Haversine 公式 - 结果太高
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【中文标题】Haversine 公式 - 结果太高【英文标题】:Haversine Formula - Results Too High 【发布时间】:2014-08-20 16:41:04 【问题描述】:我正在使用Haversine 公式来计算地球上两点之间的距离。我有以下代码:
var app = angular.module('app', []);
app.controller('firstCtrl', function($scope, $timeout)
var myLat, myLon, locLat, locLon;
navigator.geolocation.watchPosition(GetLocation)
$scope.ASiteLocs = [
"name": "IL5077 BRUSSELS",
"styleUrl": "#waypoint",
"Point":
"coordinates": "-90.58543899999999,38.955472,0"
,
"name": "IL5076 KAMPSVILLE",
"styleUrl": "#waypoint",
"Point":
"coordinates": "-90.661923,39.29403,0"
,
"name": "IL5146 CARROLLTON",
"styleUrl": "#waypoint",
"Point":
"coordinates": "-90.39965700000001,39.309142,0"
,
"name": "IL5153 GREENFIELD",
"styleUrl": "#waypoint",
"Point":
"coordinates": "-90.208747,39.364077,0"
];
$scope.SSiteLocs = [];
$scope.SiteLocs = $scope.SSiteLocs.concat($scope.ASiteLocs);
repoSortOrder = "site.name";
function GetLocation(location, myLat, myLon)
myLat = location.coords.latitude;
myLon = location.coords.longitude;
document.getElementById("lat").innerhtml = myLat;
document.getElementById("lon").innerHTML = myLon;
$timeout(function()
calculate();
);
$scope.getCoordDistance = function(myLat, myLon, locLat, locLon)
var lat1 = locLat; //41.887055
var lon1 = locLon; //-88.469233
var lat2 = myLat; //41.888668
var lon2 = myLon; //-87.640371
var R = 3959;
var x1 = lat2 - lat1;
var dLat = x1 * Math.PI / 180;
var x2 = lon2 - lon1;
var dLon = x2 * Math.PI / 180;
a = Math.sin(dLat / 2) * Math.sin(dLat / 2) +
Math.cos(lat1 * Math.PI / 180) * Math.cos(lat2 * Math.PI / 180) *
Math.sin(dLon / 2) * Math.sin(dLon / 2);
c = 2 * Math.atan2(Math.sqrt(a), Math.sqrt(1 - a));
var d = R * c;
return d;
;
angular.forEach($scope.SSiteLocs, function(object)
object.carrier = 'Sprint';
);
angular.forEach($scope.ASiteLocs, function(object)
object.carrier = 'AT&T';
);
var i = 0;
locX = 1;
var calculate = function()
angular.forEach($scope.SiteLocs, function(location)
var clength = location.Point.coordinates.length;
if (location.Point.coordinates.substring(clength - 2, clength) === ",0")
location.Point.coordinates = location.Point.coordinates.substring(0, clength - 2).split(",");
Lat = location.Point.coordinates[0];
Lon = location.Point.coordinates[1];
Com = ",";
location.Point.coordinates = Lon.concat(Com, Lat);
myLat = Number(document.getElementById("lat").innerHTML)
myLon = Number(document.getElementById("lon").innerHTML)
locLat = Lat;
locLon = Lon;
d = $scope.getCoordDistance(myLat, myLon, locLat, locLon);
location.distance = d.toFixed(1);
if(i < 15)
console.log("********LOCATON " + locX + "***********")
console.log("myCoords: " + myLat + "," + myLon);
console.log("locCoords: " + locLat + "," + locLon);
console.log("d: " + d);
console.log("***************************")
i++;
locX++;
);
;
);
公式的结果最高可达 9-10,000 左右,而它们不应该接近那么高。如果我使用注释掉的坐标,它会正确返回(42.6 英里) 由于测试坐标有效,我知道这不是数学问题。有人知道是什么导致公式无法正常工作吗?编辑 Here 是完整项目的一个笨蛋。如果这有帮助。 EDIT2 我发现了一些奇怪的东西,不同浏览器的结果不同,所以,chrome显示一组数字,IE显示另一组,等等。
【问题讨论】:
【参考方案1】:您的点坐标是经纬度
BRUSSELS",
"
"Point":
"coordinates": "-90.58543899999999,38.955472
在您的代码中
Lat = location.Point.coordinates[0];
Lon = location.Point.coordinates[1];
在您的对象中更改它们(首选)请参阅 Google latlng class
"Point":
"coordinates": "38.955472,-90.58543899999999
或
Lat = location.Point.coordinates[1];
Lon = location.Point.coordinates[0];
您的设置距离约为 9000 英里,坐标转置距离约为 200
【讨论】:
【参考方案2】:除了 kirinthos 在他的回复中所说的之外,您还可以通过将结果与 Google 地图进行比较来轻松测试这一点。我的应用程序中有一个功能可以做到这一点。 point1 和 point2 参数是简单的 Latlng 对象。我想要以公里为单位的结果,所以我除以 1000。
function calculateDistanceBetweenTwoPoints(point1, point2)
return (google.maps.geometry.spherical.computeDistanceBetween(point1, point2) / 1000).toFixed(2);
您的 HTML 页面中需要以下内容:
<script src="https://maps.googleapis.com/maps/api/js?v=3.exp&libraries=geometry,places"></script>
【讨论】:
我认为脚本标签中有错字。【参考方案3】:在这里,我不完全确定,没有对其进行测试,但看起来 GetLocation 函数通过将变量 myLat 和 myLon 声明为函数参数来覆盖它们的闭包范围,因此您正在分配位置的值。 coords.latitude 到函数作用域 myLat 变量中,而不是在代码块开头声明的 myLat。
抛出一个console.log(myLat, myLon);进入 getCoordDistance 的开头并检查它们的值。我敢打赌,它们不是你所期望的。
编辑:实际上可能是缺少分号之类的。这是您的代码的一个小 sn-p,经过重新校准,可以在 jsbin.com 等隔离环境中运行。它似乎工作正常。您缺少 4 个分号,因此除非此分配失败,否则它应该可以工作: myLon = Number(document.getElementById("lon").innerHTML)
有人抱怨没有定义变量“i”和“locX”
var myLat, myLon;
var ASiteLocs = [
"name": "IL5077 BRUSSELS",
"styleUrl": "#waypoint",
"Point":
"coordinates": "-90.58543899999999,38.955472,0"
,
"name": "IL5076 KAMPSVILLE",
"styleUrl": "#waypoint",
"Point":
"coordinates": "-90.661923,39.29403,0"
,
"name": "IL5146 CARROLLTON",
"styleUrl": "#waypoint",
"Point":
"coordinates": "-90.39965700000001,39.309142,0"
,
"name": "IL5153 GREENFIELD",
"styleUrl": "#waypoint",
"Point":
"coordinates": "-90.208747,39.364077,0"
];
var SSiteLocs = [];
var SiteLocs = SSiteLocs.concat(ASiteLocs);
function GetLocation(location, myLat, myLon)
myLat = location.coords.latitude;
myLon = location.coords.longitude;
document.getElementById("lat").innerHTML = myLat;
document.getElementById("lon").innerHTML = myLon;
function getCoordDistance(myLat, myLon, locLat, locLon)
var lat1 = locLat; //41.887055
var lon1 = locLon; //-88.469233
var lat2 = myLat; //41.888668
var lon2 = myLon; //-87.640371
var R = 3959;
var x1 = lat2 - lat1;
var dLat = x1 * Math.PI / 180;
var x2 = lon2 - lon1;
var dLon = x2 * Math.PI / 180;
a = Math.sin(dLat / 2) * Math.sin(dLat / 2) +
Math.cos(lat1 * Math.PI / 180) * Math.cos(lat2 * Math.PI / 180) *
Math.sin(dLon / 2) * Math.sin(dLon / 2);
c = 2 * Math.atan2(Math.sqrt(a), Math.sqrt(1 - a));
var d = R * c;
return d;
;
function calculate()
SiteLocs.forEach(function(location)
var clength = location.Point.coordinates.length;
if (location.Point.coordinates.substring(clength - 2, clength) === ",0")
location.Point.coordinates = location.Point.coordinates.substring(0, clength - 2).split(",");
Lat = location.Point.coordinates[0];
Lon = location.Point.coordinates[1];
Com = ",";
location.Point.coordinates = Lon.concat(Com, Lat);
myLat = -90.208747;
myLon = 39.364077;
locLat = Lat;
locLon = Lon;
d = getCoordDistance(myLat, myLon, locLat, locLon);
location.distance = d.toFixed(1);
//console.log("********LOCATON " + locX + "***********");
console.log("myCoords: " + myLat + "," + myLon);
console.log("locCoords: " + locLat + "," + locLon);
console.log("d: " + d);
console.log("***************************");
);
;
【讨论】:
myLat
和 myLon
是 getCoordDistance
的预期值,所以我认为不是这样。不过谢谢!
你能给我提供调用 getCoordDistance 的四个值吗?
myLat
和 myLon
是来自 navigate.geolocation.eatchPosition
和 locLat
的坐标,locLon
是来自 coordinates
在 $scope.ASiteLocs
中的坐标
我将你的代码导入到测试环境并编辑了,有一些分号问题,但似乎可以工作
距离表中的一些结果是什么?以上是关于Haversine 公式 - 结果太高的主要内容,如果未能解决你的问题,请参考以下文章
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