如何根据服务时间禁用时间段?
Posted
技术标签:
【中文标题】如何根据服务时间禁用时间段?【英文标题】:How to disabled time slots according to service time? 【发布时间】:2012-07-10 20:12:05 【问题描述】:我只想根据我的营业时间和阻止或禁用那些时间段计算时间段列表预约。
我已经解决了我的问题,卡在最后一个任务上,请在下面提及。
My Service Duration = 60min.
My Today Busines Hours:
start time - 10:00 AM
end time - 3:00 PM
我已根据我今天的营业时间生成了 15 分钟的时隙列表:
$start = strtotime('10:00 AM');
$end = strtotime('3:00 PM');
for( $i = $start; $i <= $end; $i += (60*15))
$slotlist[] = date('g:iA', $i);
//output
10:00AM
10:15AM
10:30AM
10:45AM
11:00AM
11:15AM
11:30AM
11:45AM
12:00PM
12:15PM
12:30PM
12:45PM
1:00PM
1:15PM
1:30PM
1:45PM
2:00PM
2:15PM
2:30PM
2:45PM
3:00PM
现在我已经预约了 3 个约会
约会 |开始时间到结束时间
Appointment-1 : 10:00 AM to 11:00 AM (根据我的服务时长60分钟) 预约 2:上午 11:15 至下午 12:15 预约 3:下午 1:00 至下午 2:00
//array of all appointment start_time
$appointment_start_time = array('10:00AM','11:15AM','1:00PM');
现在禁用那些已经预约的时间段
foreach($slotlist as $single)
if(in_array($single, $appointment_start_time))
echo "<input name=start_time type='radio' disabled value='$single' />".$single; echo "<br>";
$time = $single;
$event_length = 60-15; // 60 is time duration
$timestamp = strtotime("$time");
$endtime = strtotime("+$event_length minutes", $timestamp);
$next_time = date('g:i A', $endtime);
//calculate between slots (start-end time)
$start = strtotime($single);
$end = strtotime($next_time);
for( $i = $start; $i <= $end; $i += (60*15))
$list2[] = date('g:iA', $i);
else
if(in_array($single, $list2))
echo "<input name=start_time type='radio' disabled value='$single' />".$single; echo "<br>";
else
echo "<input name=start_time type='radio' value='$single' />".$single; echo "<br>";
//output
10:00AM -disabled
10:15AM -disabled
10:30AM -disabled
10:45AM -disabled
11:00AM
11:15AM -disabled
11:30AM -disabled
11:45AM -disabled
12:00PM -disabled
12:15PM
12:30PM
12:45PM
1:00PM -disabled
1:15PM -disabled
1:30PM -disabled
1:45PM -disabled
2:00PM
2:15PM
2:30PM
2:45PM
3:00PM
现在要做的最后一个任务, 如何删除那些不符合服务持续时间的时间段,例如:
11:00AM (single slot b/w 2 appointment, cover only 15min)
12:15PM -
12:30PM -(3 slot b/w 2 appointment, cover only 45min)
12:45PM -
【问题讨论】:
【参考方案1】:试试这个: 1.将第一个时隙与$appointment_start_time[0]比较,如果第一个时隙> $appointment_start_time[0]-60min,则禁用该时隙直到$appointment_start_time[0]。
2.比较 $appointment_start_time[1] 和 $appointment_start_time[0],如果持续时间 > 2 小时(您的服务持续时间 X 2),禁用 $appointment_start_time[0] 和 $appointment_start_time[1] 之间的时间段
3.比较 $appointment_start_time[2] 和 end-time,如果 end-time-120
【讨论】:
【参考方案2】:两天过去了,我让这件事成为可能
$slottimes = 15;
$duration = 60;
$business_start = '10:00AM';
$business_end = '3:00PM';
echo "<b>Today's Wroking Hours $business_start to $business_end</b><br>";
echo "<b>Calendar Slot(s) Time:</b> $slottimes<br>";
echo "<b>Service Duration Time:</b> $duration<br><br>";
$start = strtotime($business_start);
$end = strtotime($business_end);
/*$endtimestamp = strtotime($business_end);
$end = strtotime("-$slottimes minutes", $endtimestamp);*/
for( $i = $start; $i <= $end; $i += (60*$slottimes))
$slotlist[] = date('g:iA', $i);
echo "<b>Generate Today's Available Appointment Time(s)</b><br>";
echo "<pre>"; print_r($slotlist); echo "</pre>";
echo "<b>Today's Booked Appointment(s)</b>";
$appstarttime = array('11:00AM', '11:15AM', '1:00PM', $business_end ); //business end-time always be in array
$previoustime = NULL;
$nexttime = array($business_end);
foreach($slotlist as $single)
if(in_array($single, $appstarttime))
//calculate next time
$time = $single;
$event_length = $duration-$slottimes; // 60min Service duration time - 15 slot time
$timestamp = strtotime("$time");
$endtime = strtotime("+$event_length minutes", $timestamp);
$next_time = date('g:i A', $endtime);
//calculate between slots (start-end time)
$start = strtotime($single);
$end = strtotime($next_time);
for( $i = $start; $i <= $end; $i += (60*$slottimes))
$nexttime[] = date('g:iA', $i);
//calculate previous time
$time1 = $single;
$event_length1 = $duration-$slottimes; // 60min Service duration time - 15 slot time
$timestamp1 = strtotime("$time1");
$endtime1 = strtotime("-$event_length1 minutes", $timestamp1);
$next_time1 = date('g:i A', $endtime1);
//calculate between slots (start-end time)
$start1 = strtotime($next_time1);
$end1 = strtotime($single);
for( $i = $start1; $i <= $end1; $i += (60*$slottimes))
$previoustime[] = date('g:iA', $i);
echo "<br>Appointment Start Time: ";
print_r($appstarttime);
echo "<br>";
echo "<br><strong>Previous Time: </strong>";
print_r($previoustime);
echo "<br>";
echo "<br><strong>Next Time: </strong>";
print_r($nexttime);
echo "<br>";
echo "<br><strong>Merge Both Time:</strong> ";
if($previoustime && $nexttime)
$merge = array_merge($previoustime, $nexttime);
print_r($merge);
echo "<br>";echo "<br>";
$flag1 = 0;
$flag2 = 0;
echo "<hr><b>Today's Available Time For Appointment:</b><hr>";
foreach($slotlist as $single)
if(in_array($single, $merge))
echo "<input name=start_time type='radio' disabled value='$single' />".$single; echo "<br>";
else
echo "<input name=start_time type='radio' value='$single' />".$single; echo "<br>";
if(in_array($single, $merge))
$flag1 = 1;
else
$flag2 = 2;
if($flag2 != 2)
echo "Sorry ! Today's all appointments has been booked.";
echo "<hr>";
【讨论】:
以上是关于如何根据服务时间禁用时间段?的主要内容,如果未能解决你的问题,请参考以下文章
如何在 iOS 中禁用来自 Web 服务调用的自动排序 JSON 字典响应