Array.every 函数并未在 Object 的所有元素上运行

Posted 2023-03-07

【中文标题】Array.every 函数并未在 Object 的所有元素上运行

【英文标题】：Array.every function isn't running on all elements of Object

【发布时间】：2019-08-09 11:12:59

【问题描述】：

我正在尝试使用以下代码在 temp1 内部搜索是否有任何 值 具有字符串 "processado"

let temp1 = [
    "id":7089,
    "value":"R$ 50,00",
    "name":"Daiany Nascimento",
    "date":"18/03/2019",
    "type":"Cobrança",
    "status":
        "status":"Paga",
        "icon":"paid"
    ,
    "credit_release_date":"Não Processado",
    "credit_release_description":"— — — —"
]

let b = []

temp1.forEach((a,index_a) =>  
Object.values(a).every((value,index,array) => 
    let expression = new RegExp("processado", "i") //expression to search
    if (typeof value == "object") 
      Object.values(value).every(valueOfObject =>     
        if (expression.test(valueOfObject)) 
          b.push(temp1[index_a])
          return false;
         else 
          return true
        
      )
    
    else if (expression.test(value)) 
      b.push(temp1[index_a])
      return false
    
      else 
      return true
    
  )
)

但是，数组 b 仍然为空。如果我尝试搜索字符串 "Cobrança"，则 array b 会被填充，这是应该的。我认为，如果我尝试搜索存储在 keys status key 之后的 values，就会出现问题.

【问题讨论】：

只是一个建议：对于您的用例，Arrays 'find' 方法似乎是适合使用的方法。有什么理由在这里使用“每个”吗？

【参考方案1】：

你需要在if (typeof value == "object")里面return Object.values(value).every(valueOfObject....

let temp1 = ["id":7089,"value":"R$ 50,00","name":"Daiany Nascimento","date":"18/03/2019","type":"Cobrança","status":"status":"Paga","icon":"paid","credit_release_date":"Não Processado","credit_release_description":"— — — —"]

let b = []

temp1.forEach((a,index_a) =>  
Object.values(a).every((value,index,array) => 
    let expression = new RegExp("processado", "i") //expression to search
    if (typeof value == "object") 
      return Object.values(value).every(valueOfObject =>     
        if (expression.test(valueOfObject)) 
          b.push(temp1[index_a])
          return false;
         else 
          return true
        
      )
    
      else if (expression.test(value)) 
      b.push(temp1[index_a])
      return false
      
      else 
      return true
      
  )
)
console.log(b)

一种更简单、更简洁的方法是使用递归以及filter() 和some()。 every() 在这里对我没有任何意义

let temp1 = ["id":7089,"value":"R$ 50,00","name":"Daiany Nascimento","date":"18/03/2019","type":"Cobrança","status":"status":"Paga","icon":"paid","credit_release_date":"Não Processado","credit_release_description":"— — — —"]

function check(obj,regex)
  return Object.values(obj).some(x =>
      let y;
      if(typeof x === "object") y = check(x,regex);
      return y || regex.test(x);
   );


let b = temp1.filter(x => check(x,/Processado/i))
console.log(b)

【参考方案2】：

为什么不考虑递归来检查任何值是否是对象？我认为它可以缩短代码并更直接。

另外，对我来说Array.prototype.some 在这种情况下比Array.prototype.every 更有意义（除非我遗漏了什么）：

const temp1 = [
  "id": 7089,
  "value": "R$ 50,00",
  "name": "Daiany Nascimento",
  "date": "18/03/2019",
  "type": "Cobrança",
  "status": 
    "status":"Paga",
    "icon":"paid"
  ,
  "credit_release_date": "Não Processado",
  "credit_release_description": "— — — —"
];

const b = [];

const expression = new RegExp('processado', 'i');

const hasExpr = obj => Object.values(obj).some((value, i) => 
  if (typeof value === 'object')
    return hasExpr(value);
  return expression.test(value);
);

temp1.forEach(item => 
  if (hasExpr(item))
    b.push(item);
);

console.log(b);