在 wordpress 自定义模板中显示插入的数据

Posted 2023-02-24

【中文标题】在 wordpress 自定义模板中显示插入的数据

【英文标题】：Display the inserted data in wordpress custom template

【发布时间】：2017-05-15 07:45:55

【问题描述】：

您好，我正在开发一个文字新闻网站。我创建了一个自定义模板，其中我有一个表单和字段被插入到数据库（mysql）中。代码如下所示。Insert into database

现在我需要以table 或grid 的形式在前端显示已经插入数据库的数据。我怎么能做到这一点。

我需要这样的输出。

      Ritual Name   Ritual Active
      ---------------------------
      Test1        |    Y
      Test2        |    Y

任何帮助表示赞赏。

函数.php

function childtheme_style_andscripts()
    //wp_enqueue_style('parent-style', get_template_directory_uri() . '/style.css'  );
    wp_enqueue_script('ajax-function',  get_stylesheet_directory_uri() .   '/js/ajaxfunction.js', array('jquery'), '1.0', true );
    wp_localize_script( 'ajax-function', 'usersubmitform', array(
'url'=> admin_url('admin-ajax.php'),
    'security'=> wp_create_nonce('our-nonce')
    ) );


add_action('wp_enqueue_scripts','childtheme_style_andscripts');

function form_action_function() 
    require_once(dirname( __FILE__ ).'/../../../wp-load.php');
    $data = $_POST['data'];
    global $wpdb;
    if( !check_ajax_referer('our-nonce', 'security' ) ) 
        wp_send_json_error('security failed');
        return;
    
    //var_dump($data);
    $rname=$data['rname'];
    $ractive=$data['ractive'];

    $table_name = "rituals";
    $wpdb->insert($table_name, array ('Ritual_Name' => $rname, 'Ritual_Active' => $ractive) );

    //$wpdb->show_errors();
    //$wpdb->print_error();
    echo 'From Submitted Successfully';
    die();

add_action('wp_ajax_nopriv_form_action_function','form_action_function');
add_action('wp_ajax_form_action_function','form_action_function');

ajaxfunction.js

jQuery(document).ready(function($)
var submitButton = document.getElementById('usersubmit');
var ajaxFunctionformprocess = function(fromdata, action)
    $.ajax(
        type:'post',
        url: usersubmitform.url,
        data:
            action:action,
            data:fromdata,
            security:usersubmitform.security,               
        ,
        success:function(reponse)
            $('div.msg').html(reponse);
        ,
        error:function(response)
            alert(response);
        
    );     


submitButton.addEventListener('click', function(event)
    event.preventDefault();
    var fromdata = 
        'rname':document.getElementById('rname').value,
        'ractive':document.getElementById('ractive').value,
    ;
    ajaxFunctionformprocess(fromdata, 'form_action_function');  

    ); 
  );

Samplepage.php(自定义模板)

  <div id="primary" class="content-area">
    <div id="content" class="site-content" role="main">
        <h1 class="headingform">User Form</h1>
        <div class="msg"></div>
        <form  class="userform">
            Ritual Name: <input type="text" id="rname" name="rname" /><br> <br>
            Ritual Active: <input type="text" id="ractive" name="ractive" /> <br><br> 
            <input  id="usersubmit"type="submit" Value="Submit" />
        </form>

    </div><!-- #content -->
</div><!-- #primary -->

【问题讨论】：

***.com/questions/25065600/… 检查第二个答案

赏金未奖励

你能告诉我你在编辑器中真正需要什么吗？

@VasimVanzara 在编辑器中，我需要一个包含许多细节的弹出表单。当我单击可视化编辑器中的按钮时，应该会出现弹出窗口。

【参考方案1】：

案例一：从表格中创建展示信息的模板

<?php
/*

Template Name: Disply Ritural
Description: display ritual information in table formate

*/


global $wpdb;
$table_name = "rituals";

$result = $wpdb->get_results ("SELECT * FROM  $table_name");


foreach ( $result as $ritual_info )

        echo $ritual_info['Ritual_Name'];
        echo $ritual_info['Ritual_Active'];

案例 2：创建一个易于使用的简码。打开您的 functions.php 文件在此处添加代码。

function show_ritual_info()
global $wpdb;
$table_name = "rituals";
$query="SELECT * FROM  $table_name";
$result = $wpdb->get_results ($query);


foreach ( $result as $ritual_info )

        echo $ritual_info['Ritual_Name'];
        echo $ritual_info['Ritual_Active'];



add_shortcode('show_ritual_info','show_ritual_info');

如何使用短代码

php 文件内部

<?php echo do_shortcode('[show_ritual_info]'); ?>

内部管理页面

['show_ritual_info']

【讨论】：

我收到了这些警告Warning: strpos() expects parameter 1 to be string, array given in C:\xampp\htdocs\wordpress-4.7\wordpress\wp-includes\shortcodes.php on line 205 Warning: preg_match_all() expects parameter 2 to be string, array given in C:\xampp\htdocs\wordpress-4.7\wordpress\wp-includes\shortcodes.php on line 213 Warning: array_intersect(): Argument #2 is not an array in C:\xampp\htdocs\wordpress-4.7\wordpress\wp-includes\shortcodes.php on line 214 Array

我用的是案例2

在函数 .php 中我已经放置了这段代码function show_ritual_info() require_once(dirname( __FILE__ ).'/../../../wp-load.php'); global $wpdb; $table_name = "rituals"; $result = $wpdb->get_results ("SELECT * FROM $table_name"); $wpdb->show_errors(); $wpdb->print_error(); foreach ( $result as $ritual_info ) echo $ritual_info['Ritual_Name']; echo $ritual_info['Ritual_Active']; add_shortcode('show_ritual_info','show_ritual_info');

在自定义模板中我添加了这个<?php echo do_shortcode(['show_ritual_info']); ?>

function show_ritual_info() global $wpdb; $table_name = "rituals"; $result = $wpdb->get_results ("SELECT * FROM $table_name"); $wpdb->show_errors(); $wpdb->print_error(); //foreach ( $result as $ritual_info ) // echo $ritual_info['Ritual_Name']; echo $ritual_info['Ritual_Active']; // add_shortcode('show_ritual_info','show_ritual_info');

【参考方案2】：

类似这样的：

<?php
        global $wpdb;
        $table_name = "rituals";
        // this will get the data from your table
        $retrieve_data = $wpdb->get_results( "SELECT * FROM $table_name" );
        ?>
        <?php if( ! empty($retrieve_data) ):?>
        <table>
            <tr>
                 <th>Ritual Name</th>
                 <th>Ritual Active</th>
            </tr>
            <?php foreach ($retrieve_data as $retrieved_data): ?>
            <tr>
                <td><?php echo $retrieved_data['Ritual_Name'];?></td>
                <td><?php echo $retrieved_data['Ritual_Active'];?></td>
            </tr>
            <?php endforeach; ?>
        </table>
        <?php endif; ?>

不检查但必须工作。）