使用php将网络摄像头生成的图像上传到mysql数据库不起作用
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【中文标题】使用php将网络摄像头生成的图像上传到mysql数据库不起作用【英文标题】：Uploading image generated from webcam to mysql database with php not working 【发布时间】：2016-03-22 12:25:29 【问题描述】：尝试使用 php 将用户网络摄像头生成的图像插入 mysql 数据库，但它不起作用。我正在使用 webcam.js，一切正常。当用户拍摄快照时，图像存储在服务器上，但是，mysql insert 不执行插入作业。知道为什么它不起作用吗？
两个代码如下所示：
cam.php:
session_start();
include_once 'dbconnect.php';//connection to db
if(!isset($_SESSION['user']))//ensures that it the true user
header("Location: index.php");
//display current time
//$arrival_time= date('Y-m-d H-i-s');
//echo "$arrival_time";
if (isset($_POST['send']))
$getname= mysql_real_escape_string($_POST['last_name']);
$idvalue= $_SESSION['myvalue'];
$update=mysql_query("UPDATE `employees`.`webcam_clockin`
SET `last_name`='$getname' WHERE image_id='$idvalue'");
if($update)
//run a check to verify last_name
$sql=mysql_query("SELECT users.*, employees.* FROM users
NATURAL JOIN employees
WHERE employees.last_name='$getname'");
$result=mysql_fetch_array($sql);
if($result)
$_SESSION['user'] = $result['user_id'];
header("Location: home.php");
else
?>
<script>
alert('Wrong Last Nane');
</script>
<?php
else
echo "Error Not done";
</style>
</head>
<body>
<div class="container">
<div align="center">
<script>
webcam.set_api_url( 'camsave.php' );
webcam.set_quality( 100 ); // JPEG quality (1 - 100)
webcam.set_shutter_sound( true ); // play shutter click sound
</script>
<script>
document.write(webcam.get_html(640, 480));
webcam.set_hook('onComplete', 'my_callback');
function my_callback(msg)
document.getElementById('upload').innerHTML = msg;
function do_upload()
webcam.snap();
function my_callback(msg)
// extract URL out of PHP output
if (msg.match(/(https\:\/\/\S+)/))
var image_url = RegExp.$1;
// show JPEG image in page
document.getElementById('upload_results').innerHTML =
'<h1>Upload Successful!</h1>' +
'<h3>JPEG URL: ' + image_url + '</h3>';
else alert("PHP Error: " + msg);
</script>
</div>
<div>
<form class="form-signin" id="myForm"><br>
<h3 class="form-signin-heading">Enter Your Name. Take a Nice Picture and Submit</h3>
<input type=button class="btn btn-lg btn-primary btn-block" id="snap"
onclick="do_upload()" value="Snap">
</form>
<form action="<?php echo $_SERVER["PHP_SELF"];?>" method="post" class="form-signin" ><br>
<label for="last_name" class="sr-only">Enter Last Name</label>
<input type="text" name="last_name" id="last_name"
class="form-control" placeholder="Last Name" required autofocus>
<input type="submit" class="btn btn-lg btn-primary btn-block" name="send" id="send">
</form>
</div>
</td><td width=50> </td><td valign=top>
<div id="upload"></div>
</td></tr></table>
</div>
</body>
</html>
camsave.php：
session_start();
include_once 'dbconnect.php';
if(!isset($_SESSION['user']))
header("Location: index.php");
//get some data about this user
$res2=mysql_query("SELECT users.*, employees.* FROM users
NATURAL JOIN employees WHERE user_id=".$_SESSION['user']);
$userRow=mysql_fetch_array($res2);
if ($userRow)
echo "correct!!";
//Define storage location of original images
$folder = "images/";
$filename = date('Y-m-d-H-i-s') . '.jpg';
$original = $folder.$filename;
//Get JPEG snapshot from webcam
$input = file_get_contents('php://input');
//Blank images are discarded
if(md5($input) == '7d4df9cc423720b7f1f3d672b89362be')
exit();
//Retreive the snap and save to original dest.
$file= file_put_contents($original, $input);
if(!$file)
print "ERROR: Failed to write data to $filename, check permissions\n";
exit();
else
//Get the size of the image
$info = getimagesize($original);
list($width,$height) = $info;
if($info['mime'] != "image/jpeg")//ensure we get right file extension
unlink($original);
exit();
//Move images to the Original folder
rename($original, "images/original/".$filename);
$emp_no = $userRow['emp_no'];//employee number
$user_id = $_SESSION['user_id'];//user ID
$image_id = NULL;
$original = "images/original/".$filename;//our image
$last_name =$_SESSION['last_name'];
$path = "images/thumbnail/".$filename;
$sql=mysql_query("INSERT INTO `webcam_clockin`
(`image_id`, `user_id`, `images`, `emp_no`, `last_name`)
VALUES ('$image_id', '$user_id','$path','$emp_no', '$last_name')");
move_uploaded_file($original, $path);
if(move_uploaded_file($filename, $original))
echo "The file ". $original.$filename. " has been uploaded, and your information has been added to the directory";
echo "Thank You "; echo $userRow['username']; echo".\n";
else
echo "Sorry, there was a problem uploading your file.";
echo "Error inserting entry data: ".mysql_error();
?>
<script>
alert('Error Inserting your details. Please, see your department manager');
</script>
<?php
$value=mysql_insert_id();
$_SESSION["myvalue"]=$value;
$url = 'https://' . $_SERVER['HTTP_HOST'] . dirname($_SERVER['REQUEST_URI']) . '/' . $filename;
print "$url\n";
我终于解决了将图像保存到数据库的问题。问题是 phpmyadmin 中的数据类型错误，应该是 longblob。
【问题讨论】：
拜托，任何人都可以帮助这是我项目的最后一面，而且很紧急。谢谢 调试问题的第一个措施是捕获 mysql 错误并打印它们。 我开启了php调试，没有打印出错误，mysql也一样，没有打印出错误 我建议永远不要在 MySQL 中存储大文件。而是使用文件指针并自己管理旧文件的删除。它更加强大。 您不需要编辑您的问题以包含解决方案，而是需要发布对您的问题的正确答案并将您的问题恢复到较早的版本。 【参考方案1】：我来不及回答，但可能会对其他人有所帮助，我为此编写了教程。你可以check it here。在本教程中我使用了 HTML5、Jquery、PHP 本教程将使用 PHP 类并以两种方式保存图像。
-
本地存储
Base64
在这两种情况下，它都会将图像存储到数据库中
【讨论】：
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