基于文本的游戏。主功能

Posted 2023-02-19

【中文标题】基于文本的游戏。主功能

【英文标题】：Text based game. main function

【发布时间】：2022-01-24 01:09:30

【问题描述】：

所以我是个白痴，几乎在 main 函数之外编写了 mina 代码。我还是新手，还在学习，所以当我将代码移动到主函数时，我无法访问已定义的变量。我的位置和库存，因为它们是在主函数中定义的，所以当我尝试调用 status() 时无法正常工作。但是当我将库存和位置移到主要功能之外时，库存将无法访问房间。谁能指出我解决此问题的正确方向。谢谢

def instructions():
 print("\n      Super Humans Adventure Game")
 print("-------------Instructions-------------")
 print("Collect the 6 items within the rooms to")
 print("defeat the scientist and win.")
 print("To move type: North, South, West, or East")
 print('-' * 38)


def status():
 print('-' * 20)
 print('You are in the '.format(location['name']))
 print('Your current inventory: \n'.format(inventory))
 if location['item']:
     print('Item in room: '.format(', '.join(location['item'])))
     print('')


#calls instructions
instructions()


def main():
 rooms = 

     'Main Entrance': 
         'name': 'Main Entrance',
         'item': [],
         'East': 'Dining Room',
     'Dining Room': 
         'name': 'Dining Room',
         'item': ['potion'],
         'West': 'Main Entrance',
         'North': 'Laboratory',
         'East': 'Break Room',
         'South': 'Holding Cells',
     'Laboratory': 
         'name': 'Laboratory',
         'item': ['shield'],
         'East': 'Office',
         'South': 'Dining Room',
     'Office': 
         'name': 'Office',
         'item': [],
         'West': 'Laboratory',  # Villian
     'Break Room': 
         'name': 'Break Room',
         'item': ['key'],
         'West': 'Dining Room',
         'East': 'Bathroom',
     'Bathroom': 
         'name': 'Bathroom',
         'item': ['suit'],
         'West': 'Break Room',
     'Holding Cells': 
         'name': 'Holding Cells',
         'item': [],
         'East': 'Armory',
         'North': 'Dining Room',
     'Armory': 
         'name': 'Armory',
         'item': ['weapon'],
         'North': 'Power Room',
         'West': 'Holding Cells',
     'Power Room': 
         'name': 'Power Room',
         'item': ['power'],
         'South': 'Armory'

 

 location = rooms['Holding Cells']
 directions = ['North', 'East', 'South', 'West']
 inventory = []


 while True:
     if location == rooms['Office'] and len(inventory) > 5:
         print('')
         print('You have defeated the scientist and escaped! Congratulations')
     elif location == rooms['Office'] and len(inventory) < 6:
         print('')
         print('You have reached the scientist but you are too weak!')
         print('You have died')
         break
 # shows current location
     status()
 # user input
     cmd = input('Enter move: ').capitalize().strip()
     if cmd in directions:
         if cmd in location:
             location = rooms[location[cmd]]
             print('You successfully moved locations.')
         else:
             print('')
             print('You can not go that way!')
 # quit game
     elif cmd.lower in ('q', 'quit'):
         print('You have quit the game, thanks for playing!')
         break

 # get item
     elif cmd.lower().split()[0] == 'get':
         item = cmd.lower().split()[1]
         if item in location['item']:
             location['item'].remove(item)
             inventory.append(item)
         else:
             print('There is no item here.')
     else:
         print('That is not a valid input')
    
  
main()

【问题讨论】：

您应该将它们作为参数传递给函数。

啊啊啊是的。完全忘记了 ab 参数大声笑。谢谢，这解决了我的问题。

【参考方案1】：

将它们作为参数传递实际上是解决方案。有人提到了这一点，这正是我所需要的。这是更新代码

def status(location, inventory, rooms):
    print('-' * 20)
    print('You are in the '.format(location['name']))
    print('Your current inventory: \n'.format(inventory))
    if location['item']:
        print('Item in room: '.format(', '.join(location['item'])))
        print('')

然后在调用函数的时候我只是填写了参数。

    # shows current location
        status(location, inventory, rooms)

【参考方案2】：

你可以

在 Main 中创建一个名为“仓库”的 OBJECT，每个项目及其库存都可以在仓库对象中维护，因此您不需要将其作为子例程，和/或 您可以在 main 或其他子例程之外创建“全局变量”，以便在代码启动时定义，或者 您可以将变量传递给子例程（从 Main），并在子例程完成后将返回值传回给 main。

【讨论】：

感谢您的建议，但参数是我最容易理解的解决方案。因为我正处于学习 python 的早期阶段。