UITapGestureRecognizer 不工作

Posted 2023-02-27

【中文标题】UITapGestureRecognizer 不工作

【英文标题】：UITapGestureRecogniser not working

【发布时间】：2016-10-11 10:15:52

【问题描述】：

我编写了与 Apple 文档中相同的代码，但是当我单击照片时，照片库没有出现。点击手势识别器可能无法正常工作。

import UIKit

class ViewController: UIViewController, UITextFieldDelegate,UIImagePickerControllerDelegate,UINavigationControllerDelegate 

    override func viewDidLoad() 
        super.viewDidLoad()
        nameTextField.delegate = self
    

    // MARK: Properties
    @IBOutlet weak var nameTextField: UITextField!
    @IBOutlet weak var nameLabel: UILabel!
    @IBOutlet weak var photoImageView: UIImageView!

    //MARK: Actions
    @IBAction func setDefaultLabelText(sender: UIButton) 
        nameLabel.text = "default"
    
    @IBAction func selectImageFromPhotoLibrary(sender: UITapGestureRecognizer) 

            // Hide the keyboard.
            nameTextField.resignFirstResponder()

            // UIImagePickerController is a view controller that lets a user pick media from their photo library.
            let imagePickerController = UIImagePickerController()

            // Only allow photos to be picked, not taken.
            imagePickerController.sourceType = UIImagePickerControllerSourceType.PhotoLibrary

            // Make sure ViewController is notified when the user picks an image.
            imagePickerController.delegate = self

            presentViewController(imagePickerController, animated: true, completion: nil)
    

    func imagePickerControllerDidCancel(picker: UIImagePickerController) 
        // Dismiss the picker if the user canceled.
        dismissViewControllerAnimated(true, completion: nil)
    
    func imagePickerController(picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [String : AnyObject]) 
        // The info dictionary contains multiple representations of the image, and this uses the original.
        let selectedImage = info[UIImagePickerControllerOriginalImage] as! UIImage

        // Set photoImageView to display the selected image.
        photoImageView.image = selectedImage

        // Dismiss the picker.
        dismissViewControllerAnimated(true, completion: nil)
    

    //MARK: UITextFieldDelegate
    func textFieldShouldReturn(textField: UITextField) -> Bool 
        textField.resignFirstResponder()
        return true
    

    func textFieldDidEndEditing(textField: UITextField) 
        nameLabel.text = textField.text
    

【问题讨论】：

你在哪里添加了手势，你能显示那个代码

请尝试想出一个真正描述问题的问题标题。避免使用“紧急”之类的词，它们在这里不太受欢迎。

好吧抱歉这是我第一次

【参考方案1】：

检查一次你是否为你的Imageview启用了userInteraction属性，默认是false，我们需要手动启用，喜欢

photoImageView.userInteractionEnabled = true

例如

override func viewDidLoad()

    super.viewDidLoad()

    let tapGestureRecognizer = UITapGestureRecognizer(target:self, action:Selector("imageTapped:"))
    photoImageView.userInteractionEnabled = true
    photoImageView.addGestureRecognizer(tapGestureRecognizer)

调用你的方法

func imageTapped(img: AnyObject)

    // Your action 

【讨论】：

错误信息“预期声明

谢谢它的工作我这样做了：-

覆盖 func viewDidLoad() super.viewDidLoad() photoImageView.userInteractionEnabled = true

@ShalinGadhavi - 很高兴听到

这也解决了我的教程问题，但我仍然很困惑为什么在调用 viewDidLoad() 时 userInteractionEnabled 的默认值为 false。我已经检查以启用故事板编辑器中图像视图的“启用用户交互”字段，并且运行时的值仍然是错误的......结果如果父视图（在这种情况下为堆叠视图）具有“用户已启用交互”设置为 false，它也适用于其子级：***.com/questions/5887305/…