Django：如何在用户使用默认的 UserCreationForm 注册后立即登录？

Posted 2023-02-19

【中文标题】Django：如何在用户使用默认的 UserCreationForm 注册后立即登录？

【英文标题】：Django: How to log user in right after they had registered with somewhat default UserCreationForm?

【发布时间】：2022-01-18 12:26:07

【问题描述】：

我正在尝试在用户注册应用后立即登录，这样他们就不必立即手动登录。我已经从 django 的 UserCreationForm 创建了 RegisterForm 并且它可以正常工作 - 如果表单有效，它会创建一个 User 对象，但我不知道如何访问创建的 User 对象以使用 login 函数记录它，这需要，除了请求之外，还有一个用户对象。注意：我在 models.py 中编辑了默认用户。这是我的代码：

class RegisterForm(UserCreationForm):
    def __init__(self, *args, **kwargs):
        super().__init__(*args,**kwargs)
        self.fields['username'].widget.attrs.update('class':'form-control','id':'username', 'aria-describedby':'usernameHelp')
        self.fields['password1'].widget.attrs.update('class':'form-control','id':'password1', 'aria-describedby':'password1Help')
        self.fields['password2'].widget.attrs.update('class':'form-control','id':'password2','aria-describedby':'password2Help')
    
    class Meta:
        model = User
        fields = ['username', 'password1', 'password2', 'email', 'first_name', 'last_name',
         'photo', 'amazon', 'twitter', 'facebook', 'instagram', 'youtube']
        widgets = 
            'email':EmailInput(attrs='class':'form-control', 'id':'email', 'aria-describedby':'emailHelp'),
            'first_name':TextInput(attrs='class':'form-control', 'id':'first_name',),
            'last_name':TextInput(attrs='class':'form-control','id':'last_name', 'aria-describedby':'nameHelp'),
            'photo':ClearableFileInput(attrs='class':'form-control','id':'photo', 'aria-describedby':'photoHelp'),
            'amazon':URLInput(attrs='class':'form-control', 'id':'amazon', 'aria-describedby':'amazonHelp'),
            'twitter':URLInput(attrs='class':'form-control', 'id':'twitter', 'aria-describedby':'twitterHelp'),
            'facebook':URLInput(attrs='class':'form-control', 'id':'facebook', 'aria-describedby':'facebookHelp'),
            'instagram':URLInput(attrs='class':'form-control', 'id':'instagram', 'aria-describedby':'instagramHelp'),
            'youtube':URLInput(attrs='class':'form-control', 'id':'youtube', 'aria-describedby':'youtubeHelp')
        

这是视图：

def register(request):
    # POST
    if request.method == "POST":
        # In addition to our form we must make sure to get the files too, if photo is uploaded
        form = RegisterForm(request.POST, request.FILES or None)
        if form.is_valid():
            form.save()
            #user = User.objects.get() ???
            #login(request, user)
            return HttpResponseRedirect(reverse('index'))
        else:
            return render(request, "astator/register.html", 
            "form":form, 
            "message":"Something went wrong. Please try filling out the fields again. Make sure that your passwords match and that they satisfy the requirements listed bellow."
            )

    # GET
    else:
        form = RegisterForm()
        return render(request, "astator/register.html", "form":form)

【参考方案1】：

在您的 form 中，您可以访问您的 user 对象，这样您就可以执行类似的操作：

if form.is_valid():
        user = form.save()
        login(request, user)
        return HttpResponseRedirect(reverse('index'))

这是有关保存方法的文档中的说明：Django Save Method

【参考方案2】：

与一般的表单建模类似，UserCreationForm 在您保存表单时返回用户模型实例。

    if form.is_valid():
        user = form.save()
        login(request, user)
        return HttpResponseRedirect(reverse('index'))

【参考方案3】：

您可以创建一个 html 页面，然后从该 url 调用这个 classView，您可以使用 django 身份验证更方便

class LoginForm(AuthenticationForm):
    username = UsernameField(widget=forms.TextInput(
        attrs='autofocus': True, 'class': 'form-control'))
    password = forms.CharField(label=_("Password"), strip=False, widget=forms.PasswordInput(
        attrs='autocomplete': 'current-password', 'class': 'form-control'))

【讨论】：

不！这个没用，作者用的是FBV