在 Android 中发送 POST 数据
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【中文标题】在 Android 中发送 POST 数据【英文标题】：Sending POST data in Android 【发布时间】：2011-02-25 16:19:28 【问题描述】：我对 php、javascript 和许多其他脚本语言有经验，但对 Java 或 android 没有太多经验。
我正在寻找一种将 POST 数据发送到 PHP 脚本并显示结果的方法。
【问题讨论】：
【参考方案1】：以下方法适用于最新的 Android 库并使用 okhttp。
OkHttpClient client = new OkHttpClient();
RequestBody formBody = new FormBody.Builder()
.add("key1", "value1")
.add("key2", "value2") //optional
.add("key3", "value3") //optional
.add("key4", "value4") //optional
.build();
Request request = new Request.Builder()
.url("http://.....") //URL
.post(formBody)
.build();
client.newCall(request).enqueue(new Callback()
@Override
public void onFailure(@NonNull Call call, @NonNull IOException e)
e.getStackTrace();
@Override
public void onResponse(@NonNull Call call, @NonNull Response response) throws IOException
if(response.isSuccessful())
ResponseBody responseBody = response.body();
Log.e("TAG_", responseBody.string());
【讨论】：
【参考方案2】：您可以使用以下命令向URL 发送HTTP-POST 请求并接收响应。我总是用这个：
try
AsyncHttpClient client = new AsyncHttpClient();
// Http Request Params Object
RequestParams params = new RequestParams();
String u = "B2mGaME";
String au = "gamewrapperB2M";
// String mob = "880xxxxxxxxxx";
params.put("usr", u.toString());
params.put("aut", au.toString());
params.put("uph", MobileNo.toString());
// params.put("uph", mob.toString());
client.post("http://196.6.13.01:88/ws/game_wrapper_reg_check.php", params, new AsyncHttpResponseHandler()
@Override
public void onSuccess(String response)
playStatus = response;
//////Get your Response/////
Log.i(getClass().getSimpleName(), "Response SP Status. " + playStatus);
@Override
public void onFailure(Throwable throwable)
super.onFailure(throwable);
);
catch (Exception e)
e.printStackTrace();
您还需要在 libs 文件夹中添加以下 Jar 文件
android-async-http-1.3.1.jar
最后，我编辑了你的 build.gradle：
dependencies
compile files('libs/<android-async-http-1.3.1.jar>')
在最后重建你的项目。
【讨论】：
【参考方案3】：注意（2020 年 10 月）：以下答案中使用的 AsyncTask 在 Android API 级别 30 中已被弃用。请参阅 Official documentation 或 this blog post 了解更多更新示例
更新（2017 年 6 月）答案，适用于 Android 6.0+。感谢 @Rohit Suthar、@Tamis Bolvari 和 @sudhiskr 的 cmets。
public class CallAPI extends AsyncTask<String, String, String>
public CallAPI()
//set context variables if required
@Override
protected void onPreExecute()
super.onPreExecute();
@Override
protected String doInBackground(String... params)
String urlString = params[0]; // URL to call
String data = params[1]; //data to post
OutputStream out = null;
try
URL url = new URL(urlString);
HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection();
out = new BufferedOutputStream(urlConnection.getOutputStream());
BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(out, "UTF-8"));
writer.write(data);
writer.flush();
writer.close();
out.close();
urlConnection.connect();
catch (Exception e)
System.out.println(e.getMessage());
参考资料：
https://developer.android.com/reference/java/net/HttpURLConnection.html How to add parameters to HttpURLConnection using POST using NameValuePair原始答案（2010 年 5 月）
注意：此解决方案已过时。它仅适用于最高 5.1 的 Android 设备。 Android 6.0 及更高版本不包括此答案中使用的 Apache http 客户端。
Apache Commons 的 Http 客户端是可行的方法。它已经包含在android中。下面是一个简单的例子，说明如何使用它进行 HTTP Post。
public void postData()
// Create a new HttpClient and Post Header
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://www.yoursite.com/script.php");
try
// Add your data
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
nameValuePairs.add(new BasicNameValuePair("id", "12345"));
nameValuePairs.add(new BasicNameValuePair("stringdata", "Hi"));
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
// Execute HTTP Post Request
HttpResponse response = httpclient.execute(httppost);
catch (ClientProtocolException e)
// TODO Auto-generated catch block
catch (IOException e)
// TODO Auto-generated catch block
【讨论】：
httppost.setEntity(new UrlEncodedFormEntity(params, "UTF-8")); for UTF-8 编码。
“HttpClient”、“HttpPost”、“HttpResponse”、“HttpEntity”、“EntityUtils”、“NameValuePair”、“BasicNameValuePair”是已弃用。请提出其他解决方案。
另外DefaultHttpClient 已被弃用。
这个 - 更新 - 答案不会发布任何内容。是吗？
这确实NOT 显示POST 示例。编辑6.0 答案会很好。这是经过优化以显示为第一个结果的搜索引擎，这有点误导。【参考方案4】：
对于 Android = > 5
org.apache.http 类和 AndroidHttpClient 类已在 Android 5.1 中弃用。这些类不再维护，您应该尽快将使用这些 API 的任何应用代码迁移到 URLConnection 类。
https://developer.android.com/about/versions/android-5.1.html#http
想用 HttpUrlConnection 分享我的代码
public String performPostCall(String requestURL,
HashMap<String, String> postDataParams)
URL url;
String response = "";
try
url = new URL(requestURL);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setReadTimeout(15000);
conn.setConnectTimeout(15000);
conn.setRequestMethod("GET");
conn.setDoInput(true);
conn.setDoOutput(true);
OutputStream os = conn.getOutputStream();
BufferedWriter writer = new BufferedWriter(
new OutputStreamWriter(os, "UTF-8"));
writer.write(getPostDataString(postDataParams));
writer.flush();
writer.close();
os.close();
int responseCode=conn.getResponseCode();
if (responseCode == HttpsURLConnection.HTTP_OK)
String line;
BufferedReader br=new BufferedReader(new InputStreamReader(conn.getInputStream()));
while ((line=br.readLine()) != null)
response+=line;
else
response="";
catch (Exception e)
e.printStackTrace();
return response;
...
private String getPostDataString(HashMap<String, String> params) throws UnsupportedEncodingException
StringBuilder result = new StringBuilder();
boolean first = true;
for(Map.Entry<String, String> entry : params.entrySet())
if (first)
first = false;
else
result.append("&");
result.append(URLEncoder.encode(entry.getKey(), "UTF-8"));
result.append("=");
result.append(URLEncoder.encode(entry.getValue(), "UTF-8"));
return result.toString();
你也可以发布方法：
conn.setRequestMethod("POST");
21/02/2016 更新
对于 json 的 post 请求，请参阅此示例：
public class Empty extends
AsyncTask<Void, Void, Boolean>
String urlString = "http://www.yoursite.com/";
private final String TAG = "post json example";
private Context context;
private int advertisementId;
public Empty(Context contex, int advertisementId)
this.context = contex;
this.advertisementId = advertisementId;
@Override
protected void onPreExecute()
Log.e(TAG, "1 - RequestVoteTask is about to start...");
@Override
protected Boolean doInBackground(Void... params)
boolean status = false;
String response = "";
Log.e(TAG, "2 - pre Request to response...");
try
response = performPostCall(urlString, new HashMap<String, String>()
private static final long serialVersionUID = 1L;
put("Accept", "application/json");
put("Content-Type", "application/json");
);
Log.e(TAG, "3 - give Response...");
Log.e(TAG, "4 " + response.toString());
catch (Exception e)
// displayLoding(false);
Log.e(TAG, "Error ...");
Log.e(TAG, "5 - after Response...");
if (!response.equalsIgnoreCase(""))
try
Log.e(TAG, "6 - response !empty...");
//
JSONObject jRoot = new JSONObject(response);
JSONObject d = jRoot.getJSONObject("d");
int ResultType = d.getInt("ResultType");
Log.e("ResultType", ResultType + "");
if (ResultType == 1)
status = true;
catch (JSONException e)
// displayLoding(false);
// e.printStackTrace();
Log.e(TAG, "Error " + e.getMessage());
finally
else
Log.e(TAG, "6 - response is empty...");
status = false;
return status;
@Override
protected void onPostExecute(Boolean result)
//
Log.e(TAG, "7 - onPostExecute ...");
if (result)
Log.e(TAG, "8 - Update UI ...");
// setUpdateUI(adv);
else
Log.e(TAG, "8 - Finish ...");
// displayLoding(false);
// finish();
public String performPostCall(String requestURL,
HashMap<String, String> postDataParams)
URL url;
String response = "";
try
url = new URL(requestURL);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setReadTimeout(context.getResources().getInteger(
R.integer.maximum_timeout_to_server));
conn.setConnectTimeout(context.getResources().getInteger(
R.integer.maximum_timeout_to_server));
conn.setRequestMethod("POST");
conn.setDoInput(true);
conn.setDoOutput(true);
conn.setRequestProperty("Content-Type", "application/json");
Log.e(TAG, "11 - url : " + requestURL);
/*
* JSON
*/
JSONObject root = new JSONObject();
//
String token = Static.getPrefsToken(context);
root.put("securityInfo", Static.getSecurityInfo(context));
root.put("advertisementId", advertisementId);
Log.e(TAG, "12 - root : " + root.toString());
String str = root.toString();
byte[] outputBytes = str.getBytes("UTF-8");
OutputStream os = conn.getOutputStream();
os.write(outputBytes);
int responseCode = conn.getResponseCode();
Log.e(TAG, "13 - responseCode : " + responseCode);
if (responseCode == HttpsURLConnection.HTTP_OK)
Log.e(TAG, "14 - HTTP_OK");
String line;
BufferedReader br = new BufferedReader(new InputStreamReader(
conn.getInputStream()));
while ((line = br.readLine()) != null)
response += line;
else
Log.e(TAG, "14 - False - HTTP_OK");
response = "";
catch (Exception e)
e.printStackTrace();
return response;
2016 年 8 月 24 日更新
使用一些最好的库，例如：
Retrofit Volley因为：
避免使用 HttpUrlConnection 和 HttpClient在较低的 API 级别（主要在 Gingerbread 和 Froyo 上），HttpUrlConnection 和 HttpClient 远非完美
也避免使用 AsyncTask 他们更快 他们缓存一切自从引入 Honeycomb (API 11) 以来，必须在与主线程不同的单独线程上执行网络操作
【讨论】：
描述你的问题 我有它的工作，但我得到这个错误：NetworkOnMainThreadException 您必须在 AsyncTask 中声明此方法，而不是在主线程中。因为您的活动主线程不支持长达 5 秒的任何进度。你可以用谷歌搜索“NetworkOnMainThreadException”。您必须使用 AsyncTask ，然后在 doInBackground 中使用我的方法。 inperformPostCall() getPostData() 应替换为 getPostDataString()
对于第一种方法，考虑到您序列化数据的方式，您可能还希望添加“application/x-www-form-urlencoded”的内容类型。【参考方案5】：
使用 Square 的开源 okHttp 库。 okHttp 适用于 Android 2.3 及更高版本，并具有 Apache 2.0 license on GitHub。
发送 POST 数据就像在 AsyncTask 中添加以下内容一样简单：
OkHttpClient client = new OkHttpClient();
RequestBody formBody = new FormBody.Builder()
.add("email", emailString) // A sample POST field
.add("comment", commentString) // Another sample POST field
.build();
Request request = new Request.Builder()
.url("https://yourdomain.org/callback.php") // The URL to send the data to
.post(formBody)
.build();
okHttp 在 maven 上也有一个命名空间，因此将其添加到您的 Android Studio 项目中很简单。只需将 compile 'com.squareup.okhttp3:okhttp:3.11.0' 添加到您应用的 build.gradle 即可。
完整代码
将以下内容添加到您的活动中：
public class CallAPI extends AsyncTask<String, String, String>
String emailString;
String commentString;
public CallAPI(String email, String commnt)
emailString = email;
commentString = commnt;
@Override
protected void onPreExecute()
super.onPreExecute();
@Override
protected String doInBackground(String... params)
OkHttpClient client = new OkHttpClient();
RequestBody formBody = new FormBody.Builder()
.add("email", emailString) // A sample POST field
.add("comment", commentString) // Another sample POST field
.build();
Request request = new Request.Builder()
.url("https://yourdomain.org/callback.php") // The URL to send the data to
.post(formBody)
.build();
return "";
@Override
protected void onPostExecute(String s)
super.onPostExecute(s);
然后调用它：
new CallAPI(emailString, commentString).execute();
【讨论】：
【参考方案6】：您可以使用 WebServer 类发布 HttpRequest 并在其侦听器接口中跟踪响应。
WebServer server=new WebServer(getApplicationContext());
server.setOnServerStatusListner(new WebServer.OnServerStatusListner()
@Override
public void onServerResponded(String responce)
@Override
public void onServerRevoked()
);
现在创建一个 DataRack 来绑定你的数据
List<DataRack> racks=new ArrayList<DataRack>();
racks.add(new DataRack("name","Simon"));
racks.add(new DataRack("age","40"));
racks.add(new DataRack("location","Canada"));
现在只需使用该机架发送 POST 请求
server.connectWithPOST(MainActivity.this,"http://sangeethnandakumar.esy.es/PROJECTS/PUBLIC_SERVICE/posttest.php",racks);
为此，您需要包含我的库。文档here
【讨论】：
【参考方案7】：我在 this 视频教程中发现了 this 有用的示例。
连接器类：
package com.tutorials.hp.mysqlinsert;
import java.io.IOException;
import java.net.HttpURLConnection;
import java.net.MalformedURLException;
import java.net.URL;
/**
* Created by Oclemmy on 3/31/2016 for ProgrammingWizards Channel.
*/
public class Connector
/*
1.SHALL HELP US ESTABLISH A CONNECTION TO THE NETWORK
2. WE ARE MAKING A POST REQUEST
*/
public static HttpURLConnection connect(String urlAddress)
try
URL url=new URL(urlAddress);
HttpURLConnection con= (HttpURLConnection) url.openConnection();
//SET PROPERTIES
con.setRequestMethod("POST");
con.setConnectTimeout(20000);
con.setReadTimeout(20000);
con.setDoInput(true);
con.setDoOutput(true);
//RETURN
return con;
catch (MalformedURLException e)
e.printStackTrace();
catch (IOException e)
e.printStackTrace();
return null;
DataPackager 类：
package com.tutorials.hp.mysqlinsert;
import org.json.JSONException;
import org.json.JSONObject;
import java.io.UnsupportedEncodingException;
import java.net.URLEncoder;
import java.util.Iterator;
/**
* Created by Oclemmy on 3/31/2016 for ProgrammingWizards Channel.
* 1.BASICALLY PACKS DATA WE WANNA SEND
*/
public class DataPackager
String name,position,team;
/*
SECTION 1.RECEIVE ALL DATA WE WANNA SEND
*/
public DataPackager(String name, String position, String team)
this.name = name;
this.position = position;
this.team = team;
/*
SECTION 2
1.PACK THEM INTO A JSON OBJECT
2. READ ALL THIS DATA AND ENCODE IT INTO A FROMAT THAT CAN BE SENT VIA NETWORK
*/
public String packData()
JSONObject jo=new JSONObject();
StringBuffer packedData=new StringBuffer();
try
jo.put("Name",name);
jo.put("Position",position);
jo.put("Team",team);
Boolean firstValue=true;
Iterator it=jo.keys();
do
String key=it.next().toString();
String value=jo.get(key).toString();
if(firstValue)
firstValue=false;
else
packedData.append("&");
packedData.append(URLEncoder.encode(key,"UTF-8"));
packedData.append("=");
packedData.append(URLEncoder.encode(value,"UTF-8"));
while (it.hasNext());
return packedData.toString();
catch (JSONException e)
e.printStackTrace();
catch (UnsupportedEncodingException e)
e.printStackTrace();
return null;
发件人类别：
package com.tutorials.hp.mysqlinsert;
import android.app.ProgressDialog;
import android.content.Context;
import android.os.AsyncTask;
import android.widget.EditText;
import android.widget.Toast;
import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.OutputStream;
import java.io.OutputStreamWriter;
import java.net.HttpURLConnection;
/**
* Created by Oclemmy on 3/31/2016 for ProgrammingWizards Channel and Camposha.com.
* 1.SEND DATA FROM EDITTEXT OVER THE NETWORK
* 2.DO IT IN BACKGROUND THREAD
* 3.READ RESPONSE FROM A SERVER
*/
public class Sender extends AsyncTask<Void,Void,String>
Context c;
String urlAddress;
EditText nameTxt,posTxt,teamTxt;
String name,pos,team;
ProgressDialog pd;
/*
1.OUR CONSTRUCTOR
2.RECEIVE CONTEXT,URL ADDRESS AND EDITTEXTS FROM OUR MAINACTIVITY
*/
public Sender(Context c, String urlAddress,EditText...editTexts)
this.c = c;
this.urlAddress = urlAddress;
//INPUT EDITTEXTS
this.nameTxt=editTexts[0];
this.posTxt=editTexts[1];
this.teamTxt=editTexts[2];
//GET TEXTS FROM EDITEXTS
name=nameTxt.getText().toString();
pos=posTxt.getText().toString();
team=teamTxt.getText().toString();
/*
1.SHOW PROGRESS DIALOG WHILE DOWNLOADING DATA
*/
@Override
protected void onPreExecute()
super.onPreExecute();
pd=new ProgressDialog(c);
pd.setTitle("Send");
pd.setMessage("Sending..Please wait");
pd.show();
/*
1.WHERE WE SEND DATA TO NETWORK
2.RETURNS FOR US A STRING
*/
@Override
protected String doInBackground(Void... params)
return this.send();
/*
1. CALLED WHEN JOB IS OVER
2. WE DISMISS OUR PD
3.RECEIVE A STRING FROM DOINBACKGROUND
*/
@Override
protected void onPostExecute(String response)
super.onPostExecute(response);
pd.dismiss();
if(response != null)
//SUCCESS
Toast.makeText(c,response,Toast.LENGTH_LONG).show();
nameTxt.setText("");
posTxt.setText("");
teamTxt.setText("");
else
//NO SUCCESS
Toast.makeText(c,"Unsuccessful "+response,Toast.LENGTH_LONG).show();
/*
SEND DATA OVER THE NETWORK
RECEIVE AND RETURN A RESPONSE
*/
private String send()
//CONNECT
HttpURLConnection con=Connector.connect(urlAddress);
if(con==null)
return null;
try
OutputStream os=con.getOutputStream();
//WRITE
BufferedWriter bw=new BufferedWriter(new OutputStreamWriter(os,"UTF-8"));
bw.write(new DataPackager(name,pos,team).packData());
bw.flush();
//RELEASE RES
bw.close();
os.close();
//HAS IT BEEN SUCCESSFUL?
int responseCode=con.getResponseCode();
if(responseCode==con.HTTP_OK)
//GET EXACT RESPONSE
BufferedReader br=new BufferedReader(new InputStreamReader(con.getInputStream()));
StringBuffer response=new StringBuffer();
String line;
//READ LINE BY LINE
while ((line=br.readLine()) != null)
response.append(line);
//RELEASE RES
br.close();
return response.toString();
else
catch (IOException e)
e.printStackTrace();
return null;
主活动：
package com.tutorials.hp.mysqlinsert;
import android.os.Bundle;
import android.support.v7.app.AppCompatActivity;
import android.support.v7.widget.Toolbar;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
/*
1.OUR LAUNCHER ACTIVITY
2.INITIALIZE SOME UI STUFF
3.WE START SENDER ON BUTTON CLICK
*/
public class MainActivity extends AppCompatActivity
String urlAddress="http://10.0.2.2/android/poster.php";
EditText nameTxt,posTxt,teamTxt;
Button saveBtn;
@Override
protected void onCreate(Bundle savedInstanceState)
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
Toolbar toolbar = (Toolbar) findViewById(R.id.toolbar);
setSupportActionBar(toolbar);
//INITIALIZE UI FIELDS
nameTxt= (EditText) findViewById(R.id.nameEditTxt);
posTxt= (EditText) findViewById(R.id.posEditTxt);
teamTxt= (EditText) findViewById(R.id.teamEditTxt);
saveBtn= (Button) findViewById(R.id.saveBtn);
saveBtn.setOnClickListener(new View.OnClickListener()
@Override
public void onClick(View v)
//START ASYNC TASK
Sender s=new Sender(MainActivity.this,urlAddress,nameTxt,posTxt,teamTxt);
s.execute();
);
ContentMain.xml：
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:app="http://schemas.android.com/apk/res-auto"
xmlns:tools="http://schemas.android.com/tools"
android:layout_
android:layout_
android:paddingBottom="@dimen/activity_vertical_margin"
android:paddingLeft="@dimen/activity_horizontal_margin"
android:paddingRight="@dimen/activity_horizontal_margin"
android:paddingTop="@dimen/activity_vertical_margin"
app:layout_behavior="@string/appbar_scrolling_view_behavior"
tools:context="com.tutorials.hp.mysqlinsert.MainActivity"
tools:showIn="@layout/activity_main">
<TextView
android:layout_
android:layout_
android:text="Hello World!" />
<LinearLayout
android:layout_
android:layout_
android:layout_marginTop="?attr/actionBarSize"
android:orientation="vertical"
android:paddingLeft="15dp"
android:paddingRight="15dp"
android:paddingTop="50dp">
<android.support.design.widget.TextInputLayout
android:id="@+id/nameLayout"
android:layout_
android:layout_>
<EditText
android:id="@+id/nameEditTxt"
android:layout_
android:layout_
android:singleLine="true"
android:hint= "Name" />
</android.support.design.widget.TextInputLayout>
<android.support.design.widget.TextInputLayout
android:id="@+id/teamLayout"
android:layout_
android:layout_>
<EditText
android:id="@+id/teamEditTxt"
android:layout_
android:layout_
android:hint="Description" />
</android.support.design.widget.TextInputLayout>
<android.support.design.widget.TextInputLayout
android:id="@+id/posLayout"
android:layout_
android:layout_>
<EditText
android:id="@+id/posEditTxt"
android:layout_
android:layout_
android:hint="Position" />
<!--android:inputType="textPassword"-->
</android.support.design.widget.TextInputLayout>
<Button android:id="@+id/saveBtn"
android:layout_
android:layout_
android:text="Save"
android:clickable="true"
android:background="@color/colorAccent"
android:layout_marginTop="40dp"
android:textColor="@android:color/white"/>
</LinearLayout>
</RelativeLayout>
【讨论】：
【参考方案8】：这是一个如何在不使用外部 Apache 库的情况下发布多部分数据的示例：
byte[] buffer = getBuffer();
if(buffer.length > 0)
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "RQdzAAihJq7Xp1kjraqf";
ByteArrayOutputStream baos = new ByteArrayOutputStream();
DataOutputStream dos = new DataOutputStream(baos);
// Send parameter #1
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"param1\"" + lineEnd);
dos.writeBytes("Content-Type: text/plain; charset=US-ASCII" + lineEnd);
dos.writeBytes("Content-Transfer-Encoding: 8bit" + lineEnd);
dos.writeBytes(lineEnd);
dos.writeBytes(myStringData + lineEnd);
// Send parameter #2
//dos.writeBytes(twoHyphens + boundary + lineEnd);
//dos.writeBytes("Content-Disposition: form-data; name=\"param2\"" + lineEnd + lineEnd);
//dos.writeBytes("foo2" + lineEnd);
// Send a binary file
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"param3\";filename=\"test_file.dat\"" + lineEnd);
dos.writeBytes("Content-Type: application/octet-stream" + lineEnd);
dos.writeBytes("Content-Transfer-Encoding: binary" + lineEnd);
dos.writeBytes(lineEnd);
dos.write(buffer);
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
dos.flush();
dos.close();
ByteArrayInputStream content = new ByteArrayInputStream(baos.toByteArray());
BasicHttpEntity entity = new BasicHttpEntity();
entity.setContent(content);
HttpPost httpPost = new HttpPost(myURL);
httpPost.addHeader("Connection", "Keep-Alive");
httpPost.addHeader("Content-Type", "multipart/form-data; boundary="+boundary);
//MultipartEntity entity = new MultipartEntity();
//entity.addPart("param3", new ByteArrayBody(buffer, "test_file.dat"));
//entity.addPart("param1", new StringBody(myStringData));
httpPost.setEntity(entity);
/*
String httpData = "";
ByteArrayOutputStream baos1 = new ByteArrayOutputStream();
entity.writeTo(baos1);
httpData = baos1.toString("UTF-8");
*/
/*
Header[] hdrs = httpPost.getAllHeaders();
for(Header hdr: hdrs)
httpData += hdr.getName() + " | " + hdr.getValue() + " |_| ";
*/
//Log.e(TAG, "httpPost data: " + httpData);
response = httpClient.execute(httpPost);
【讨论】：
使用apache库有什么问题吗？我是 android 应用程序的初学者，不知道原因背景 - 抱歉可能是愚蠢的问题:-) 没有，哈哈。 httpClient 和 httpPost 是 apache。 如何同时发送 JSONObject 和 doc 文件？ @lubosdz 因为android sdk下没有MultipartEntity，你必须为此包含外部jars【参考方案9】：这样我们就可以用http post方法发送数据并得到结果
public class MyHttpPostProjectActivity extends Activity implements OnClickListener
private EditText usernameEditText;
private EditText passwordEditText;
private Button sendPostReqButton;
private Button clearButton;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState)
super.onCreate(savedInstanceState);
setContentView(R.layout.login);
usernameEditText = (EditText) findViewById(R.id.login_username_editText);
passwordEditText = (EditText) findViewById(R.id.login_password_editText);
sendPostReqButton = (Button) findViewById(R.id.login_sendPostReq_button);
sendPostReqButton.setOnClickListener(this);
clearButton = (Button) findViewById(R.id.login_clear_button);
clearButton.setOnClickListener(this);
@Override
public void onClick(View v)
if(v.getId() == R.id.login_clear_button)
usernameEditText.setText("");
passwordEditText.setText("");
passwordEditText.setCursorVisible(false);
passwordEditText.setFocusable(false);
usernameEditText.setCursorVisible(true);
passwordEditText.setFocusable(true);
else if(v.getId() == R.id.login_sendPostReq_button)
String givenUsername = usernameEditText.getEditableText().toString();
String givenPassword = passwordEditText.getEditableText().toString();
System.out.println("Given username :" + givenUsername + " Given password :" + givenPassword);
sendPostRequest(givenUsername, givenPassword);
private void sendPostRequest(String givenUsername, String givenPassword)
class SendPostReqAsyncTask extends AsyncTask<String, Void, String>
@Override
protected String doInBackground(String... params)
String paramUsername = params[0];
String paramPassword = params[1];
System.out.println("*** doInBackground ** paramUsername " + paramUsername + " paramPassword :" + paramPassword);
HttpClient httpClient = new DefaultHttpClient();
// In a POST request, we don't pass the values in the URL.
//Therefore we use only the web page URL as the parameter of the HttpPost argument
HttpPost httpPost = new HttpPost("http://www.nirmana.lk/hec/android/postLogin.php");
// Because we are not passing values over the URL, we should have a mechanism to pass the values that can be
//uniquely separate by the other end.
//To achieve that we use BasicNameValuePair
//Things we need to pass with the POST request
BasicNameValuePair usernameBasicNameValuePair = new BasicNameValuePair("paramUsername", paramUsername);
BasicNameValuePair passwordBasicNameValuePAir = new BasicNameValuePair("paramPassword", paramPassword);
// We add the content that we want to pass with the POST request to as name-value pairs
//Now we put those sending details to an ArrayList with type safe of NameValuePair
List<NameValuePair> nameValuePairList = new ArrayList<NameValuePair>();
nameValuePairList.add(usernameBasicNameValuePair);
nameValuePairList.add(passwordBasicNameValuePAir);
try
// UrlEncodedFormEntity is an entity composed of a list of url-encoded pairs.
//This is typically useful while sending an HTTP POST request.
UrlEncodedFormEntity urlEncodedFormEntity = new UrlEncodedFormEntity(nameValuePairList);
// setEntity() hands the entity (here it is urlEncodedFormEntity) to the request.
httpPost.setEntity(urlEncodedFormEntity);
try
// HttpResponse is an interface just like HttpPost.
//Therefore we can't initialize them
HttpResponse httpResponse = httpClient.execute(httpPost);
// According to the JAVA API, InputStream constructor do nothing.
//So we can't initialize InputStream although it is not an interface
InputStream inputStream = httpResponse.getEntity().getContent();
InputStreamReader inputStreamReader = new InputStreamReader(inputStream);
BufferedReader bufferedReader = new BufferedReader(inputStreamReader);
StringBuilder stringBuilder = new StringBuilder();
String bufferedStrChunk = null;
while((bufferedStrChunk = bufferedReader.readLine()) != null)
stringBuilder.append(bufferedStrChunk);
return stringBuilder.toString();
catch (ClientProtocolException cpe)
System.out.println("First Exception caz of HttpResponese :" + cpe);
cpe.printStackTrace();
catch (IOException ioe)
System.out.println("Second Exception caz of HttpResponse :" + ioe);
ioe.printStackTrace();
catch (UnsupportedEncodingException uee)
System.out.println("An Exception given because of UrlEncodedFormEntity argument :" + uee);
uee.printStackTrace();
return null;
@Override
protected void onPostExecute(String result)
super.onPostExecute(result);
if(result.equals("working"))
Toast.makeText(getApplicationContext(), "HTTP POST is working...", Toast.LENGTH_LONG).show();
else
Toast.makeText(getApplicationContext(), "Invalid POST req...", Toast.LENGTH_LONG).show();
SendPostReqAsyncTask sendPostReqAsyncTask = new SendPostReqAsyncTask();
sendPostReqAsyncTask.execute(givenUsername, givenPassword);
【讨论】：
【参考方案10】：@primpop 回答我将添加如何将响应转换为字符串：
HttpResponse response = client.execute(request);
HttpEntity entity = response.getEntity();
if (entity != null)
InputStream instream = entity.getContent();
String result = RestClient.convertStreamToString(instream);
Log.i("Read from server", result);
Here is an example of convertStramToString.
【讨论】：
“HttpClient”、“HttpPost”、“HttpResponse”、“HttpEntity”、“EntityUtils”、“NameValuePair”、“BasicNameValuePair”是已弃用。请提出其他解决方案。【参考方案11】：
如果您只想将数据附加到 Url，您可以使用 HttpUrlConnection 来完成，因为 HttpClient 现在已被弃用。 更好的方法是使用类似的库-
凌空抽射 改造
我们可以使用通过AsyncTask类执行的代码将数据发布到php脚本并获取结果并显示它。
private class LongOperation extends AsyncTask<String, Void, Void>
// Required initialization
private String Content;
private String Error = null;
private ProgressDialog Dialog = new ProgressDialog(Login.this);
String data ="";
int sizeData = 0;
protected void onPreExecute()
// NOTE: You can call UI Element here.
//Start Progress Dialog (Message)
Dialog.setMessage("Please wait..");
Dialog.show();
Dialog.setCancelable(false);
Dialog.setCanceledOnTouchOutside(false);
try
// Set Request parameter
data +="&" + URLEncoder.encode("username", "UTF-8") + "="+edittext.getText();
catch (UnsupportedEncodingException e)
// TODO Auto-generated catch block
e.printStackTrace();
// Call after onPreExecute method
protected Void doInBackground(String... urls)
/************ Make Post Call To Web Server ***********/
BufferedReader reader=null;
// Send data
try
// Defined URL where to send data
URL url = new URL(urls[0]);
// Send POST data request
URLConnection conn = url.openConnection();
conn.setConnectTimeout(5000);//define connection timeout
conn.setReadTimeout(5000);//define read timeout
conn.setDoOutput(true);
OutputStreamWriter wr = new OutputStreamWriter(conn.getOutputStream());
wr.write( data );
wr.flush();
// Get the server response
reader = new BufferedReader(new InputStreamReader(conn.getInputStream()));
StringBuilder sb = new StringBuilder();
String line = null;
// Read Server Response
while((line = reader.readLine()) != null)
// Append server response in string
sb.append(line + " ");
// Append Server Response To Content String
Content = sb.toString();
catch(Exception ex)
Error = ex.getMessage();
finally
try
reader.close();
catch(Exception ex)
return null;
protected void onPostExecute(Void unused)
// NOTE: You can call UI Element here.
// Close progress dialog
Dialog.dismiss();
if (Error != null)
Toast.makeText(getApplicationContext(),"Error encountered",Toast.LENGTH_LONG).show();
else
try
JSONObject jsonRootObject = new JSONObject(Content);
JSONObject json2 =jsonRootObject.getJSONObject("jsonkey");//pass jsonkey here
String id =json2.optString("id").toString();//parse json to string through parameters
//the result is stored in string id. you can display it now
catch (JSONException e) e.printStackTrace();
但是使用诸如 volley 或 retrofit 之类的库是更好的选择，因为 Asynctask 类和 HttpurlConnection 与库相比要慢得多。该库还将获取所有内容，并且速度也更快。
【讨论】：
【参考方案12】：您可以将URLConnection 与setDoOutput(true)、getOutputStream()（用于发送数据）、和 getInputStream()（用于接收）一起使用。 Sun 有an example正是为了这个。
【讨论】：
仅供参考，与 HttpClient 4.x 库相比，URLConnection 的性能相当差。 我更喜欢纯 URLConnection，因为它似乎比 Apache Commons HttpClient 更快。【参考方案13】：对我来说接下来的作品：
private sendData()
JSONObject jsonObject = new JSONObject();
jsonObject.accumulate("key1", value1);
jsonObject.accumulate("key2", value2);
boolean success = sendPost(SERVER_URL + "/v1/auth", jsonObject);
private boolean sendPost(String url, JSONObject parameters)
boolean requestResult = false;
InputStream inputStream = null;
String result = "";
try
HttpClient httpclient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url);
String json = "";
json = parameters.toString();
StringEntity se = new StringEntity(json);
httpPost.setEntity(se);
httpPost.setHeader("Accept", "application/json");
httpPost.setHeader("Content-type", "application/json");
HttpResponse httpResponse = httpclient.execute(httpPost);
inputStream = httpResponse.getEntity().getContent();
if (inputStream != null)
result = convertInputStreamToString(inputStream);
requestResult = true;
else
result = "Did not work!";
requestResult = false;
System.out.println(result);
catch (Exception e)
Log.d("InputStream", e.getLocalizedMessage());
requestResult = false;
return requestResult;
【讨论】：
【参考方案14】：在较新版本的 Android 中，您必须将所有 Web I/O 请求放入一个新线程中。 AsyncTask 最适合小请求。
【讨论】：
虽然很有价值，但这不是问题的答案，应该作为评论。【参考方案15】：将数据作为 HTTP 请求发布的方法，
public static InputStream callPostService(String Url,
List<NameValuePair> data)
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(Url);
try
httppost.setEntity(new UrlEncodedFormEntity(data));
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
return entity.getContent();
catch (ClientProtocolException e)
e.printStackTrace();
catch (IOException e)
e.printStackTrace();
return null;
【讨论】：
“HttpClient”、“HttpPost”、“HttpResponse”、“HttpEntity”、“EntityUtils”、“NameValuePair”、“BasicNameValuePair”是已弃用。请提出其他解决方案。
@Rohit Suthar，不推荐用于新的 Android 版本，而不是旧版本。所以停止垃圾邮件【参考方案16】：
最好使用 Apache Commons HttpClient，它也包含在 android 中。 看一下 Android Developer: Apache HTTP Client Package Summary 获取一般 api 信息。
【讨论】：
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