php include_once 使我的代码停止运行

Posted 2023-02-24

【中文标题】php include_once 使我的代码停止运行

【英文标题】：php include_once makes my code stop running

【发布时间】：2015-12-28 14:10:58

【问题描述】：

我有一个简单的 html 表单，用于将字段中的信息 http POST 到文件 register.php。在 register.php 中成功执行回显只是为了表明文件已被输入。下一行使用 include_once 包含一个名为 UserManagement.php 的文件，该文件包含一个同名的类。然后尝试实例化这个类，以便可以访问它的方法，但是程序流似乎永远不会超过 register.php 中的第一个 echo 语句。 我希望更有经验的人能直接发现一个菜鸟错误。我花了很长时间研究问题所在，但我似乎无法理解。

我的 2 个 php 文件和我的 html 表单如下：

<form action="register.php" method="POST">
    Username: <input type="text" name="uname" /><br />
    FirstName: <input type="text" name="fname" /><br />
    Last Name: <input type="text" name="lname" /><br />
    Date of Birth: <input type="date" name="dob" /><br />
    Telephone: <input type="mob" name="tel" /><br />
    Email: <input type="email" name="email1" /><br />
    Confirm Email: <input type="email" name="email2" /><br />
    Password: <input type="password" name="pass1" /><br />
    Confirm Password: <input type="password" name ="pass2" /><br />
    <input type="submit" value="Register" name="sub" />
    
    <br/><A HREF="login.php">Already Registered? Login Here</A><br/>
</form>  

注册.php

<?php
echo "entered register.php";
require_once('UserManagement.php');
echo "userman was included";
$um = new UserManagement();
echo "usermanagement object created";
$response = array("error" => FALSE);
//check that all fields were populated by the http POST.
echo "about to check if fields are all populsted";

if( isset($_POST['uname']) &&  
    isset($_POST['fname']) &&
    isset($_POST['lname']) &&
    isset($_POST['tel']) &&  
    isset($_POST['dob']) &&  
    isset($_POST['email1']) &&
    isset($_POST['email2']) &&  
    isset($_POST['pass1']) &&  
    isset($_POST['pass2'])) 

    echo "all fields were populated";
    //take values from http POST
    $uname = $_POST['uname'];
    $fname = $_POST['fname'];
    $lname = $_POST['lname'];
    $tel = $_POST['tel'];
    $dob = $_POST['dob'];
    $email1 = $_POST['email1'];
    $email2 = $_POST['email2'];
    $pass1 = $_POST['pass1'];
    $pass2 = $_POST['pass2'];
    $um->registerUser($uname,$fname,$lname,$tel,$dob,$email1,$pass1);

else 
    echo "not all fields were populated";

?>

用户管理.php

<?php
require_once('DB_Connect.php');
//Contains functions for all user management related isues i.e. add, remove, edit user.
//only user management - essentially CRM.
class UserManagement

    echo "entered user management class";
    private $conn;

    function __construct()
    
        echo "user management constructo end";

        $db = new DB_Connect();
        $this->conn = $db->connect();
        echo "user management constructo end";
    

    function __destruct()
    
        //TODO
    

    function registerUser($username,$firstname,$lastname,$telephone,$dob,$email,$password)
    
        echo "you chose to register a new user.";
        $uuid = uniqid('', true);
        $hash = $this->hashSSHA($password);
        $encrypted_password = $hash["encrypted"]; // encrypted password
        $salt = $hash["salt"]; // salt

        $sql = "INSERT INTO User(`id`,`username`,`first_name`,`last_name`,`telephone`,`email`,`password`) VALUES (NULL,?,?,?,?,?,?)";
        $stmt = $this->conn->prepare($sql);
        $stmt->bind_param('ssssss',$username,$firstname,$lastname,$telephone,$email,$encrypted_password);
        $result = $stmt->execute();

        echo "user added";
        echo $result;
        $stmt->close();
    

    function unregisterUser($uname,$pass1,$pass2)
    
        echo "you chose to deregister a user.";
    

    public function hashSSHA($password) 
    

        $salt = sha1(rand());
        $salt = substr($salt, 0, 10);
        $encrypted = base64_encode(sha1($password . $salt, true) . $salt);
        $hash = array("salt" => $salt, "encrypted" => $encrypted);
        return $hash;
    

    public function checkhashSSHA($salt, $password) 
    
            $hash = base64_encode(sha1($password . $salt, true) . $salt);
            return $hash;
        

?>

DB_Connect.php

    <?php
class DB_Connect 
    private $conn;
    // Connecting to database
    public function connect() 
        // Connecting to mysql database
        require_once('Config.php');
        $this->conn = new mysqli(DB_HOST, DB_USER, DB_PASSWORD, DB_DATABASE);
        // return database handler
        return $this->conn;
            

?>

【问题讨论】：

请在您的 php 文件顶部添加 error_reporing( -1 ); 以获取错误并在此处分享以寻求帮助:-)

显示 require_once('DB_Connect.php') 的内容；或删除该行进行测试。

您的班级名称是 UserManagement，您正在调用 $um->registerUser

把它改成 $UserManagement->registerUser .

是error_reporting，不是error_reporing

【参考方案1】：

您的问题是类定义中的echo 行：

...
class UserManagement

    echo "entered user management class";
    private $conn;
...

类定义子句不能用于执行代码，因为它违反了 OOP 原则。