获取不同级别的所有同名节点

Posted

技术标签:

【中文标题】获取不同级别的所有同名节点【英文标题】:Get all nodes with the same name in different levels 【发布时间】:2017-03-07 19:16:25 【问题描述】:

以下是我的 XML 文件:

<scenario>
  <negotiation>
    <type>auction</type>

    <agent>
      <type>UtilityCompany</type>
      <electricityPlan>
        <type>PlanUtility</type>
        <offeredEnergy>10</offeredEnergy>
        <duration>20</duration>
        <price>10</price>
        <role>
          <type>Seller</type>
        </role>
        <electricityOrder>
          <type>SalesOrder</type>
        </electricityOrder>
      </electricityPlan>
    </agent>

    <agent>
      <type>LargeCustomer</type>
      <electricityPlan>
        <type>LargecPlan</type>
        <requestedEnergy>100</requestedEnergy>
        <duration>20</duration>
        <price>10</price>
        <role>
          <type>Buyer</type>
        </role>
        <electricityOrder>
          <type>PurchaseOrder</type>
        </electricityOrder>
      </electricityPlan>
    </agent>

  </negotiation>
</scenario>

我需要知道如何将&lt;type&gt;&lt;/type&gt; 标签内的所有值附加到ArrayList

类似于以下内容:

Agent[0] = UtilityCompany
Agent[1] = LargeCustomer

electricityPlan[0] = PlanUtility
electricityPlan[1] = LargecPlan

role[0] = Seller
role[1] = Buyer

有人可以提供一些见解吗?

更新信息

目前,我有这个:

public static void main(String[] args) 抛出 ParserConfigurationException、SAXException、IOException、XPathExpressionException

    File fXmlFile = new File("scenario.xml");
    DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
    DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
    Document doc = dBuilder.parse(fXmlFile);

    NodeList nodes = doc.getElementsByTagName("negotiation");
    Element element = (Element) nodes.item(0);
    NodeList negotiationList = element.getElementsByTagName("agent");
    for (int i = 0; i < negotiationList.getLength(); i++) 

    Element negotiationElement = (Element) negotiationList.item(i);


NodeList agent = negotiationElement.getElementsByTagName("type");
System.out.println(agent.item(0).getFirstChild().getTextContent());

NodeList role = negotiationElement.getElementsByTagName("role");
Element roleline = (Element) role.item(0);
System.out.println(roleline.getElementsByTagName("type").item(0).getTextContent());



Output

UtilityCompany
Seller
LargeCustomer
Buyer
LargeCustomer
Buyer

大客户 买家

但我不知道如何从

中获取值
      1.         <type>auction</type>

      2. <type>PlanUtility</type>  from ElectricityPlan tag.

最后我找到了解决方案:

此代码用于获取请求的节点

我有一个解决方案:

 public class ReadingXML 

static List<String> AuctionType = new ArrayList<String>();
static List<String> AgentType = new ArrayList<String>();
static List<String> PlanType = new ArrayList<String>();
static List<String> RoleType = new ArrayList<String>();
static List<String> OrderType = new ArrayList<String>();
static NodeList auction ;

 public List<List<String>> ReadingXML(String fileLocation) throws      
 ParserConfigurationException, SAXException, IOException 

//File fXmlFile = new File("C:....location\\scenario.xml");

File fXmlFile = new File(fileLocation);
DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
Document doc = dBuilder.parse(fXmlFile);
List<List<String>> listOfLists = Lists.newArrayList();

    NodeList nodesScenario = doc.getElementsByTagName("scenario");
    Element element0 = (Element) nodesScenario.item(0);
    NodeList scenarioList = element0.getElementsByTagName("negotiation");

   for (int j = 0; j < scenarioList.getLength(); j++) 
     
       Element scenarioElement = (Element) scenarioList.item(j);
       auction = scenarioElement.getElementsByTagName("type");
       System.out.println(auction.item(0).getFirstChild().getTextContent());
       AuctionType.add(auction.item(0).getFirstChild().getTextContent()); 
     
    List<String> AuctionTypeFiltered = Lists.newArrayList(Sets.newHashSet(AuctionType));
    listOfLists.add(Lists.newArrayList(AuctionTypeFiltered));

NodeList nodesNegotiation = doc.getElementsByTagName("negotiation");
Element element = (Element) nodesNegotiation.item(0);
NodeList negotiationList = element.getElementsByTagName("agent"); 

for (int i = 0; i < negotiationList.getLength(); i++) 
 
   Element negotiationElement = (Element) negotiationList.item(i);
   NodeList agent = negotiationElement.getElementsByTagName("type");
   System.out.println(agent.item(0).getFirstChild().getTextContent());
   AgentType.add(agent.item(0).getFirstChild().getTextContent());

   NodeList nodesElectricityPlan = doc.getElementsByTagName("electricityPlan");
   Element element1 = (Element) nodesElectricityPlan.item(0);
   NodeList ElectricityPlanList = element1.getElementsByTagName("plan");

   for (int j = 0; j < ElectricityPlanList.getLength(); j++) 
    
      Element electricityPlanElement = (Element) ElectricityPlanList.item(j);
      NodeList plan = electricityPlanElement.getElementsByTagName("type");
      System.out.println(plan.item(0).getFirstChild().getTextContent());
      PlanType.add(plan.item(0).getFirstChild().getTextContent());
     
    List<String> PlanTypeFiltered = Lists.newArrayList(Sets.newHashSet(PlanType));
    listOfLists.add(Lists.newArrayList(PlanTypeFiltered));

    NodeList role = negotiationElement.getElementsByTagName("role");
    Element roleline = (Element) role.item(0);
    System.out.println(roleline.getElementsByTagName("type").item(0).getTextContent());
    RoleType.add(roleline.getElementsByTagName("type").item(0).getTextContent());

    NodeList electricityorder = negotiationElement.getElementsByTagName("electricityOrder");
    Element electricityorderline = (Element) electricityorder.item(0);
    System.out.println(electricityorderline.getElementsByTagName("type").item(0).getTextContent());
    OrderType.add(electricityorderline.getElementsByTagName("type").item(0).getTextContent());
  
   List<String> AgentTypeFiltered = Lists.newArrayList(Sets.newHashSet(AgentType));
   listOfLists.add(Lists.newArrayList(AgentTypeFiltered));

   List<String> RoleTypeFiltered = Lists.newArrayList(Sets.newHashSet(RoleType));
   listOfLists.add(Lists.newArrayList(RoleTypeFiltered));

   List<String> OrderTypeFiltered = Lists.newArrayList(Sets.newHashSet(OrderType));
   listOfLists.add(Lists.newArrayList(OrderTypeFiltered));

    return listOfLists;
    



   

【问题讨论】:

您可能需要使用一些 xml 解析器库。Dom Parser、SAX 解析器、Stax 解析器是其中的一些。 是的,我知道,问题是如何获取元素,首先,我正在解析 xml 文件: .... dom = db.parse("file.xml")... .;后来我在解析文档,但我使用的是:NodeList nl = docEle.getElementsByTagName("Agent"); 你用什么来解析 XML?我会用你正在使用的任何东西写一个答案。 我不明白这有什么难的。为什么你不能遍历 dom 并在你下降得更深时记住父元素?当您找到一个 时,您将保存的父级添加到 arrayList...? @Calicoder 对我来说困难的部分是获得 auctionPlanUtility。谢谢 【参考方案1】:

考虑采用 OO(面向对象)方法,而不是为每种类型使用 ArrayList。您会注意到这种方法的许多优点,例如(很多)更少的变量和代码行。举个例子:

Driver.java:

public class Driver 
    public static final String XML_FILE_PATH = "zin/zin.xml";

    /**
     * Entry point of the program.
     */
    public static void main(String[] args) throws IOException, JDOMException 
        File xmlFile = new File(XML_FILE_PATH);
        // the SAXBuilder is the easiest way to create the JDOM2 objects
        SAXBuilder jdomBuilder = new SAXBuilder();

        // jdomDocument is the JDOM2 Object
        Document jdomDocument = jdomBuilder.build(xmlFile);
        Element root = jdomDocument.getRootElement();
        Element negotiation = root.getChild("negotiation");

        // get the list of children agent elements
        List<Element> xmlAgents = negotiation.getChildren("agent");
        // list for holding the agent objects parsed from the XML file
        List<Agent> agents = new ArrayList<Agent>();

        // iterate over the agent nodes from the XML file and create
        // agent objects to represent them
        for (Element currentAgent : xmlAgents) 
            Agent newAgent = new Agent();
            // set the new agent's 'AgentType' before descending into
            // the children XML nodes
            newAgent.setAgentType(currentAgent.getChildText("type"));

            // recursively finish the new agent
            descend(currentAgent, newAgent);

            // add the new agent to the ArrayList of agents
            agents.add(newAgent);
        

        // print agent data to output
        for(Agent agent : agents) 
            System.out.println(agent);
        
    

    /**
     * Note: Agent is not immutable, this method alters the members
     * of the passed in Agent object.
     * 
     * Recursive method to fill in the rest of a passed in Agent object.
     * 
     * @param ele - an XML element to descend.
     * @param agent - the Agent object to finish filling.
     */
    public static void descend(Element ele, Agent agent) 
        for (Element e : ele.getChildren()) 
            switch (e.getName()) 
                case "electricityPlan":
                    agent.setPlanType(e.getChildText("type"));
                    break;
                case "role":
                    agent.setRoleType(e.getChildText("type"));
                    break;
                case "electricityOrder":
                    agent.setOrderType(e.getChildText("type"));
                    break;
                default:
                    break;
            

            descend(e, agent);
        
    

Agent.java

public class Agent 
    private String auctionType;
    private String agentType;
    private String planType;
    private String roleType;
    private String orderType;

    public Agent() 
        auctionType = "";
        agentType = "";
        planType = "";
        roleType = "";
        orderType = "";
    

    @Override
    public String toString() 
        String str = "Agent\r\n";

        str += "  AuctionType: " + getAuctionType() + "\r\n";
        str += "    AgentType: " + getAgentType() + "\r\n";
        str += "     RoleType: " + getRoleType() + "\r\n";
        str += "     PlanType: " + getPlanType() + "\r\n";
        str += "    OrderType: " + getOrderType();

        return str;
    

    public String getAuctionType() 
        return auctionType;
    

    public void setAuctionType(String auctionType) 
        this.auctionType = auctionType;
    

    public String getAgentType() 
        return agentType;
    

    public void setAgentType(String agentType) 
        this.agentType = agentType;
    

    public String getPlanType() 
        return planType;
    

    public void setPlanType(String planType) 
        this.planType = planType;
    

    public String getRoleType() 
        return roleType;
    

    public void setRoleType(String roleType) 
        this.roleType = roleType;
    

    public String getOrderType() 
        return orderType;
    

    public void setOrderType(String orderType) 
        this.orderType = orderType;
    


Running Driver 的main 方法输出如下:

Agent
  AuctionType: 
    AgentType: UtilityCompany
     RoleType: Seller
     PlanType: PlanUtility
    OrderType: SalesOrder
Agent
  AuctionType: 
    AgentType: LargeCustomer
     RoleType: Buyer
     PlanType: LargecPlan
    OrderType: PurchaseOrder

当然上面的代码只是一个例子。 Agent 类不一定需要所有这些访问器和修改器,或者根本不需要,它的成员都可以是公共的或受保护的。关键是您可以拥有一个代理列表,每个代理对象包含每种类型的成员,而不是每个类型的列表,每个索引代表不同的代理。

【讨论】:

以上是关于获取不同级别的所有同名节点的主要内容,如果未能解决你的问题,请参考以下文章

Qt通过Doc模式读取XML并设计一个增删改查方便的一个操作类

使用 XML 获取所有同名元素的内容?

如何从PHP中的URL获取多个同名参数并将所有记录插入表中

转载 Easyui Tree方法扩展 - getLevel(获取节点级别)

获取有关“间接级别不同”的错误

java通过反射获取加了某个注解的所有的类