如何在 Symfony Easy admin crud 面板中创建下拉选择？

Posted 2023-02-16

【中文标题】如何在 Symfony Easy admin crud 面板中创建下拉选择？

【英文标题】：How to create dropdown select in Symfony easy admin crud panel?

【发布时间】：2021-11-01 06:44:13

【问题描述】：

我是 Symfony 的新手。我有关系表，例如作者、书籍和 book_authors。一本书可以有很多作者，一个作者可以有很多本书。 所以，这是我的表：

现在，我正在尝试使用简单的管理扩展来实现 crud 控制器。

<?php

namespace App\Controller\Admin;

use App\Entity\Books;
use EasyCorp\Bundle\EasyAdminBundle\Config\Crud;
use EasyCorp\Bundle\EasyAdminBundle\Controller\AbstractCrudController;
use EasyCorp\Bundle\EasyAdminBundle\Field\IntegerField;
use EasyCorp\Bundle\EasyAdminBundle\Field\TextField;

class BooksCrudController extends AbstractCrudController

    public static function getEntityFqcn(): string
    
        return Books::class;
    

    public function configureFields(string $pageName): iterable
    
        return [
            TextField::new('title'),
            IntegerField::new('publish_year'),
            TextField::new('isbn'),
            IntegerField::new('pages'),
        ];
    

    public function configureCrud(Crud $crud): Crud
    
        return $crud
            ->setSearchFields(['publish_year', 'isbn', 'title', 'pages'])
            ->setPaginatorPageSize(20);
    

和

<?php

namespace App\Controller\Admin;

use App\Entity\Authors;
use EasyCorp\Bundle\EasyAdminBundle\Config\Crud;
use EasyCorp\Bundle\EasyAdminBundle\Controller\AbstractCrudController;
use EasyCorp\Bundle\EasyAdminBundle\Field\TextField;

class AuthorsCrudController extends AbstractCrudController

    public static function getEntityFqcn(): string
    
        return Authors::class;
    

    public function configureFields(string $pageName): iterable
    
        return [
            TextField::new('name'),
            TextField::new('first_name'),
            TextField::new('last_name'),
        ];
    

    public function configureCrud(Crud $crud): Crud
    
        return $crud
            ->setSearchFields(['name', 'first_name', 'last_name'])
            ->setPaginatorPageSize(20);
    

但是在 BookAuthorsCrudController 中我有一个问题：

<?php

namespace App\Controller\Admin;

use App\Entity\BookAuthors;
use EasyCorp\Bundle\EasyAdminBundle\Config\Crud;
use EasyCorp\Bundle\EasyAdminBundle\Controller\AbstractCrudController;
use EasyCorp\Bundle\EasyAdminBundle\Field\AssociationField;

class BookAuthorsCrudController extends AbstractCrudController

    public static function getEntityFqcn(): string
    
        return BookAuthors::class;
    

    public function configureFields(string $pageName): iterable
    
        return [
//            ChoiceField::new('author')->setChoices(['Joan' => 1, 'Rowling' => 2]),
// this give me only search by id, not by other fields that I need, for example I need:
// authors by name + first_name + last_name and books by title.
            AssociationField::new('author')->autocomplete(),
            AssociationField::new('book')->autocomplete(),
        ];
    

    public function configureCrud(Crud $crud): Crud
    
        return $crud
            ->setSearchFields(['book_id', 'author_id'])
            ->setPaginatorPageSize(20);
    

我不能使用 book_id 和 author_id 来实现搜索功能。只有在 BookAuthor 实体中实现的书籍和作者：

<?php

namespace App\Entity;

use App\Repository\BookAuthorsRepository;
use Doctrine\ORM\Mapping as ORM;

/**
 * @ORM\Entity(repositoryClass=BookAuthorsRepository::class)
 */
class BookAuthors

    /**
     * @ORM\Id
     * @ORM\GeneratedValue
     * @ORM\Column(type="integer")
     */
    private $id;

    /**
     * @ORM\ManyToOne(targetEntity=Authors::class, inversedBy="books")
     * @ORM\JoinColumn(nullable=false)
     */
    private $author;

    /**
     * @ORM\ManyToOne(targetEntity=Books::class, inversedBy="authors")
     * @ORM\JoinColumn(nullable=false)
     */
    private $book;

    public function getId(): ?int
    
        return $this->id;
    

    public function getAuthor(): ?Authors
    
        return $this->author;
    

    public function setAuthor(?Authors $author): self
    
        $this->author = $author;

        return $this;
    

    public function getBook(): ?Books
    
        return $this->book;
    

    public function setBook(?Books $book): self
    
        $this->book = $book;

        return $this;
    

请帮帮我！

【参考方案1】：

使用点在 Doctrine 关联中进行搜索。

（例如“book.id”或“author.id”）而不是 book_id 或 author_id。

或者在 Book 和 Author 中实现 __toString() 方法。

【讨论】：

我不能在 AssociationFields 中使用它...因为它要求我选择 BookAuthors 实体字段。

或者在Book和Author中实现__toString()方法