将多个数组的每一项平均到一个数组中

Posted 2023-03-05

【中文标题】将多个数组的每一项平均到一个数组中

【英文标题】：Getting average of every item of multiple arrays into one array

【发布时间】：2018-02-08 17:37:54

【问题描述】：

嗯，我的大脑正在融化......我正在努力完成以下工作：

我知道有多少个数组以及每个数组有多少个元素。 这些数字是动态的，但假设有：3 个数组，每个数组有 18 个元素。

例子：

["106","142","112","77","115","127","87","127","156","118","91","93","107","151","110","79","40","186"]

["117","139","127","108","172","113","79","128","121","104","105","117","139","109","137","109","82","137"]

["111","85","110","112","108","109","107","89","104","108","123","93","125","174","129","113","162","159"]

现在我想获得所有三个数组的元素 1 的平均值，以及所有三个数组的元素 2 的平均值，依此类推。

最终结果应该是一个具有所有 18 个元素的平均值的数组。

类似：

var result_array = [];
for (i = 0; i < 3; i++)   
  result_array.push(arrayone[i] + arraytwo[i] + arraythree[i]) / 3

如果 3 是固定的，这将起作用，但数组的数量是动态的。

希望这是有道理的......

【问题讨论】：

数组的大小总是一样吗？

是的，每个循环都有相同的大小。但是数组的数量每次都不一样..

实际上数组来自逗号分隔项的数组。使用拆分使它们成为数组。在 for 循环中...

【参考方案1】：

这里的答案是使用循环。我们将您的数组称为 arr1、arr2 和 arr3。

var averages = [];

for(i = 0; i < arr1.length; i++) 
    var a = arr1[i];
    var b = arr2[i];
    var c = arr3[i];
    var avg = (a + b + c) / 3;
    averages.push(avg);

对于此循环的每次迭代，它将： - 将每个数组的下一位分配给一个变量（从索引 0 开始） - 求三个数字的平均值 -将计算结果添加到averages数组中

【讨论】：

这个问题实际上要求可变数量的数组，这是 OP 无法做到的。问题中已经几乎完全复制了此代码。

【参考方案2】：

用 Java 编写了这个解决方案，但您可以获得逻辑方面的帮助。希望对您有所帮助。

ArrayList<Integer> averageArrayList = new ArrayList<>();
int arrayListLength = arrayList1.length(); //assuming previous arraylists have same size.


   for(int i=0; i<arrayListLength; i++)
        int averageValue = (arrayList1.get(i) + arrayList2.get(i) + arrayList3.get(i)) / 3;
        //adds average value to current index.
        averageArrayList.add(i, averageValue);
    
//averageArrayList is ready with your values..

【参考方案3】：

var arrays = [
    [106,142,112,77,115,127,87,127,156,118,91,93,107,151,110,79,40,186],
    [117,139,127,108,172,113,79,128,121,104,105,117,139,109,137,109,82,137],
    [111,85,110,112,108,109,107,89,104,108,123,93,125,174,129,113,162,159],
    [104,153,110,112,108,109,107,89,104,108,123,93,125,174,129,113,162,159]
    /* Can be any amount of arrays */
    ],
    result = [];

//Rounding to nearest whole number.
for(var i = 0; i < arrays[0].length; i++)
  var num = 0;
  //still assuming all arrays have the same amount of numbers
  for(var i2 = 0; i2 < arrays.length; i2++) 
    num += arrays[i2][i];
  
  result.push(Math.round(num / arrays.length));


alert(result);

【参考方案4】：

此函数将获取任意数量的数组并计算出它们的平均值。它使用 + 运算符自动将字符串转换为数字。它是动态的，因为它不关心数组的长度或数组的数量，只要它们的长度都相等。由于我们可以假设它们都是相同的长度（基于问题），它迭代第一个数组的长度。它没有圆，因为没有要求。

function average_of_arrays(...arrays) 
  let result = [];
  for(let array_index in arrays[0]) 
    let total = 0;
    for (let arr of arrays) 
      total += +arr[array_index]
    
    result.push(total / arrays.length);
  
  return result;

let arr1 = ["106", "142", "112", "77", "115", "127", "87", "127", "156", "118", "91", "93", "107", "151", "110", "79", "40", "186"];

let arr2 = ["117", "139", "127", "108", "172", "113", "79", "128", "121", "104", "105", "117", "139", "109", "137", "109", "82", "137"];

let arr3 = ["111", "85", "110", "112", "108", "109", "107", "89", "104", "108", "123", "93", "125", "174", "129", "113", "162", "159"];

function average_of_arrays(...arrays) 
  let result = [];
  for(let array_index in arrays[0]) 
    let total = 0;
    for (let arr of arrays) 
      total += +arr[array_index]
    
    result.push(total / arrays.length);
  
  return result;



console.log(average_of_arrays(arr1, arr2, arr3));

【参考方案5】：

var result = getAvg( [ 1, 2, 3 ], [ 2, 3, 4 ] )

console.log( result ) // [ 1.5, 2.5, 3.5 ]

function getAvg() 

  var a = arguments
  var nar = a.length
  var nel = a[ 0 ].length
  var el, ar, avg, avgs = []

  for( el = 0; el < nel; ++el ) 
    avg = 0
    for( ar = 0; ar < nar; ++ar ) avg += a[ ar ][ el ]
    avgs[ el ] = avg / nar
  

  return avgs

【参考方案6】：

您确实使用 underscore.js 标记了这个问题，因此您可以使用 _.zip 方法。这会将数组中的所有第一个元素放在一起，依此类推。然后，您可以平均每个数组。

见CodePen。

var arr1 = ["106","142","112","77","115","127","87","127","156","118","91","93","107","151","110","79","40","186"]
var arr2 = ["117","139","127","108","172","113","79","128","121","104","105","117","139","109","137","109","82","137"]
var arr3 = ["111","85","110","112","108","109","107","89","104","108","123","93","125","174","129","113","162","159"]
// ... as many more arrays as you want

var avgEmAll = function (arrays) 
  // zip with array of arrays https://***.com/a/10394791/327074
  return _.zip.apply(null, arrays).map(avg)


// average an array https://***.com/a/10624256/327074
var avg = function (x) 
  return x.reduce(function (y, z) return Number(y) + Number(z)) / x.length

console.log(avgEmAll([arr1, arr2, arr3]))

使用 ES6 箭头函数 (CodePen)：

const avgEmAll = arrays => _.zip.apply(null, arrays).map(avg)
const sum = (y, z) => Number(y) + Number(z)
const avg = x => x.reduce(sum) / x.length