如何将 JSON 字符串转换为对象的 Arraylist

Posted 2023-02-26

【中文标题】如何将 JSON 字符串转换为对象的 Arraylist

【英文标题】：How to convert JSON String into Arraylist of Objects

【发布时间】：2018-10-26 12:09:49

【问题描述】：

我有 JSON 字符串，从 HTTP 请求接收到：

     [  
         
      "id":15,
      "title":"1",
      "description":"desc",
      "user_id":152
     ,
      
      "id":18,
      "title":"2",
      "description":"desc",
      "user_id":152
    ,
      
      "id":19,
      "title":"tab3",
      "description":"zadanka",
      "user_id":152
   
]

如何将其转换为对象的 ArrayList？

【参考方案1】：

你需要声明一个pojo

class Data
  String id;
  String title;
  String description;
  String userId;
  //Generate setter an getter

对 json 的迭代如下：

JSONArray jsonArr = new JSONArray("[your JSON Stirng]");
    List<Data> dataList = new ArrayList<Data>();
    for (int i = 0; i < jsonArr.length(); i++) 
        JSONObject jsonObj = jsonArr.getJSONObject(i);
        Data data = new Data();
        data.setId(jsonObj.getString("id"));
        data.setTitle(jsonObj.getString("title"));
        data.setDescription(jsonObj.getString("description"));
        data.setUserId(jsonObj.getString("user_id"));
        dataList.add(data);
    

你还需要 json jar。可以从here下载

【讨论】：

谢谢。这正是我所需要的。

不要从海报提供的链接下载，而是使用 Maven 和合法来源：mvnrepository.com/artifact/org.json/json

【参考方案2】：

使用 Gson

Gson gson = new Gson();
        ArrayList<Object> listFromGson = gson.fromJson("json string",
               new TypeToken<ArrayList<Object>>() .getType());

使用杰克逊

    ObjectMapper mapper = new ObjectMapper();
    ArrayList<Object> listFromJackson = mapper.readValue("json string",
           new TypeReference<ArrayList<Object>>());

如果你可以将 pojo 定义为

public class Example 

    private Integer id;
    private String title;
    private String description;
    private Integer userId;
    // setters / getters

然后

ArrayList<Example> listFromGson = gson.fromJson("json string",
               new TypeToken<ArrayList<Example>>() .getType());

ArrayList<Example> listFromJackson = mapper.readValue("json string",
               new TypeReference<ArrayList<Example>>());

此外，您应该更喜欢使用List 而不是ArrayList。

【参考方案3】：

如果您使用的是 RestApi，则将注释 @RequestBody 与您的 pojo 类一起使用。

@RequestMapping(value="/your api name", method=RequestMethod.POST)
public ResponseData createUser(@RequestBody MyPojo myPojo)
System.out.println("Creating User "+myPojo.toString());

//Here you will able to access your request data from myPojo object

制作你的 pojo 类：

public class MyPojo

private Data[] data;

public Data[] getData ()

    return data;


public void setData (Data[] data)

    this.data = data;


@Override
public String toString()

    return "ClassPojo [data = "+data+"]";



public class Data

private String id;

private String title;

private String description;

private String user_id;

public String getId ()

    return id;


public void setId (String id)

    this.id = id;


public String getTitle ()

    return title;


public void setTitle (String title)

    this.title = title;


public String getDescription ()

    return description;


public void setDescription (String description)

    this.description = description;


public String getUser_id ()

    return user_id;


public void setUser_id (String user_id)

    this.user_id = user_id;


@Override
public String toString()

    return "ClassPojo [id = "+id+", title = "+title+", description = "+description+", user_id = "+user_id+"]";

【参考方案4】：

除了@Sudhir，我推荐使用Gson

Gson gson = new GsonBuilder().create();
 Data p = gson.fromJson(jsonString, Data.class);
// Or to array.
 Data[] data = gson.fromJson(jsonString, Data[].class);