在 Android/phpMyAdmin 中插入数据库时​​出错

Posted 2023-02-25

【中文标题】在 Android/phpMyAdmin 中插入数据库时​​出错

【英文标题】：Error inserting to database in Android/phpMyAdmin

【发布时间】：2016-06-06 17:39:26

【问题描述】：

如果我在网络浏览器中测试我的 php 文件，它可以工作（例如，给定 newObsindiaries.php?idd="52"&ido="1"&when="10"，它会毫无问题地插入数据库）。

但是，在 android 中，它不起作用并在日志中返回此消息：

org.json.JSONException: [idd=52, ido=1, when=10] 的字符 5 处未终止的数组

这是 PHP 代码：

<?php
$dbhost = "127.0.0.1";
$dbuser = "root";
$dbpass = "";
$dbname = "clinic_last";

$link = @mysqli_connect($dbhost,$dbuser,$dbpass,$dbname)
    or die("Impossibile collegarsi al server: " . mysqli_error());
mysqli_select_db($link ,'clinic_last')
    or die("unable to select database 'dbname': " . mysqli_error());

$idd = $_GET['idd'];
$ido = $_GET['ido'];        
$when = $_GET['when'];

$string = ("INSERT INTO obsindiaries (`when`, ido, idd)
    SELECT $when,$ido,idd FROM diaries WHERE idd = $idd LIMIT 1");

$string2 = "INSERT INTO obsindiaries (idod,idd,ido,`when`) VALUES
    (NULL,'$idd','$ido','$when')";

$flag['code']=0;

$result = mysqli_query($link,$string);
// check if row inserted or not
if ($result) 
    // successfully inserted into database    
    $response["success"] = 1;
    $response["message"] = "**successfully Registration.**";

    // echoing JSON response
    echo json_encode($response);
 
if (!$result) 
    // failed to insert row
    $response["success"] = 0;
    $response["message"] = "Oops! An error occurred.";

    // echoing JSON response
    echo json_encode($response);


if (!$result) 
    // required field is missing
    $response["success"] = 0;
    $response["message"] = "Required field(s) is missing";

    // echoing JSON response
    echo json_encode($response);

mysqli_close($link);  
?>

这是文件.class的一部分：

public void ClickSaveObsindiaries()
    SavingObs=(ImageButton)findViewById(R.id.saveObsindiaries);
    SavingObs.setOnClickListener(new OnClickListener() 
        @Override
        public void onClick(View arg0) 
            //INSERISCO VALORI DENTRO LISTA
            StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder().permitAll().build();
            StrictMode.setThreadPolicy(policy);

            List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
            nameValuePairs.add(new BasicNameValuePair("idd", ID_diary.getText().toString()));
            int positionTypeObs = typeObsindiaries.getSelectedItemPosition() + 1;
            String valueType = String.valueOf(positionTypeObs);
            nameValuePairs.add(new BasicNameValuePair("ido",valueType));
            char first = hours.getSelectedItem().toString().charAt(0);
            if (first=='I')
                nameValuePairs.add(new BasicNameValuePair("when", IntervalHours.getText().toString()));
            else 
                nameValuePairs.add(new BasicNameValuePair("when", hours.getSelectedItem().toString()));

            System.out.println("valore di RESULT: "+nameValuePairs.toString());
            try 
                HttpClient httpClient = new DefaultHttpClient();
                HttpPost httpPost = new HttpPost("http://10.0.2.2/newObsindiaries.php");
                Log.e("httpPost is:"," "+httpPost.toString());
                httpPost.setEntity(new UrlEncodedFormEntity(nameValuePairs));//,"UTF-8"

                HttpResponse response = httpClient.execute(httpPost);
                HttpEntity entity = response.getEntity();
                is = entity.getContent();
                Log.e("pass 1", "connection success ");
             catch(Exception e)   
                Log.e("Fail 1", e.toString());
                Toast.makeText(getApplicationContext(), "Invalid IP Address", Toast.LENGTH_LONG).show();
             
            try 
                BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"),8);
                StringBuilder sb = new StringBuilder();
                while ((line = reader.readLine()) != null) 
                    sb.append(line + "\n");
                
                is.close();
                result = sb.toString();
                Log.e("pass 2", "connection success ");
             catch(Exception e) 
                Log.e("Fail 2", e.toString());
                 
            try 
                JSONObject json_data = new JSONObject(nameValuePairs.toString());
                code=(json_data.getInt("code"));

                if(code==1) 
                    Toast.makeText(getBaseContext(), "Inserted Successfully", Toast.LENGTH_SHORT).show();
                 else 
                    Toast.makeText(getBaseContext(), "Sorry, Try Again", Toast.LENGTH_LONG).show();
                
             catch(Exception e) 
                Log.e("Fail 3", e.toString());
                Log.e("JSON Parser", "Error parsing data " + e.toString());
            

            AlertDialog.Builder builder = new AlertDialog.Builder(new ContextThemeWrapper(add_obsindiaries.this, R.style.myDialog));
            builder.setMessage("Misurazione inserita! Premere OK per tornare alla lista delle misurazioni")
                .setCancelable(false)
                .setPositiveButton("OK", new DialogInterface.OnClickListener() 
                public void onClick(DialogInterface dialog, int id) 
                    Intent listOBS = new Intent(add_obsindiaries.this,obsindiaries_list.class);
                    fromObsList.putString("idDiary", fromObsList.getString("idDiary"));
                    listOBS.putExtras(fromObsList);
                    add_obsindiaries.this.finish();
                    startActivity(listOBS);
                
            );
            AlertDialog alert = builder.create();
            alert.show();
        
    );

【参考方案1】：

我认为问题出在这一行

JSONObject json_data = new JSONObject(nameValuePairs.toString());

您正在尝试解析从参数返回的数据。这没有意义。而nameValuePairs.toString() 将返回与 Json 格式不匹配的字符串，这就是您收到错误的原因。你应该使用result 而不是nameValuePairs.toString()

JSONObject json_data = new JSONObject(result);

【讨论】：

感谢回复，但还不行。日志显示“新”错误“org.json.JSONException：Java.lang.String 类型的值

您需要检查从您的服务器返回的 Json。尝试使用 Postman 之类的工具来根据您的请求获得准确的结果。你能在你的php项目中发布函数json_encode吗？

我不知道问题出在哪里。我使用邮递员，ecc 检查它；如果在浏览器php文件中传递参数有效，否则无效，传递给php文件时格式结构有问题，我不知道真的需要帮助

你能把你在使用浏览器时得到的输出发到这里吗？

这是输出 "success":0,"message":"糟糕！发生错误。""success":0,"message":"必填字段是失踪”