PayPal REST API 获取 react-native 中的 access_token，“AUTHENTICATION_FAILURE”

Posted 2023-02-22

【中文标题】PayPal REST API 获取 react-native 中的 access_token，“AUTHENTICATION_FAILURE”

【英文标题】：PayPal REST API fetch for access_token in react-native, "AUTHENTICATION_FAILURE"

【发布时间】：2021-05-24 16:29:29

【问题描述】：

我正在尝试通过https://medium.com/zestgeek/paypal-integration-in-react-native-9d447df4fce1 链接将 PayPal 集成到我的 react-native 应用程序中。使用邮递员我得到了响应，但是使用我的代码却给出了这个错误：

“链接”：[“href”：“https://developer.paypal.com/docs/api/overview/#error”，“rel”：“information_link”]，“消息”：“由于身份验证凭据无效或缺少授权标头，身份验证失败。", "name": "AUTHENTICATION_FAILURE"

预期响应（使用 Postman - 成功案例）

    "scope": "https://uri.paypal.com/services/invoicing https://uri.paypal.com/services/vault/payment-tokens/read https://uri.paypal.com/services/disputes/read-buyer https://uri.paypal.com/services/payments/realtimepayment https://uri.paypal.com/services/disputes/update-seller https://uri.paypal.com/services/payments/payment/authcapture openid https://uri.paypal.com/services/disputes/read-seller Braintree:Vault https://uri.paypal.com/services/payments/refund https://api.paypal.com/v1/vault/credit-card https://api.paypal.com/v1/payments/.* https://uri.paypal.com/payments/payouts https://uri.paypal.com/services/vault/payment-tokens/readwrite https://api.paypal.com/v1/vault/credit-card/.* https://uri.paypal.com/services/subscriptions https://uri.paypal.com/services/applications/webhooks",
    "access_token": "A21AAL0lvt6p5QhxL5p6KusbbwMNu8o_DWDyNHHWAc3KuOBK7MO4YY3s_1CTMiY1BCAZwQ-dX7MzixsxY5StFfEFrSI2pamNg",
    "token_type": "Bearer",
    "app_id": "APP-80W284485P519543T",
    "expires_in": 32400,
    "nonce": "2021-02-22T11:42:28ZIt4HFB53zPnqZtMo8CeBA17Aj1MKaRQDVAVRE9VqUJg"

我的错误代码

    fetch('https://api.sandbox.paypal.com/v1/oauth2/token', grant_type: 'client_credentials' ,
     
        method: 'POST',
        headers:  
             'Accept': 'application/json', 
             'Accept-Language': 'en_US',
             'Content-Type': 'application/x-www-form-urlencoded',
             'Authorization': 'Basic QVVydEp4Y0hmTVVsRGpIZ1YyRkhNT1Vuek1rVWV1ODZfa203aDY3dUVIekg1YjVSTjdWby1xOEFZUHRjZHo3SWFpb2M0NnhXMEg5SlFabVQ6RU1iYkotWXFRTFQ2bGl1UHRKVVJxMnBBZ2g5V3VVVERLbVYzNTVfVkllQURzdDBCTWxuVU5LaUhWTEs3aXRDeVpGWHJFUU9leDlwOTNXTzg='
        
    
      ) .then(response => response.json())
      .then(async (data) => 
        console.log(data)
       
    )
    .catch(function (error) 
        let edata = error.message;
        console.log('Error:', edata)
    
    )

【参考方案1】：

错误的获取语法（为什么要单独的对象参数？）以及在作为主体的对象部分中的 URL 编码表单数据的错误语法。

因此，没有为您的调用设置请求标头和表单发布数据（在正文中）——它评估并作为对端点的空白请求运行，因此出现错误。

这是怎么做的

fetch('https://api.sandbox.paypal.com/v1/oauth2/token',  
    method: 'POST',
    headers:  
         'Accept': 'application/json', 
         'Accept-Language': 'en_US',
         'Content-Type': 'application/x-www-form-urlencoded',
         'Authorization': 'Basic ' + btoa('YOUR_CLIENTID:YOUR_SECRET')
    ,
    body: 'grant_type=client_credentials'

).then(response => response.json())
  .then(async (data) => 
    console.log(data)
).catch(function (error) 
    let edata = error.message;
    console.log('Error:', edata)