应用服务计划的 Azure 函数应用超时

Posted 2023-02-19

【中文标题】应用服务计划的 Azure 函数应用超时

【英文标题】：Azure function app timeout for app service plan

【发布时间】：2019-08-30 08:44:10

【问题描述】：

我确实遵循https://docs.microsoft.com/da-dk/azure/azure-functions/functions-host-json#functiontimeout 中提到的指南，通过使用“functionTimeout”更新主机文件将应用服务计划中功能应用主机的默认超时时间从 30 分钟增加到 2 小时：“02:00:00”

在检查函数应用的事件查看器日志时，我可以看到超时限制仍然是 30m。添加错误信息以供参考，

        <EventData>
            <Data>Application: w3wp.exe
CoreCLR Version: 4.6.27317.7
Description: The process was terminated due to an unhandled exception.
Exception Info: Microsoft.Azure.WebJobs.Host.FunctionTimeoutException: Timeout value of 00:30:00 was exceeded by function: CreateRequestApplicationPostProcessor
   at Microsoft.Azure.WebJobs.Host.Executors.FunctionExecutor.TryHandleTimeoutAsync(Task invokeTask, CancellationToken shutdownToken, Boolean throwOnTimeout, CancellationToken timeoutToken, TimeSpan timeoutInterval, IFunctionInstance instance, Action onTimeout) in C:\projects\azure-webjobs-sdk-rqm4t\src\Microsoft.Azure.WebJobs.Host\Executors\FunctionExecutor.cs:line 631
   at Microsoft.Azure.WebJobs.Host.Executors.FunctionExecutor.InvokeAsync(IFunctionInvoker invoker, ParameterHelper parameterHelper, CancellationTokenSource timeoutTokenSource, CancellationTokenSource functionCancellationTokenSource, Boolean throwOnTimeout, TimeSpan timerInterval, IFunctionInstance instance) in C:\projects\azure-webjobs-sdk-rqm4t\src\Microsoft.Azure.WebJobs.Host\Executors\FunctionExecutor.cs:line 547
   at Microsoft.Azure.WebJobs.Host.Executors.FunctionExecutor.ExecuteWithWatchersAsync(IFunctionInstance instance, ParameterHelper parameterHelper, ILogger logger, CancellationTokenSource functionCancellationTokenSource) in C:\projects\azure-webjobs-sdk-rqm4t\src\Microsoft.Azure.WebJobs.Host\Executors\FunctionExecutor.cs:line 503
   at Microsoft.Azure.WebJobs.Host.Executors.FunctionExecutor.ExecuteWithLoggingAsync(IFunctionInstance instance, ParameterHelper parameterHelper, IFunctionOutputDefinition outputDefinition, ILogger logger, CancellationTokenSource functionCancellationTokenSource) in C:\projects\azure-webjobs-sdk-rqm4t\src\Microsoft.Azure.WebJobs.Host\Executors\FunctionExecutor.cs:line 439
   at Microsoft.Azure.WebJobs.Host.Executors.FunctionExecutor.ExecuteWithLoggingAsync(IFunctionInstance instance, FunctionStartedMessage message, FunctionInstanceLogEntry instanceLogEntry, ParameterHelper parameterHelper, ILogger logger, CancellationToken cancellationToken) in C:\projects\azure-webjobs-sdk-rqm4t\src\Microsoft.Azure.WebJobs.Host\Executors\FunctionExecutor.cs:line 249
   at Microsoft.Azure.WebJobs.Host.Executors.FunctionExecutor.ExecuteWithLoggingAsync(IFunctionInstance instance, FunctionStartedMessage message, FunctionInstanceLogEntry instanceLogEntry, ParameterHelper parameterHelper, ILogger logger, CancellationToken cancellationToken) in C:\projects\azure-webjobs-sdk-rqm4t\src\Microsoft.Azure.WebJobs.Host\Executors\FunctionExecutor.cs:line 293
   at Microsoft.Azure.WebJobs.Host.Executors.FunctionExecutor.TryExecuteAsync(IFunctionInstance functionInstance, CancellationToken cancellationToken) in C:\projects\azure-webjobs-sdk-rqm4t\src\Microsoft.Azure.WebJobs.Host\Executors\FunctionExecutor.cs:line 89
   at Microsoft.Azure.WebJobs.Host.Timers.WebJobsExceptionHandler.&lt;&gt;c__DisplayClass3_0.&lt;OnUnhandledExceptionAsync&gt;b__0() in C:\projects\azure-webjobs-sdk-rqm4t\src\Microsoft.Azure.WebJobs.Host\Timers\WebJobsExceptionHandler.cs:line 54
   at System.Threading.Thread.ThreadMain_ThreadStart()
   at System.Threading.ThreadHelper.ThreadStart_Context(Object state)
   at System.Threading.ExecutionContext.RunInternal(ExecutionContext executionContext, ContextCallback callback, Object state)
--- End of stack trace from previous location where exception was thrown ---
   at System.Threading.ExecutionContext.RunInternal(ExecutionContext executionContext, ContextCallback callback, Object state)
   at System.Threading.ThreadHelper.ThreadStart()
</Data>
        </EventData>
    </Event>

感谢您在覆盖自定义超时值方面的帮助。

【问题讨论】：

您是否为Always on启用了应用服务计划？

感谢您查看@JoeyCai。是的

【参考方案1】：

如果您在应用服务计划上运行，则应启用 始终开启 设置，以便您的函数应用正确运行。

即使启用了 Always On，单个函数的执行超时也由 host.json 项目文件中的 functionTimeout 设置控制。

更多详情可以参考article。

【讨论】：

我已经在一个应用服务计划中运行函数应用程序，并且在我最初的问题中提到，host.json 中的值 "functionTimeout": "02:00:00" 始终处于打开状态跨度>

你的函数重启了吗？

【参考方案2】：

您始终可以在函数级别使用属性 [Timeout("1:00:00")] 来覆盖默认超时