如何以编程方式在 Firebase 中创建动态链接?迅速
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【中文标题】如何以编程方式在 Firebase 中创建动态链接?迅速【英文标题】:How to create a Dynamic link in Firebase programmatically? Swift 【发布时间】:2018-05-28 16:49:45 【问题描述】:我想创建一个 firebase 动态,但我在 components.shorten
中找不到错误
操作无法完成。长链接不可解析。
我正在关注 firebase 文档,但我可以获得预期的结果。
@IBAction func createGroupAction(_ sender: Any)
let dynamicLinkDomain = "https://a5481.app.goo.gl/"
let appBundleID = "com.vividapartments.myStr.com"
let params:[String : String] = [
"ibi": appBundleID,
"isi": "1222420082",
"efr":"1",
"groupID":"-LDSfWKKbWjyrXiFljT3",
"chatID":"-LDSfWKMbm9mSE2a6EIe"
]
// general link params
let urlParams = params.flatMap ( (key,value) -> String in
return "\(key)=\(value)"
).joined(separator: "&")
guard let deepLink = URL(string:"https://www.mystr.com/groups?\(urlParams)") else return
print("deepLink is \(deepLink)")
//prints:
//deepLink is https://www.mystr.com/groups?isi=1222420082&chatID=-LDSfWKMbm9mSE2a6EIe&efr=1&ibi=com.vividapartments.myStr.com&groupID=-LDSfWKKbWjyrXiFljT3
let components = DynamicLinkComponents(link: deepLink, domain: dynamicLinkDomain)
let iosParams = DynamicLinkIOSParameters(bundleID: appBundleID)
iOSParams.minimumAppVersion = "1.5"
components.iOSParameters = iOSParams
//1. Build the dynamic long link
let longlLink = components.url
print("The long link is \(longlLink!)")
//prints:
//The long link is https://https://a5481.app.goo.gl//?link=https%3A%2F%2Fwww%2Emystr%2Ecom%2Fgroups%3Fisi%3D1222420082%26chatID%3D%2DLDSfWKMbm9mSE2a6EIe%26efr%3D1%26ibi%3Dcom%2Evividapartments%2EmyStr%2Ecom%26groupID%3D%2DLDSfWKKbWjyrXiFljT3&ibi=com%2Evividapartments%2EmyStr%2Ecom&imv=1%2E5
//Set the length of a short Dynamic Link
let options = DynamicLinkComponentsOptions()
options.pathLength = .unguessable
components.options = options
//2. Or create a shortened dynamic link
components.shorten (shortURL, warnings, error) in
if let error = error
print("error is \(error.localizedDescription)")
//prints:
//error is The operation couldn’t be completed. Long link is not parsable: https://https://a5481.app.goo.gl//?link=https%3A%2F%2Fwww%2Emystr%2Ecom%2Fgroups%3Fisi%3D1222420082%26chatID%3D%2DLDSfWKMbm9mSE2a6EIe%26efr%3D1%26ibi%3Dcom%2Evividapartments%2EmyStr%2Ecom%26groupID%3D%2DLDSfWKKbWjyrXiFljT3&ibi=com%2Evividapartments%2EmyStr%2Ecom&imv=1%2E5
return
// TODO: Handle shortURL.
print("shortURL is \(String(describing: shortURL))")
【问题讨论】:
【参考方案1】:感谢您将输出包含在 cmets 中,这样可以轻松发现错误。
-
仅包含动态链接域中的域,例如
let dynamicLinkDomain = "a5481.app.goo.gl"
进一步测试:您可以通过在长链接末尾添加“&d=1”并将其粘贴到浏览器中来调试长链接。
【讨论】:
嗨,我遇到了同样的错误,如果您有解决方案,请查看下面的链接帮助我***.com/q/67019905/11468227以上是关于如何以编程方式在 Firebase 中创建动态链接?迅速的主要内容,如果未能解决你的问题,请参考以下文章
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