Android登录注册:无法使用凌空将数据插入数据库
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【中文标题】Android登录注册:无法使用凌空将数据插入数据库【英文标题】:Android Login Register: Cant insert data into a database using volley 【发布时间】:2019-01-22 16:55:53 【问题描述】:伙计们,我被困在一个坚硬的地方。使用凌空我尝试在 000webhost 的数据库中创建用户。因此我使用这个Register.php
<?php
$connect = mysqli_connect("localhost", "id6777294_l2w", "123l2w456", "id6777294_l2w");
if(isset($_POST["name"]) && isset($_POST["email"]) && isset($_POST["password"]) && isset($_POST["grade"]))
$name = $_POST["name"];
$email = $_POST["email"];
$password = $_POST["password"];
$class = $_POST["grade"];
$statement = mysqli_prepare($connect, "INSERT INTO user(name, email, password, grade) VALUES (?, ?, ?, ?)");
mysqli_stmt_bind_param($statement, "sssi", $name, $email, $password, $grade);
mysqli_stmt_execute($statement);
$response = array();
$response["success"] = true;
echo json_encode($response);
?>
以及以下两个android类
public class RegisterActivity extends AppCompatActivity
@Override
protected void onCreate(Bundle savedInstanceState)
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_register);
final EditText nameID = (EditText) findViewById(R.id.nameID);
final EditText emailID = (EditText) findViewById(R.id.emailID);
final EditText passwordID = (EditText) findViewById(R.id.passwordID);
final EditText gradeID = (EditText) findViewById(R.id.gradeID);
final Button registerbtn = (Button) findViewById(R.id.registerbtn);
registerbtn.setOnClickListener(new View.OnClickListener()
@Override
public void onClick(View v)
//we need to get the data given by the user
final String name = nameID.getText().toString();
final String email = emailID.getText().toString();
final String password = passwordID.getText().toString();
final int grade = Integer.parseInt(gradeID.getText().toString());
//now we need a String Listener for the constructor
Response.Listener<String> responseListener = new Response.Listener<String>()
/**
* everything in here happens when the response listener has been executed,
* given the response (which comes as a JSON String) from the Register.php.
* If the response is not in the form of a JSON format, then JSONException
* will catch the error
*/
@Override
public void onResponse(String response)
try
JSONObject jsonResponse = new JSONObject(response);
boolean success = jsonResponse.getBoolean("success");
//if successful then go back to LoginActivity, if not make an alert
if (success)
Intent intent = new Intent(RegisterActivity.this, LoginActivity.class);
RegisterActivity.this.startActivity(intent);
else
AlertDialog.Builder builder = new AlertDialog.Builder(RegisterActivity.this);
builder.setMessage("Registrierung fehlgeschlagen").setNegativeButton("Wiederhole",null).create().show();
catch (JSONException e)
e.printStackTrace();
;
//this actual creates the request we need for registration
RegisterRequest registerRequest = new RegisterRequest(name, email, password, grade, responseListener);
RequestQueue queue = Volley.newRequestQueue(RegisterActivity.this);
queue.add(registerRequest);
);
public class RegisterActivity extends AppCompatActivity
@Override
protected void onCreate(Bundle savedInstanceState)
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_register);
final EditText nameID = (EditText) findViewById(R.id.nameID);
final EditText emailID = (EditText) findViewById(R.id.emailID);
final EditText passwordID = (EditText) findViewById(R.id.passwordID);
final EditText gradeID = (EditText) findViewById(R.id.gradeID);
final Button registerbtn = (Button) findViewById(R.id.registerbtn);
registerbtn.setOnClickListener(new View.OnClickListener()
@Override
public void onClick(View v)
//we need to get the data given by the user
final String name = nameID.getText().toString();
final String email = emailID.getText().toString();
final String password = passwordID.getText().toString();
final int grade = Integer.parseInt(gradeID.getText().toString());
//now we need a String Listener for the constructor
Response.Listener<String> responseListener = new Response.Listener<String>()
/**
* everything in here happens when the response listener has been executed,
* given the response (which comes as a JSON String) from the Register.php.
* If the response is not in the form of a JSON format, then JSONException
* will catch the error
*/
@Override
public void onResponse(String response)
try
JSONObject jsonResponse = new JSONObject(response);
boolean success = jsonResponse.getBoolean("success");
//if successful then go back to LoginActivity, if not make an alert
if (success)
Intent intent = new Intent(RegisterActivity.this, LoginActivity.class);
RegisterActivity.this.startActivity(intent);
else
AlertDialog.Builder builder = new AlertDialog.Builder(RegisterActivity.this);
builder.setMessage("Registrierung fehlgeschlagen").setNegativeButton("Wiederhole",null).create().show();
catch (JSONException e)
e.printStackTrace();
;
//this actual creates the request we need for registration
RegisterRequest registerRequest = new RegisterRequest(name, email, password, grade, responseListener);
RequestQueue queue = Volley.newRequestQueue(RegisterActivity.this);
queue.add(registerRequest);
);
我没有收到来自 logcat 等的错误或提示。当我点击注册按钮时,我回到了 LoginActivity,它看起来很完美。但是使用 phpmyadmin 检查数据库时,“用户”数据中没有新条目。
请帮忙,我做了所有建议的改进并清除了常见错误,但它不会存储数据...
【问题讨论】:
【参考方案1】:在您的绑定参数语句中,您传递了参数 $grade,但我没有看到 $grade 变量已初始化,您的意思是要传递 $class 吗?可能是检查的开始。
【讨论】:
Aww man thx这么多,我不小心把旧的php文件上传到000webhost,所以我没有发现错误以上是关于Android登录注册:无法使用凌空将数据插入数据库的主要内容,如果未能解决你的问题,请参考以下文章
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