsing

【发布时间】：2016-03-02 07:37:15

【问题描述】：

这是一个响应，我想将此响应值打印到表格视图中： 我正在发布我的 tableview 代码，请检查它是对还是错。 我在这里挣扎了2天，如果有人知道请回复我。

 - (IBAction)search:(UIButton *)sender 


NSString *post =[[NSString alloc]initWithFormat:@"keyword=%@",[keyword text]];
NSLog(@"PostData: %@",post);

NSURL *url=[NSURL URLWithString:@"url"];

NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];

NSString *postLength = [NSString stringWithFormat:@"%lu",(unsigned long)[postData length]];

NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init];
[request setURL:url];
[request setHTTPMethod:@"POST"];
[request setValue:postLength forHTTPHeaderField:@"Content-Length"];
[request setValue:@"application/json" forHTTPHeaderField:@"Accept"];
[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
[request setHTTPBody:postData];
//[NSURLRequest setAllowsAnyHTTPSCertificate:YES forHost:[url host]];

//NSError *error = [[NSError alloc] init];
NSError *error=nil;
NSHTTPURLResponse *response = nil;
NSData *urlData=[NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error];
if (!urlData) 
    NSLog(@"Error: %@", [error localizedDescription]);
    //return NO;



NSLog(@"Response code: %ld", (long)[response statusCode]);



if ([response statusCode] >=200 && [response statusCode] <300)
 
    NSString *responseData = [[NSString alloc]initWithData:urlData encoding:NSUTF8StringEncoding];
    NSLog(@"Response ==> %@", responseData);

    NSError *error = nil;
    NSDictionary *dic = [NSJSONSerialization JSONObjectWithData:urlData
                         options:NSJSONReadingMutableContainers error:&error];
    NSLog(@"json ==> %@ ", dic);
    name     = [[NSMutableArray alloc]init];
    username = [[NSMutableArray alloc]init];

    for (id obj in dic) 
        NSString *nameNameObj=[obj objectForKey:@"name"];
        [name  addObject:nameNameObj];
         NSString *userNameObj=[obj objectForKey:@"username"];
        [username  addObject:userNameObj];

    

    NSLog(@"name array is %@",name);
    NSLog(@"username array is %@",username);

  


- (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView
 
   // Return the number of sections.
    return [name count];
    return 1;
 

- (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section 
  
    return [name count];
  
- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:  
  (NSIndexPath *)indexPath 
  
   static NSString *simpleTableIdentifier = @"MYCustomCell";
   MyCustomCellTableViewCell *cell = (MyCustomCellTableViewCell *)
   [tableView dequeueReusableCellWithIdentifier:simpleTableIdentifier];
   if (cell == nil)
    
     NSArray *nib = [[NSBundle mainBundle]    
     loadNibNamed:@"MyCustomCellTableViewCell" owner:self options:nil];
     cell = [nib objectAtIndex:0];
    
    // apply setters for cell
    cell.nameLbl.text=[name objectAtIndex:indexPath.row];
    cell.usernameLbl.text=[username objectAtIndex:indexPath.row];
    return cell;
 
[
    "id":60,"username":"test001","name":"name",     
    "id":61,"username":"test","name":"",  
    "id":65,"username":"test002","name":"first",
    "id":69,"username":"test003","name":"second", 
    "id":71,"username":"test004","name":"third",
    "id":78,"username":"test005","name":"fourth",
    "id":79,"username":"test006","name":"Name of the person"
]

【问题讨论】：

请在此处添加您的 tableview 委托方法。没有它，我们无法帮助您。

【参考方案1】：

忽略这个，因为你没有使用这个

检查这 2 行：

cell.nameLbl.text = [name objectAtIndex:indexPath.row];
cell.usernameLbl.text = [username objectAtIndex:indexPath.row];

name 是一个数组，在每个索引中都包含一个 NSDictionary。所以如果你想访问它的值，你必须这样做：

cell.nameLbl.text = [[name objectAtIndex:indexPath.row] objectForKey:@"name"];
cell.usernameLbl.text = [[username objectAtIndex:indexPath.row] objectForKey:@"username"]];

编辑：

当您编辑了代码后，修改后的答案将是：

 - (IBAction)search:(UIButton *)sender 


    NSString *post =[[NSString alloc]initWithFormat:@"keyword=%@",[keyword text]];
    NSLog(@"PostData: %@",post);

    ......
    ......

    if ([response statusCode] >=200 && [response statusCode] <300)
    
        NSString *responseData = [[NSString alloc]initWithData:urlData encoding:NSUTF8StringEncoding];
        NSLog(@"Response ==> %@", responseData);
        .....
        .....

        for (id obj in dic) 
            NSString *nameNameObj=[obj objectForKey:@"name"];
            [name  addObject:nameNameObj];
            NSString *userNameObj=[obj objectForKey:@"username"];
            [username  addObject:userNameObj];

        

        .......
        .......
        [self.tableView reloadData];

    

【讨论】：

不，它不工作。数据再次进入控制台但未显示在表格视图中..

@ParveshMishra > 你的名字和用户名数组有数据吗？

2016-03-02 15:38:23.107 UITableView1[7722:105442] 名称数组是 (vfvv, "", "", "Ben Franklin", vneflv, "Ben Franklin", "Name的人”) 2016-03-02 15:38:23.108 UITableView1[7722:105442] 用户名数组是 (test001, test, test002, test003, test004, test005, test006)

cell.nameLbl.text =@"测试文本";检查你是否能看到这个。

所以你可以看到问题不在这里。问题出在其他地方。

【参考方案2】：

可能有以下一些原因：

确保正确设置委托和数据源。

当您收到响应时，在主线程上重新加载 tableView

dispatch_async(dispatch_get_main_queue(), ^                                                                  

      [self.tableView reloadData];
);

从

返回有效单元格

cellForRowAtIndexPath:

返回有效的单元格数

numberOfRowInSection: