将控制台应用程序输出获取到 xml 文件并保存文件 [重复]

Posted 2023-02-16

【中文标题】将控制台应用程序输出获取到 xml 文件并保存文件 [重复]

【英文标题】：Get Console application output to xml file and save the file [duplicate]

【发布时间】：2021-08-05 01:01:02

【问题描述】：

我的 ASP.Net 控制台应用程序生成一个 xml 输出，我如何创建一个 xml 文件并保存它？

namespace ConsoleApp2

课堂节目 静态异步任务 Main(string[] args) var TicketTask = 等待 createTicket(); var TicketTask2 = 等待 createTicket2();

    async static Task<string> createTicket2()
    
        var content = "unknown error";
        using (var httpClient = new System.Net.Http.HttpClient())
        
            using (var request = new System.Net.Http.HttpRequestMessage(new HttpMethod("POST"), "http://10/sap-lve/"))
            
                try
                
                    var base64authorization = Convert.ToBase64String(Encoding.ASCII.GetBytes("an:s"));
                    request.Headers.TryAddWithoutValidation("Authorization", $"Basic base64authorization");

                    String str1 = @"<s:Envelope xmlns:s='http://schemas.xmlsoap.org/soap/envelope/'><s:Body><Get_api_version xmlns='http://e.s.a.com'/></s:Body></s:Envelope>";

                    request.Content = new StringContent(str1, Encoding.UTF8, "text/xml"); ;
                    request.Content.Headers.ContentType = MediaTypeHeaderValue.Parse("text/xml");
                    ServicePointManager.Expect100Continue = true;
                    ServicePointManager.SecurityProtocol = SecurityProtocolType.Tls12;
                    HttpResponseMessage response = await httpClient.SendAsync(request).ConfigureAwait(false);
                    content = await response.Content.ReadAsStringAsync().ConfigureAwait(false);
                    //Console.WriteLine(response);
                    var result = response.Content.ReadAsStringAsync();
                    Console.WriteLine(result.Result);

                
                catch (Exception ex)
                
                    content = ex.Message;
                
            
        
        return content;
    

【参考方案1】：

从 xml 字符串创建一个 XmlDocument 并使用其保存方法。

string s = "<xml><sample></sample></xml>";
XmlDocument doc = new XmlDocument();
doc.LoadXml(s);
doc.Save("myfilename.xml");

【讨论】：

谢谢，解决了！