转换为 mysql_connect 到 PDO

Posted 2023-02-24

【中文标题】转换为 mysql_connect 到 PDO

【英文标题】：Convert to mysql_connect to PDO

【发布时间】：2017-01-26 19:15:27

【问题描述】：

您好，我可以使用此代码，但我需要将代码转换为 PDO。 我尝试了很多变化，但没有奏效。 我有 $conn 作为连接。 提前致谢。

        $projectrfpid = $_GET['projectrfpid'];
        $allRecords = mysql_query('SELECT * FROM projectscostbreakdown WHERE projectscostbreakdown_projectid='.$projectrfpid.' AND projectscostbreakdown_deleted=1 ORDER BY projectscostbreakdown_areaname, projectscostbreakdown_order ASC');
        if(is_resource($allRecords))
        
            while($row = mysql_fetch_assoc($allRecords))
            
                ?>
                <tr id="<?php echo $row['projectscostbreakdown_id']; ?>" >
                    <td ><img src="../test/images/icon-drag.png"   style="cursor:pointer;"/></td>
                    <td><b><?php echo $row['projectscostbreakdown_areaname']; ?>:</b> <?php echo $row['projectscostbreakdown_itemname']; ?><br /><?php echo nl2br($row['projectscostbreakdown_itemdescription']); ?></td>
                </tr>
                <?php
            
        
        ?>

【问题讨论】：

您应该向我们展示您的尝试以及您遇到的问题。 *** 不是一个要求别人为你工作的网站。

抱歉，我试了很多次，一旦失效就删除了代码。所以我无法记录我尝试过的内容。很快就会更新。谢谢。

【参考方案1】：

I am writing a general format.
Fill up the below fields:
$dbhost     = "";
$dbname     = "";
$dbuser     = "";
$dbpass     = "";

//make the connection

$conn = new PDO("mysql:host=$dbhost;dbname=$dbname",$dbuser,$dbpass);

$sql="SELECT * FROM projectscostbreakdown WHERE projectscostbreakdown_projectid=:id AND projectscostbreakdown_deleted=1 ORDER BY projectscostbreakdown_areaname, projectscostbreakdown_order ASC";

//always use parameterized queries

$query=$conn->prepare("$sql");

//Bind parameter values using PDO's bindValue method
$query->bindValue(':id', $projectrfpid);  

$query->execute();
$results = $query->fetchAll(PDO::FETCH_ASSOC);

Look up the PDO section in the php manual to learn more.

【参考方案2】：

做这个改变..

$con = mysqli_connect(DB_SERVER,DB_USER,DB_PASSWORD,DB_NAME);
$sql ="SELECT * FROM projectscostbreakdown WHERE projectscostbreakdown_projectid='.$projectrfpid.' AND projectscostbreakdown_deleted=1 ORDER BY projectscostbreakdown_areaname, projectscostbreakdown_order ASC";

$allRecords = mysqli_query($con, $sql);

while ($row = mysqli_fetch_array($allRecords , MYSQLI_ASSOC)) 
  
    ?>
      <tr id="<?php echo $row['projectscostbreakdown_id']; ?>" >
        <td ><img src="../test/images/icon-drag.png"   style="cursor:pointer;"/></td>
        <td><b><?php echo $row['projectscostbreakdown_areaname']; ?>:</b> <?php echo $row['projectscostbreakdown_itemname']; ?><br /><?php echo nl2br($row['projectscostbreakdown_itemdescription']); ?></td>
      </tr>
    <?php