如何在 C 中制作立体声? [关闭]
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【中文标题】如何在 C 中制作立体声? [关闭]【英文标题】:How can I make stereo wave sound in C? [closed] 【发布时间】:2021-05-09 17:36:39 【问题描述】:虽然我想在 C 中制作立体声,但我可以找到单声道声音代码,这里是
#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <iostream>
#pragma once
#define WAVE_FORMAT_UNKNOWN 0X0000;
#define WAVE_FORMAT_PCM 0X0001;
#define WAVE_FORMAT_MS_ADPCM 0X0002;
#define WAVE_FORMAT_IEEE_FLOAT 0X0003;
#define WAVE_FORMAT_ALAW 0X0006;
#define WAVE_FORMAT_MULAW 0X0007;
#define WAVE_FORMAT_IMA_ADPCM 0X0011;
#define WAVE_FORMAT_YAMAHA_ADPCM 0X0016;
#define WAVE_FORMAT_GSM 0X0031;
#define WAVE_FORMAT_ITU_ADPCM 0X0040;
#define WAVE_FORMAT_MPEG 0X0050;
#define WAVE_FORMAT_EXTENSIBLE 0XFFFE;
#define DURATION 8
#define SAMPLE_RATE 48000
#define CHANNEL 2
#define BIT_RATE 16
typedef struct
unsigned char ChunkID[4]; // Contains the letters "RIFF" in ASCII form
unsigned int ChunkSize; // This is the size of the rest of the chunk following this number
unsigned char Format[4]; // Contains the letters "WAVE" in ASCII form
RIFF;
typedef struct
unsigned char ChunkID[4]; // Contains the letters "fmt " in ASCII form
unsigned int ChunkSize; // 16 for PCM. This is the size of the rest of the Subchunk which follows this number.
unsigned short AudioFormat; // PCM = 1
unsigned short NumChannels; // Mono = 1, Stereo = 2, etc.
unsigned int SampleRate; // 8000, 44100, etc.
unsigned int AvgByteRate; // SampleRate * NumChannels * BitsPerSample/8
unsigned short BlockAlign; // NumChannels * BitsPerSample/8
unsigned short BitPerSample; // 8 bits = 8, 16 bits = 16, etc
FMT;
typedef struct
char ChunkID[4]; // Contains the letters "data" in ASCII form
unsigned int ChunkSize; // NumSamples * NumChannels * BitsPerSample/8
DATA;
typedef struct
RIFF Riff;
FMT Fmt;
DATA Data;
WAVE_HEADER;
int main()
FILE * f_out;
f_out = fopen("D:\\test.wav", "wb");
WAVE_HEADER header;
memcpy(header.Riff.ChunkID, "RIFF", 4);
header.Riff.ChunkSize = DURATION * SAMPLE_RATE * CHANNEL * BIT_RATE / 8 + 36;
memcpy(header.Riff.Format, "WAVE", 4);
memcpy(header.Fmt.ChunkID, "fmt ", 4);
header.Fmt.ChunkSize = 0x10;
header.Fmt.AudioFormat = WAVE_FORMAT_PCM;
header.Fmt.NumChannels = CHANNEL;
header.Fmt.SampleRate = SAMPLE_RATE;
header.Fmt.AvgByteRate = SAMPLE_RATE * CHANNEL * BIT_RATE / 8;
header.Fmt.BlockAlign = CHANNEL * BIT_RATE / 8;
header.Fmt.BitPerSample = BIT_RATE;
memcpy(header.Data.ChunkID, "data", 4);
header.Data.ChunkSize = DURATION * SAMPLE_RATE * CHANNEL * BIT_RATE / 8;
fwrite(&header, sizeof(header), 1, f_out);
short y[2]; double freq = 1000;
for (int i = 0; i < SAMPLE_RATE * DURATION * CHANNEL * BIT_RATE / 8; i++)
y[0] = (short)30000 * sin(2 * 3.141592 * i * freq / SAMPLE_RATE);
fwrite(&y[0], sizeof(short), 1, f_out);
fclose(f_out);
return 0;
但我想将其更改为立体声(通道 2)。 详细地说,我希望我可以控制左声音功能和右声音功能(例如 Left_sound[0] = ~~; right_sound[0] = ~~) 我的最终目标是制造警报器,它向我走来并远离我。 怎么添加左右声音的功能??
【问题讨论】:
究竟是什么问题阻碍了您自己实施?请注意,Stack Overflow 是一个询问特定编程问题的地方。您可能需要阅读此内容以获取更多信息:Why is “Can someone help me?” not an actual question? 【参考方案1】:重点是16bit立体数据在data chunk中打包如下:
+-----------------+-----------------+-----------------+-----------------+
| Left ch | Left ch | Right ch | Right ch |
| low-order byte | high-order byte | low-order byte | high-order byte |
+-----------------+-----------------+-----------------+-----------------+
那么与您的代码的区别将是:
short y[2]; double freq = 1000;
for (int i = 0; i < SAMPLE_RATE * DURATION; i++)
double level_r = (double)i / (SAMPLE_RATE * DURATION);
double level_l = 1.0 - level_r;
y[0] = (short)(30000 * sin(2 * 3.141592 * i * freq / SAMPLE_RATE) * level_l);
y[1] = (short)(30000 * sin(2 * 3.141592 * i * freq / SAMPLE_RATE) * level_r);
fwrite(&y[0], sizeof(short), 1, f_out);
fwrite(&y[1], sizeof(short), 1, f_out);
声音从左侧开始,靠近中心,然后通过
向右走。
请注意您的代码中索引i
的范围不正确,因为i
的单位是样本,而不是字节。
【讨论】:
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