Django 按主页中最高点赞数排序

Posted 2023-02-26

【中文标题】Django 按主页中最高点赞数排序

【英文标题】：Django order by highest number of likes in homepage

【发布时间】：2021-01-28 19:39:21

【问题描述】：

我正在尝试创建一个页面，人们可以在主页上看到评分最高的文章，但我不知道如何使用喜欢来做到这一点。

我的帖子模型

class Post(models.Model):
    title = models.CharField(max_length=225)
    post_image = models.ImageField(null=True, blank=True,  upload_to="images/")
    author = models.ForeignKey(User, on_delete=models.CASCADE)
    body = models.TextField()
    post_date = models.DateField(auto_now_add=True)
    likes = models.ManyToManyField(User, related_name='blog_posts')

    def total_likes(self):
        return self.likes.count()

    def __str__(self):
        return self.title + ' | '  + str(self.author)

    def get_absolute_url(self):
        return reverse('post-detail', args=(str(self.id)),)

我的意见.py

def LikeView(request, pk):
    post = get_object_or_404(Post, id=request.POST.get('post_id'))
    liked = False
    if post.likes.filter(id=request.user.id).exists():
        post.likes.remove(request.user)
        liked = False
    else:
        post.likes.add(request.user)
        liked = True

    return HttpResponseRedirect(reverse('post-detail', args=[str(pk)]))

class HomeView(ListView):
    model = Post
    template_name = 'home.html'
   


class PostDetail(DetailView):
    model = Post
    template_name = 'post_detail.html'

    def get_context_data(self, *args, **kwargs):
        context = super(PostDetail, self).get_context_data()
        current_post = get_object_or_404(Post, id=self.kwargs['pk'])
        total_likes = current_post.total_likes()

        liked = False
        if current_post.likes.filter(id=self.request.user.id).exists():
            liked = True 


        context['total_likes'] = total_likes
        context['liked'] = liked 
        return context                    
    

提前致谢！ ..................................................... ..................................................

【问题讨论】：

这能回答你的问题吗？ Django order by highest number of likes

【参考方案1】：

As anoop quoted 你的HomeView 将是：

class HomeView(ListView):
    queryset = Post.objects.annotate(like_count=Count('likes')).order_by('-like_count')
    template_name = 'home.html'
    context_object_name = 'post_list' # Providing a useful context_object_name is always a good idea

在您的模板中：

% for post in post_list %    

【讨论】：

我尝试了代码，但似乎没有任何反应。它没有显示错误，但什么也不做

尝试从 shell 执行查询。它会起作用的。您在 db 中有 post 对象吗？

对不起，我是新人。如何从 shell 执行查询？

python manage.py shell 。在运行 python manage.py runserver 的路径中运行此命令。执行 > from .models import Post (appname/projectnname.models) > posts = Post.objects.annotate(like_count=Count('likes')).order_by('-like_count') > 帖子。您可以看到帖子查询集，无论它是充满帖子对象还是空查询集