JavaScript 拆分字符串变量（不使用任何额外变量）

Posted 2023-02-24

【中文标题】JavaScript 拆分字符串变量（不使用任何额外变量）

【英文标题】：JavaScript split string variable (without using any extra variable)

【发布时间】：2014-03-25 00:29:08

【问题描述】：

我正在使用 MVC 模型 (django)。我在模板中有一个从 sqlite3 数据库收集数据的 for 循环。我需要填充一个 javascript 变量（采用 JSON 格式）从数据库中拆分 radar.client 字段。此字段是一个逗号分隔值字符串。我需要将其解析为不同“子”值的 json。让我现在开始练习。

生成 json var 的代码如下所示：

var json = 
    "id": "1",
    "name": "Server",
    "children": [
      % if clave_radar % 
        % for radar in clave_radar % 
        "id": " radar.key ",
         "name": " radar.ap ",
         "data": "": "", "": "",
         "children": [
//This is where I need to split in different children
               "id": "1_ radar.key ",
                "name": " radar.clients ",
                "data": "": "", "": "",
                "children": [],

         ],
          % endfor % 
      % endif % 
    ],
;

现在让我向您展示一个示例，说明服务器中处理后的代码对于客户端的外观：

  var json_test=
    "id": "1",
    "name": "Server",
    "children": [
      
        "id": "13",
        "name": "WLT",
        "data": "": "","": "",
        "children": [
          
            "id": "1_13",
            "name": "081196(Intel Corporate), 68a3c4(Liteon Technology Corporation), b8d9ce(Samsung Electronics)",
            "data": "": "","": "",
            "children": []
          ,
          //Children Liteon and Samsung should appear here and not packed in 1_13
        ]
      ,
      ],
  ;

这就是我努力使它看起来像的方式：

varjson_real=
  "id": "1",
  "name": "Server",
  "children": [
    
      "id": "13",
      "name": "WLT",
      "data": "": "","": "",
      "children": [
        
          "id": "1_13",
          "name": "081196(Intel Corporate)",
          "data": "": "","": "",
          "children": []
        ,
        
          "id": "2_13",
          "name": "68a3c4(Liteon Technology Corporation)",
          "data": 
            "": "",
            "": ""
          ,
          "children": []
        ,
        
          "id": "3_13",
          "name": "b8d9ce(Samsung Electronics)",
          "data": "": "","": "",
          "children": []
        ,
      ]
    ,  
  ]
;

【问题讨论】：

您的问题是什么？很想投票结束这个......

【参考方案1】：

为什么你不循环客户端，像这样：

var json = 
"id": "1",
"name": "Server",
"children": [
% if clave_radar % 
    % for radar in clave_radar % 
        "id": " radar.key ",
         "name": " radar.ap ",
         "data": "": "", "": "",
         "children": [
         % for client in radar.clients %
              "id": "1_ radar.key ",
               "name": " client ",
               "data": "": "", "": "",
               "children": [],
         % endfor % 
         ],
    % endfor % 
% endif % 
],
;

【讨论】：

我已经尝试过这种方式，它将为每个字符在“081196（英特尔公司），68a3c4（Liteon Technology Corporation），b8d9ce（三星电子）”，我需要 for 在这种特殊情况下发生 3 次（逗号分隔）。

我不知道它是一个字符串，无论如何你可以将 forloop 更改为： % for client in radar.clients.split(', ') % 这就是你要拆分这个字符串的原因到 3 个对象。

您正在帮助我更接近解决方案...我无法在 django 的 for 中使用 .split。不过，我现在正在阅读如何从模型中拆分 ***.com/questions/8317537/…

【参考方案2】：

我刚刚找到了解决这个问题的方法。首先我受到this how to split a string to an array with django的启发

我将此功能添加到radar 模型中：

def list_clients(self):
    return self.clientes_encontrados.split('), ')

然后，代码会像这样：

var json_radar = 
    "id": "1",
    "name": "Server",
    "children": [
    % if clave_radar %
      % for radar in clave_radar %
        "id": " radar.key ",
        "name": " radar.ap ",
        "data": "": "","": "",
        "children": [
          % if radar.clients != "null" %
            % for client in radar.list_clients %
          "id": "1_ radar.key ",
           "name": " client ",
           "data": "": "", "": "",
           "children": [],
            % endfor %
          % endif % 

        ],
        % endfor %
    % endif %  
    ],
;