Swift 3.0：推送通知中对成员“下标”问题的模糊引用

Posted 2023-02-24

【中文标题】Swift 3.0：推送通知中对成员“下标”问题的模糊引用

【英文标题】：Swift 3.0 : Ambiguous reference to member 'Subscript' issue in push notification

【发布时间】：2017-01-20 10:24:38

【问题描述】：

这是以下代码，但我在 swift3 中收到以下错误

func application(_ application: UIApplication, didReceiveRemoteNotification userInfo: [AnyHashable : Any], fetchCompletionHandler completionHandler: @escaping (UIBackgroundFetchResult) -> Void) 
    notificationReceived(notification: userInfo as [NSObject : AnyObject])


func notificationReceived(notification: [NSObject:AnyObject]) 
        let viewController = window?.rootViewController
        let view = viewController as? ViewController
        view?.addNotification(
            title: getAlert(notification: notification).0,
            body: getAlert(notification: notification).1)
    

    private func getAlert(notification: [NSObject:AnyObject]) -> (String, String) 
        let aps = notification["aps"] as? NSDictionary
        let alert = aps?["alert"] as? [String:AnyObject]
        let title = alert?["title"] as? String
        let body = alert?["body"] as? String
        return (title ?? "-", body ?? "-")
    

但我在“let aps = notification["aps"] as?NSDictionary 处收到以下错误“Swift 3.0 : Ambiguous reference to member 'Subscript' issue” >"

【参考方案1】：

类型转换

将 userInfo 从 NSDictionary 更改为 [String : Any]。并尝试一次

let aps = notification["aps"] as? [String : Any]

或者像这样写

let aps = notification["aps" as NSString] as? [String:Any]

【参考方案2】：

字符串不能转换为 NSObject，只需使用 Swift 3 将所有 [NSObject:AnyObject] 重命名为 [String:Any]