如何将 GraphQLObjectType 与 graphql-tag 和 gql-tag 创建的模式结合起来？

Posted 2023-03-08

【中文标题】如何将 GraphQLObjectType 与 graphql-tag 和 gql-tag 创建的模式结合起来？

【英文标题】：How can I combine a GraphQLObjectType with a schema created by graphql-tag with gql-tag?

【发布时间】：2021-02-25 19:25:49

【问题描述】：

我使用 graphql-tag 和 apollo-server-express 来连接为 api 构建 graphQL 端点。目前我创建这样的架构定义：

properties.js

let model = 
const typeDefs = gql`
    extend type Query 
        property(id: Int!): [Property]
    
    
    type Property 
        title: String
        street: String
        postalcode: String
        city: String
        country: String
    
`
const resolvers = 
    Query: 
        property: getTheEntriesFromDB,
    ,


model.typeDefs = typeDefs;
model.resolvers = resolvers;

module.exports = model;

和 server.js

const server = new ApolloServer(
    modules: [
        require('./modules/properties'),
    ],
):

但是，我想根据数据库架构自动创建类型“属性”。我发现我可以像这样创建一个 GraphQLObjectType：

const propertyType = new graphql.GraphQLObjectType(
    name: 'Property',
    fields: 
        title:  type: graphql.GraphQLString ,
        street:  type: graphql.GraphQLString ,
        postalcode:  type: graphql.GraphQLString ,
        city:  type: graphql.GraphQLString ,
        country:  type: graphql.GraphQLString ,
    
);

但我不知道如何将其与

let model = 
const typeDefs = gql`
    extend type Query 
        property(id: Int!): [Property]
    
`
const resolvers = 
    Query: 
        property: getTheEntriesFromDB,
    ,


model.typeDefs = typeDefs;
model.resolvers = resolvers;

module.exports = model;

创建最终架构。有人可以指出我正确的方向吗？ 非常感谢任何帮助。提前非常感谢！

【参考方案1】：

好的，经过数小时的反复试验和搜索，我找到了适合我的解决方案：

properties.js

const  buildASTSchema, GraphQLObjectType, GraphQLSchema, GraphQLString, parse, printSchema  = require('graphql')

let model = 

const propertyType = new GraphQLObjectType(
    name: 'Property',
    fields: 
        title:  type: GraphQLString ,
        street:  type: GraphQLString ,
        postalcode:  type: GraphQLString ,
        city:  type: GraphQLString ,
        country:  type: GraphQLString ,
    
);

let typeDefs = gql`
    extend type Query 
        property(id: Int!): [Property]
    
    
    type Property 
        id: Int
    
`

typeDefs.definitions[0].kind = 'ObjectTypeDefinition' //replace ObjectTypeExtension with ObjectTypeDefinition to make AST 'valid' but keep extend in gql-tag to satisfy code inspection in ide
typeDefs = parse(printSchema(buildASTSchema(typeDefs)).replace('type Query ', 'extend type Query ') + printSchema(new GraphQLSchema( types: [ propertyType ])).replace('type Property ', 'extend type Property '))

const resolvers = 
    Query: 
        property: getTheEntriesFromDB,
    ,


model.typeDefs = typeDefs;
model.resolvers = resolvers;

module.exports = model;

需要“扩展”关键字，因为需要在 gql 标记内声明属性，并且在整个项目中多次声明查询。