java中的重复分隔符与数组的损坏消息
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【中文标题】java中的重复分隔符与数组的损坏消息【英文标题】:Recurring Delimiter in java with broken message to an array 【发布时间】:2017-09-10 07:58:51 【问题描述】:我有一个字符串:
String received = "28,gZrate:-1.48,
gXrate:9.10,gYrate:-0.69,gZrate:-1.50,
gXrate:9.22,gYrate:0.54,gZrate:-1.67,
gXrate:9.20,gYrate:-2.40,gZrate:-1.65,gXrate:9.02" ;
我需要这个字符串在这样的数组中:
["gXrate:9.10,gYrate:-0.69,gZrate:-1.50","gXrate:9.22,gYrate:0.54,gZrate:-1.67","gXrate:9.20,gYrate:-2.40,gZrate:-1.65"]
忽略接收到的字符串开头和结尾的断线部分 即
28,gZrate:-1.48
gXrate:9.02 ;
还要注意有时字符串可能不会被破坏。
【问题讨论】:
【参考方案1】:String received = "28,gZrate:-1.48,gXrate:9.10,gYrate:-0.69,gZrate:-1.50,";
received += "gXrate:9.22,gYrate:0.54,gZrate:-1.67,";
received += "gXrate:9.20,gYrate:-2.40,gZrate:-1.65,gXrate:9.02";
String pattern = "\\(.*?)\\,?";
StringBuilder sb = new StringBuilder("[");
boolean first = true;
Pattern r = Pattern.compile(pattern);
Matcher m = r.matcher(received);
while (m.find())
if (!first)
sb.append(",");
first = false;
sb.append("\"" + m.group(1) + "\"");
sb.append("]");
System.out.println(sb);
输出:
["gXrate:9.10,gYrate:-0.69,gZrate:-1.50","gXrate:9.22,gYrate:0.54,gZrate:-1.67","gXrate:9.20,gYrate:-2.40,gZrate:-1.65"]
这是一个演示,它表明上述代码适用于破碎和平衡的情况:
Rextester
【讨论】:
【参考方案2】:你可以使用正则表达式:
import java.util.regex.*;
import java.util.Arrays;
import java.util.ArrayList;
public class Main
public static void main (String[] args)
ArrayList<String> nonBrokenStrings = new ArrayList<String>();
String received = "28,gZrate:-1.48,gXrate:9.10,gYrate:-0.69,gZrate:-1.50, gXrate:9.22,gYrate:0.54,gZrate:-1.67, gXrate:9.20,gYrate:-2.40,gZrate:-1.65,gXrate:9.02";
Matcher m = Pattern.compile("\\([^]+)\\").matcher(received);
while(m.find())
nonBrokenStrings.add(m.group(1));
String[] nonBrokenStringsArr = nonBrokenStrings.toArray(new String[nonBrokenStrings.size()]);
System.out.print(Arrays.toString(nonBrokenStringsArr));
输出:
[gXrate:9.10,gYrate:-0.69,gZrate:-1.50, gXrate:9.22,gYrate:0.54,gZrate:-1.67, gXrate:9.20,gYrate:-2.40,gZrate:-1.65]
试试here!
【讨论】:
【参考方案3】:public static String formatToArrayStr(String input)
String regex="\\([^]+)\\";
Matcher m=Pattern.compile(regex).matcher(input);
StringBuilder result=new StringBuilder().append("[");
while(m.find())
result.append("\"").append(m.group(1)).append("\"").append(",");
result=(result.lastIndexOf(",")>=0?result.deleteCharAt(result.length()-1):result).append("]");
return result.toString();
也可以这样写:
public static String formatToArrayStr(String input)
Matcher m=Pattern.compile("\\([^]+)\\").matcher(input);
List<String> result=new ArrayList<String>();
while(m.find())
result.add("\""+m.group(1)+"\"");
return result.toString();
输出
["gXrate:9.10,gYrate:-0.69,gZrate:-1.50","gXrate:9.22,gYrate:0.54,gZrate:-1.67","gXrate:9.20,gYrate:-2.40,gZrate:-1.65"]
【讨论】:
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