获取不同级别的所有同名节点
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【中文标题】获取不同级别的所有同名节点【英文标题】:Get all nodes with the same name in different levels 【发布时间】:2017-03-07 19:16:25 【问题描述】:以下是我的 XML 文件:
<scenario>
<negotiation>
<type>auction</type>
<agent>
<type>UtilityCompany</type>
<electricityPlan>
<type>PlanUtility</type>
<offeredEnergy>10</offeredEnergy>
<duration>20</duration>
<price>10</price>
<role>
<type>Seller</type>
</role>
<electricityOrder>
<type>SalesOrder</type>
</electricityOrder>
</electricityPlan>
</agent>
<agent>
<type>LargeCustomer</type>
<electricityPlan>
<type>LargecPlan</type>
<requestedEnergy>100</requestedEnergy>
<duration>20</duration>
<price>10</price>
<role>
<type>Buyer</type>
</role>
<electricityOrder>
<type>PurchaseOrder</type>
</electricityOrder>
</electricityPlan>
</agent>
</negotiation>
</scenario>
我需要知道如何将<type></type>
标签内的所有值附加到ArrayList
。
类似于以下内容:
Agent[0] = UtilityCompany
Agent[1] = LargeCustomer
electricityPlan[0] = PlanUtility
electricityPlan[1] = LargecPlan
role[0] = Seller
role[1] = Buyer
有人可以提供一些见解吗?
更新信息
目前,我有这个:
public static void main(String[] args) 抛出 ParserConfigurationException、SAXException、IOException、XPathExpressionException
File fXmlFile = new File("scenario.xml");
DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
Document doc = dBuilder.parse(fXmlFile);
NodeList nodes = doc.getElementsByTagName("negotiation");
Element element = (Element) nodes.item(0);
NodeList negotiationList = element.getElementsByTagName("agent");
for (int i = 0; i < negotiationList.getLength(); i++)
Element negotiationElement = (Element) negotiationList.item(i);
NodeList agent = negotiationElement.getElementsByTagName("type");
System.out.println(agent.item(0).getFirstChild().getTextContent());
NodeList role = negotiationElement.getElementsByTagName("role");
Element roleline = (Element) role.item(0);
System.out.println(roleline.getElementsByTagName("type").item(0).getTextContent());
Output
UtilityCompany
Seller
LargeCustomer
Buyer
LargeCustomer
Buyer
大客户 买家
但我不知道如何从
中获取值 1. <type>auction</type>
2. <type>PlanUtility</type> from ElectricityPlan tag.
最后我找到了解决方案:
此代码用于获取请求的节点
我有一个解决方案:
public class ReadingXML
static List<String> AuctionType = new ArrayList<String>();
static List<String> AgentType = new ArrayList<String>();
static List<String> PlanType = new ArrayList<String>();
static List<String> RoleType = new ArrayList<String>();
static List<String> OrderType = new ArrayList<String>();
static NodeList auction ;
public List<List<String>> ReadingXML(String fileLocation) throws
ParserConfigurationException, SAXException, IOException
//File fXmlFile = new File("C:....location\\scenario.xml");
File fXmlFile = new File(fileLocation);
DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
Document doc = dBuilder.parse(fXmlFile);
List<List<String>> listOfLists = Lists.newArrayList();
NodeList nodesScenario = doc.getElementsByTagName("scenario");
Element element0 = (Element) nodesScenario.item(0);
NodeList scenarioList = element0.getElementsByTagName("negotiation");
for (int j = 0; j < scenarioList.getLength(); j++)
Element scenarioElement = (Element) scenarioList.item(j);
auction = scenarioElement.getElementsByTagName("type");
System.out.println(auction.item(0).getFirstChild().getTextContent());
AuctionType.add(auction.item(0).getFirstChild().getTextContent());
List<String> AuctionTypeFiltered = Lists.newArrayList(Sets.newHashSet(AuctionType));
listOfLists.add(Lists.newArrayList(AuctionTypeFiltered));
NodeList nodesNegotiation = doc.getElementsByTagName("negotiation");
Element element = (Element) nodesNegotiation.item(0);
NodeList negotiationList = element.getElementsByTagName("agent");
for (int i = 0; i < negotiationList.getLength(); i++)
Element negotiationElement = (Element) negotiationList.item(i);
NodeList agent = negotiationElement.getElementsByTagName("type");
System.out.println(agent.item(0).getFirstChild().getTextContent());
AgentType.add(agent.item(0).getFirstChild().getTextContent());
NodeList nodesElectricityPlan = doc.getElementsByTagName("electricityPlan");
Element element1 = (Element) nodesElectricityPlan.item(0);
NodeList ElectricityPlanList = element1.getElementsByTagName("plan");
for (int j = 0; j < ElectricityPlanList.getLength(); j++)
Element electricityPlanElement = (Element) ElectricityPlanList.item(j);
NodeList plan = electricityPlanElement.getElementsByTagName("type");
System.out.println(plan.item(0).getFirstChild().getTextContent());
PlanType.add(plan.item(0).getFirstChild().getTextContent());
List<String> PlanTypeFiltered = Lists.newArrayList(Sets.newHashSet(PlanType));
listOfLists.add(Lists.newArrayList(PlanTypeFiltered));
NodeList role = negotiationElement.getElementsByTagName("role");
Element roleline = (Element) role.item(0);
System.out.println(roleline.getElementsByTagName("type").item(0).getTextContent());
RoleType.add(roleline.getElementsByTagName("type").item(0).getTextContent());
NodeList electricityorder = negotiationElement.getElementsByTagName("electricityOrder");
Element electricityorderline = (Element) electricityorder.item(0);
System.out.println(electricityorderline.getElementsByTagName("type").item(0).getTextContent());
OrderType.add(electricityorderline.getElementsByTagName("type").item(0).getTextContent());
List<String> AgentTypeFiltered = Lists.newArrayList(Sets.newHashSet(AgentType));
listOfLists.add(Lists.newArrayList(AgentTypeFiltered));
List<String> RoleTypeFiltered = Lists.newArrayList(Sets.newHashSet(RoleType));
listOfLists.add(Lists.newArrayList(RoleTypeFiltered));
List<String> OrderTypeFiltered = Lists.newArrayList(Sets.newHashSet(OrderType));
listOfLists.add(Lists.newArrayList(OrderTypeFiltered));
return listOfLists;
【问题讨论】:
您可能需要使用一些 xml 解析器库。Dom Parser、SAX 解析器、Stax 解析器是其中的一些。 是的,我知道,问题是如何获取元素,首先,我正在解析 xml 文件: .... dom = db.parse("file.xml")... .;后来我在解析文档,但我使用的是:NodeList nl = docEle.getElementsByTagName("Agent"); 你用什么来解析 XML?我会用你正在使用的任何东西写一个答案。 我不明白这有什么难的。为什么你不能遍历 dom 并在你下降得更深时记住父元素?当您找到一个考虑采用 OO(面向对象)方法,而不是为每种类型使用 ArrayList
。您会注意到这种方法的许多优点,例如(很多)更少的变量和代码行。举个例子:
Driver.java:
public class Driver
public static final String XML_FILE_PATH = "zin/zin.xml";
/**
* Entry point of the program.
*/
public static void main(String[] args) throws IOException, JDOMException
File xmlFile = new File(XML_FILE_PATH);
// the SAXBuilder is the easiest way to create the JDOM2 objects
SAXBuilder jdomBuilder = new SAXBuilder();
// jdomDocument is the JDOM2 Object
Document jdomDocument = jdomBuilder.build(xmlFile);
Element root = jdomDocument.getRootElement();
Element negotiation = root.getChild("negotiation");
// get the list of children agent elements
List<Element> xmlAgents = negotiation.getChildren("agent");
// list for holding the agent objects parsed from the XML file
List<Agent> agents = new ArrayList<Agent>();
// iterate over the agent nodes from the XML file and create
// agent objects to represent them
for (Element currentAgent : xmlAgents)
Agent newAgent = new Agent();
// set the new agent's 'AgentType' before descending into
// the children XML nodes
newAgent.setAgentType(currentAgent.getChildText("type"));
// recursively finish the new agent
descend(currentAgent, newAgent);
// add the new agent to the ArrayList of agents
agents.add(newAgent);
// print agent data to output
for(Agent agent : agents)
System.out.println(agent);
/**
* Note: Agent is not immutable, this method alters the members
* of the passed in Agent object.
*
* Recursive method to fill in the rest of a passed in Agent object.
*
* @param ele - an XML element to descend.
* @param agent - the Agent object to finish filling.
*/
public static void descend(Element ele, Agent agent)
for (Element e : ele.getChildren())
switch (e.getName())
case "electricityPlan":
agent.setPlanType(e.getChildText("type"));
break;
case "role":
agent.setRoleType(e.getChildText("type"));
break;
case "electricityOrder":
agent.setOrderType(e.getChildText("type"));
break;
default:
break;
descend(e, agent);
Agent.java
public class Agent
private String auctionType;
private String agentType;
private String planType;
private String roleType;
private String orderType;
public Agent()
auctionType = "";
agentType = "";
planType = "";
roleType = "";
orderType = "";
@Override
public String toString()
String str = "Agent\r\n";
str += " AuctionType: " + getAuctionType() + "\r\n";
str += " AgentType: " + getAgentType() + "\r\n";
str += " RoleType: " + getRoleType() + "\r\n";
str += " PlanType: " + getPlanType() + "\r\n";
str += " OrderType: " + getOrderType();
return str;
public String getAuctionType()
return auctionType;
public void setAuctionType(String auctionType)
this.auctionType = auctionType;
public String getAgentType()
return agentType;
public void setAgentType(String agentType)
this.agentType = agentType;
public String getPlanType()
return planType;
public void setPlanType(String planType)
this.planType = planType;
public String getRoleType()
return roleType;
public void setRoleType(String roleType)
this.roleType = roleType;
public String getOrderType()
return orderType;
public void setOrderType(String orderType)
this.orderType = orderType;
Running Driver 的main
方法输出如下:
Agent
AuctionType:
AgentType: UtilityCompany
RoleType: Seller
PlanType: PlanUtility
OrderType: SalesOrder
Agent
AuctionType:
AgentType: LargeCustomer
RoleType: Buyer
PlanType: LargecPlan
OrderType: PurchaseOrder
当然上面的代码只是一个例子。 Agent
类不一定需要所有这些访问器和修改器,或者根本不需要,它的成员都可以是公共的或受保护的。关键是您可以拥有一个代理列表,每个代理对象包含每种类型的成员,而不是每个类型的列表,每个索引代表不同的代理。
【讨论】:
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