扁平化仅包含一个 dict 的列表

Posted 2023-02-14

【中文标题】扁平化仅包含一个 dict 的列表

【英文标题】：Flat a list of containing only one dict

【发布时间】：2022-01-17 15:58:07

【问题描述】：

我有一个字典，其中包含一个列表product，它只包含一个字典：

d = 
    "thickness": 90.0,
    "mass_surf": 37.8,
    "res_therm": 0.75,
    "codename": "codename1",
    "category": "category1",
    "sub_categories": [
        "sub_categories1"
    ],
    "secondary_targets": [
        "secondary_targets1",
        "secondary_targets2",
        "secondary_targets3"
    ],
    "product": [
        
            "codename": "codename1",
            "purpose": "purpose1",
            "category": "category1",
            "material": "material1"
        
    ]

我想将 dict 的product 列表变平以获得这个：

d = 
    "thickness": 90.0,
    "mass_surf": 37.8,
    "res_therm": 0.75,
    "codename": "codename1",
    "category": "category1",
    "sub_categories": [
        "sub_categories1"
    ],
    "secondary_targets": [
        "secondary_targets1",
        "secondary_targets2",
        "secondary_targets3"
    ],
    "product.codename": "codename1",
    "product.purpose": "purpose 1",
    "product.purpose": "purpose1",
    "product.category": "category1",
    "product.material": "material1"

我该怎么做？

product 列表将始终只包含一项

【参考方案1】：

您可以展平内部字典并将其更新回原始字典。 例如，

product = d.pop("product")[0]
flattened = f"product.key": value for key, value in product.items()
d.update(flattened)

这应该可以解决问题。

【讨论】：

哦，确实这是一个非常聪明的方法，谢谢@Kris！