如何在屏幕上显示 UIControl 的子类
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【中文标题】如何在屏幕上显示 UIControl 的子类【英文标题】:How to display a Subclass of UIControl on the screen 【发布时间】:2011-06-06 02:18:34 【问题描述】:我通过以下代码创建了一个名为 ToggleImageControl 的 UIControl 子类(参考以下帖子Checkbox image toggle in UITableViewCell)
@interface ToggleImageControl : UIControl
BOOL photoIsStarred;
UIImageView *imageView;
UIImage *normalImage;
UIImage *selectedImage;
@property (nonatomic, assign) BOOL photoIsStarred;
@property (nonatomic, retain) UIImageView *imageView;
@property (nonatomic, retain) UIImage *normalImage;
@property (nonatomic, retain) UIImage *selectedImage;
- (void) toggleImage;
@end
@implementation ToggleImageControl
@synthesize photoIsStarred, imageView, normalImage,selectedImage;
- (id)initWithFrame:(CGRect)frame
NSLog(@"in inti with frame method");
self.normalImage = [UIImage imageNamed: @"blank_star.png"];
self.selectedImage = [UIImage imageNamed: @"star.png"];
self.imageView = [[UIImageView alloc] initWithImage: normalImage];
// set imageView frame
[self addSubview: imageView];
[self addTarget: self action: @selector(toggleImage) forControlEvents: UIControlEventTouchDown];
return self;
- (void) toggleImage
NSLog(@"image toggled");
self.photoIsStarred = !photoIsStarred;
self.imageView.image = (photoIsStarred ? selectedImage : normalImage);
@end
我尝试在表格单元格中创建 ToggleImageControl 的实例,但无法显示“正常图像”。下面的实现中是否缺少某些内容?
//In a UItableview cell
ToggleImageControl *toggleControl = [[ToggleImageControl alloc]initWithFrame:CGRectMake(670, 10,80, 80)];
[cell.contentView addSubview:toggleControl];
【问题讨论】:
【参考方案1】:确保在您的initWithFrame:
方法中调用[super initWithFrame:frame]
。
例如
self = [super initWithFrame:frame];
if (self)
// Initialization
return self;
【讨论】:
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