如何让我的网格填充所有单元格？

Posted 2023-02-23

【中文标题】如何让我的网格填充所有单元格？

【英文标题】：How can I make my grid populate all cells?

【发布时间】：2022-01-10 09:31:59

【问题描述】：

我正在使用 for 循环随机填充一个 8x8 网格，其中包含两个不同的按钮。我有一组按钮实例，出于某种原因，它只给我每个按钮一个，而不用任何东西填充网格的其余部分。有什么建议吗？ 我只包含了代码的 buildPanel 块，但我确实有单独的按钮类和 Game 类。我还完成了其余的代码。它还没有完全满足我的需要并且需要清理，但如果它可能有助于解决这个问题，我可以发布它。如果不写更多细节，我无法在问题中发布比这更多的代码，但我认为这是一个非常简单的问题。

    private void buildPanel()
            
        // Create labels to display the 
        treasuresLeftLabel = new JLabel("Treasures left: ");
        treasuresFoundLabel = new JLabel("Treasures found: ");        
        triesLeftLabel = new JLabel("Tries left: ");
        
        // Create text fields for each label
        treasuresLeftTextField = new JTextField(2);
        treasuresLeftTextField.setEditable(false);
        treasuresLeftTextField.setText(String.valueOf(20-game.getTreasuresFound()));
        treasuresFoundTextField = new JTextField(2);
        treasuresFoundTextField.setEditable(false);
        treasuresFoundTextField.setText(String.valueOf(game.getTreasuresFound()));
        triesLeftTextField = new JTextField(2);
        triesLeftTextField.setEditable(false);
        triesLeftTextField.setText(String.valueOf(game.getTriesLeft()));
        
        emptyButton = new EmptyButton();
        emptyButton.addActionListener(new emptyButtonListener());
        treasureButton = new TreasureButton();
        treasureButton.addActionListener(new treasureButtonListener());

        // new JPanel object referenced by panel
        panel = new JPanel();
        panel.setLayout(new BorderLayout());
        panel.add(new JLabel("Treasure Hunt", JLabel.CENTER), BorderLayout.NORTH);

        statsPanel = new JPanel();
        statsPanel.setLayout(new GridLayout(3, 2));
        statsPanel.add(treasuresLeftLabel);
        statsPanel.add(treasuresLeftTextField);
        statsPanel.add(treasuresFoundLabel);
        statsPanel.add(treasuresFoundTextField);
        statsPanel.add(triesLeftLabel);
        statsPanel.add(triesLeftTextField);
    
        panel.add(statsPanel, BorderLayout.WEST);
        
        JButton[] buttons = new JButton[62];
        for (int index = 0; index < 62; index++)
        
            if (index < 20)
            
                buttons[index] = treasureButton;
            
            else
            
                buttons[index] = emptyButton;
            
        
        gameGridPanel = new JPanel();
        gameGridPanel.setLayout(new GridLayout(8, 8));
        
        // Generate a random number between 0 and 61
        int randomNumber = new Random().nextInt(62);  
        for (int count = 0; count < 62; count++)
           
            if (buttons[randomNumber] != null)
            
                gameGridPanel.add(buttons[randomNumber]);
                randomNumber = new Random().nextInt(62);  
            
            else
            
                randomNumber = new Random().nextInt(62);  
            
        
        
        panel.add(gameGridPanel, BorderLayout.CENTER);
    

【参考方案1】：

每个按钮只给我一个

因为每个按钮只有一个实例：

for (int index = 0; index < 62; index++)

    if (index < 20)
    
        buttons[index] = treasureButton; // single instance
    
    else
    
        buttons[index] = emptyButton; // single instance
    

添加到数组时需要创建一个新实例。

for (int index = 0; index < 62; index++)

    if (index < 20)
    
        //buttons[index] = treasureButton;
        buttons[index] = new TreasureButton();            
    
    else
    
        //buttons[index] = emptyButton;
        buttons[index] = new EmptyButton();
    

还有一种更简单的随机化按钮的方法是：

将按钮添加到ArrayList 使用Collections.shuffle(...) 方法随机化按钮的顺序 遍历ArrayList 并将每个按钮添加到网格中