继续后如何返回循环的特定部分？

Posted 2023-02-25

【中文标题】继续后如何返回循环的特定部分？

【英文标题】：How to return to a particular part of a loop after continue?

【发布时间】：2016-02-21 02:25:21

【问题描述】：

我正在学习使用类。我已经在我定义的方法之一 setBirthday 中构建了异常。它确保输入适合于真正的生日输出。这部分代码没有按我的意愿工作。

    def setBirthday(you):
    while True:
        #get numeric birth month
        try:
            m = int(raw_input("What is your birth month?"))
        except ValueError:
            print "Enter an integer, please try again."
            continue
        if m <= 0:
            print "Enter a number between 1-12, please try again."
            continue
        elif m >= 13:
            print "Enter a number between 1-12, please try again."
            continue
      #get birth date
        try:
            d = int(raw_input("What day were you born that month?"))
        except ValueError:
            print "Enter an integer, please try again."
            continue        
        if d <= 0:
            print "Enter a number between 1-31, please try again."
            continue
        elif d >= 32:
            print "Enter a number between 1-31, please try again."
            continue
        #get birth year
        try:
            y = int(raw_input("What year were you born?"))
        except ValueError:
            print "Enter an integer, please try again."
            continue        
        if y <= 0:
            print "Enter a number greater than zero, please try again."
            continue
        else:
            break
    you.bday = datetime(y, m, d)
    age = str(m) + "/" + str(d) + "/" + str(y)
    print "Your birthday is " + (age)

当它现在运行时，如果有人在月份 (d) 或出生年份 (y) 输入了不需要的输入，“继续”将再次重新启动整个循环：询问出生月份、日期、年份。我想让它在出错的地方继续（日期或年份），而不是再次向用户询问以前的良好输入以达到这一点。任何帮助将不胜感激。

【问题讨论】：

我会把它分成三个不同的循环，当我得到有效的输入时用break 退出它们。

当我在每次询问后添加“else”“break”时，这个月不会继续。

【参考方案1】：

while True:
    #get numeric birth month
    try:
        m = int(raw_input("What is your birth month?"))
    except ValueError:
        print "Enter an integer, please try again."
        continue
    if m <= 0 or m >= 13:
        print "Enter a number between 1-12, please try again."
    else:
        break

然后是一天的相同循环和一年的第三个循环。