简化 java 正则表达式代码以验证密码

Posted 2023-02-24

【中文标题】简化 java 正则表达式代码以验证密码

【英文标题】：Simplify java regex code to validate passwords

【发布时间】：2021-11-08 11:08:54

【问题描述】：

我想告诉用户他需要什么，这样他的密码才有效，当密码不符合要求时，jlabels 将颜色变为红色，当满足时变为黑色。我可以做我想做的最短的方法，但它会存在其他吗？我附上代码和照片

    private void JB_MostrarActionPerformed(java.awt.event.ActionEvent evt)                                            

    String password = "";

    password = jPasswordField_pass.getText().trim();

    final String regex = "^(?:(?=.*\\d)(?=.*[a-z])(?=.*[A-Z])(?=.*[@#$%^&+=.,]).*)[^\\s]8,$";

    if (password.equals("")) 
        jl_Error.setText("Please enter your Password.");
        jl_Error.setForeground(Color.red);

     else if (password.matches(regex) == false) 

        jLabel_infopass.setText("Your password must be between 8 and 64 characters long. It must contain at least three (3) of the below:");
        jLabel_infopass.setForeground(Color.red);

        if (Pattern.matches("(?=.*\\d).*", password) == false) 
            jLabel_infopass3.setText("numbers (0-9)");
            jLabel_infopass3.setForeground(Color.red);
         else 
            jLabel_infopass3.setText("numbers (0-9)");
            jLabel_infopass3.setForeground(Color.black);
        
        if (Pattern.matches("(?=.*[a-z]).*", password) == false) 
            jLabel_infopass2.setText("lowercase (a-z)");
            jLabel_infopass2.setForeground(Color.red);
         else 
            jLabel_infopass2.setText("lowercase (a-z)");
            jLabel_infopass2.setForeground(Color.black);
        
        if (Pattern.matches("(?=.*[A-Z]).*", password) == false) 
            jLabel_infopass1.setText("uppercase (A-Z)");
            jLabel_infopass1.setForeground(Color.red);
         else 
            jLabel_infopass1.setText("uppercase (A-Z)");
            jLabel_infopass1.setForeground(Color.black);
        
        if (Pattern.matches("(?=.*[@#$%^&+!.,]).*", password) == false) 
            jLabel_infopass4.setText("symbols (e.g. #, $, !, @, ^, &, *, etc)");
            jLabel_infopass4.setForeground(Color.red);
         else 
            jLabel_infopass4.setText("symbols (e.g. #, $, !, @, ^, &, *, etc)");
            jLabel_infopass4.setForeground(Color.black);
        

     else 
        jLabel_infopass.setText("Your password must be between 8 and 64 characters long. It must contain at least three (3) of the below:");
        jLabel_infopass.setForeground(Color.black);
        JOptionPane.showMessageDialog(null, password);
    
 

【问题讨论】：

扔掉四台显示器，把规则告诉他一个。然后只需使用一个匹配或不匹配的正则表达式。这是矫枉过正。

【参考方案1】：

使用简单的一行来告知用户密码限制。单行显示“您的密码长度必须为 8-64 个字符，并且至少包含三个数字或特殊字符”

使用 Pattern 类来验证您的密码。

import java.util.regex.*;  

// this will check for 8-64 character with at least 3 numbers or special characters
String passwordRegex = "(?=.*[a-z])(?=.*[A-Z])(?=.*\d)(?=.*[#$@!%&*?])[A-Za-z\d#$@!%&*?]8,64[\d#$@!%&*?]3,";

Pattern pattern = Pattern.compile(passwordRegex);

// this is inside your password check function
Matcher match = pattern.matcher(passwordCheck);

if(match.matches())
// OK
 else 
// show warning message