使用 javax.sound.midi 接收 midi 输入
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【中文标题】使用 javax.sound.midi 接收 midi 输入【英文标题】:Receive midi input with javax.sound.midi 【发布时间】:2018-06-24 20:00:34 【问题描述】:我想要一个程序,当它得到一个 midi 输入时,它可以做一些事情。
例如,当我单击控制器上的按钮 1 时,它应该打印“You clicked btn 1”,当我单击按钮 2 时,它应该打印“You clicked btn 2”。
我尝试使用 javax.sound.midi 库,但论坛或 youtube 上的所有示例都不起作用。
这对我来说最有效。它打印了我 PC 上的所有 Midi 设备,但没有收到任何东西。有人可以帮忙吗?
package de.snke.dev;
import javax.sound.midi.*;;
public class Main extends Object implements Receiver
static MidiClass myMidi;
public static void main(String[] args) throws Exception
MidiDevice.Info[] info =
MidiSystem.getMidiDeviceInfo();
for (int i=0; i < info.length; i++)
System.out.println(i + ") " + info[i]);
System.out.println("Name: " + info[i].getName());
System.out.println("Description: " +
info[i].getDescription());
MidiDevice device =
MidiSystem.getMidiDevice(info[i]);
System.out.println("Device: " + device);
public void send(MidiMessage msg,
long time)
System.out.println("Received message " + msg);
public void close()
System.out.println("Closing");
编辑:现在我有
Sequencer seq;
Transmitter seqTrans;
Synthesizer synth;
Receiver synthRcvr;
try
seq = MidiSystem.getSequencer();
seqTrans = seq.getTransmitter();
synth = MidiSystem.getSynthesizer();
synthRcvr = synth.getReceiver();
seqTrans.setReceiver(synthRcvr);
catch (MidiUnavailableException e)
// handle or throw exception
我现在是否已连接到我的 APC Mini?对不起,我是初学者... 如果是,我现在如何读取 MIDI 输入?如果否,我需要改变什么?
【问题讨论】:
阅读documentation。 谢谢。我以前已经这样做了。我现在在线程中添加了一个新问题。 1.您的main
运行多长时间? 2.你希望哪个对象接收消息?
【参考方案1】:
解决办法是:
package de.snke.dev;
import javax.sound.midi.*;
import java.util.ArrayList;
import java.util.List;
import java.io.*;
public class Main
public void Main()
MidiDevice device;
MidiDevice.Info[] infos = MidiSystem.getMidiDeviceInfo();
for (int i = 0; i < infos.length; i++)
try
device = MidiSystem.getMidiDevice(infos[i]);
//does the device have any transmitters?
//if it does, add it to the device list
System.out.println(infos[i]);
//get all transmitters
List<Transmitter> transmitters = device.getTransmitters();
//and for each transmitter
for(int j = 0; j<transmitters.size();j++)
//create a new receiver
transmitters.get(j).setReceiver(
//using my own MidiInputReceiver
new MidiInputReceiver(device.getDeviceInfo().toString())
);
Transmitter trans = device.getTransmitter();
trans.setReceiver(new MidiInputReceiver(device.getDeviceInfo().toString()));
//open each device
device.open();
//if code gets this far without throwing an exception
//print a success message
System.out.println(device.getDeviceInfo()+" Was Opened");
catch (MidiUnavailableException e)
//tried to write my own class. I thought the send method handles an MidiEvents sent to it
public class MidiInputReceiver implements Receiver
public String name;
public MidiInputReceiver(String name)
this.name = name;
public void send(MidiMessage msg, long timeStamp)
byte[] aMsg = msg.getMessage();
// take the MidiMessage msg and store it in a byte array
// msg.getLength() returns the length of the message in bytes
for(int i=0;i<msg.getLength();i++)
System.out.println(aMsg[i]);
// aMsg[0] is something, velocity maybe? Not 100% sure.
// aMsg[1] is the note value as an int. This is the important one.
// aMsg[2] is pressed or not (0/100), it sends 100 when they key goes down,
// and 0 when the key is back up again. With a better keyboard it could maybe
// send continuous values between then for how quickly it's pressed?
// I'm only using VMPK for testing on the go, so it's either
// clicked or not.
System.out.println();
public void close()
它是 2 线程解决方案结合起来打开所有 MIDI 设备并打印它们的速度、音符值和状态(点击或未点击)
别忘了!
你必须打电话
Main main = new Main();
main.Main();
在一个单独的类中启动 Main 类中的方法 Main。
【讨论】:
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