如何使用 pyplot.bar 仅绘制正误差条？

Posted 2023-02-23

【中文标题】如何使用 pyplot.bar 仅绘制正误差条？

【英文标题】：How do I plot just the positive error bar with pyplot.bar?

【发布时间】：2012-10-30 01:16:30

【问题描述】：

我正在尝试绘制 4 个带有正误差线的平均值和图中的最大值。

means   = [26.82,26.4,61.17,61.55]         # Mean Data 
stds    = [4.59,4.39,4.37,4.38]            # Standard deviation Data
peakval = ['26.82','26.4','61.17','61.55'] # String array of means

ind = np.arange(len(means))
width = 0.35
colours = ['red','blue','green','yellow']

pyplot.figure()
pyplot.title('Average Age')
for i in range(len(means)):
    pyplot.bar(ind[i],means[i],width,color=colours[i],align='center',yerr=stds[i],ecolor='k')
pyplot.ylabel('Age (years)')
pyplot.xticks(ind,('Young Male','Young Female','Elderly Male','Elderly Female'))

def autolabel(bars,peakval):
    for ii,bar in enumerate(bars):
        height = bars[ii]
        pyplot.text(ind[ii], height-5, '%s'% (peakval[ii]), ha='center', va='bottom')
autolabel(means,peakval)    

但是我不知道如何仅绘制正误差条。 所以我最终得到了这样的图表：

任何建议将不胜感激。

【参考方案1】：

如果我理解正确，您可以这样做：

import numpy as np
from matplotlib import pyplot

means   = [26.82,26.4,61.17,61.55]           # Mean Data 
stds    = [(0,0,0,0), [4.59,4.39,4.37,4.38]] # Standard deviation Data
peakval = ['26.82','26.4','61.17','61.55']   # String array of means

ind = np.arange(len(means))
width = 0.35
colours = ['red','blue','green','yellow']

pyplot.figure()
pyplot.title('Average Age')
pyplot.bar(ind, means, width, color=colours, align='center', yerr=stds, ecolor='k')
pyplot.ylabel('Age (years)')
pyplot.xticks(ind,('Young Male','Young Female','Elderly Male','Elderly Female'))

def autolabel(bars,peakval):
    for ii,bar in enumerate(bars):
        height = bars[ii]
        pyplot.text(ind[ii], height-5, '%s'% (peakval[ii]), ha='center', va='bottom')
autolabel(means,peakval) 
pyplot.show()

结果：

之所以有效，是因为您可以将2xN 列表作为yerr 传递，代表正负“偏移量”，请参阅documentation。