Ajax 无法正常工作。 PHP 无法在 SQL 中插入数据

Posted 2023-05-09

【中文标题】Ajax 无法正常工作。 PHP 无法在 SQL 中插入数据

【英文标题】：Ajax not working properly. PHP cannot insert data in SQL

【发布时间】：2019-11-26 01:17:37

【问题描述】：

我正在使用 Jquery 数组来获取动态输入表单上的变量。我可以将数组分组并输出到 console.log 中，但是不能在多表数据库本身中插入任何数据。

这是带有 ajax 和 console.log 的 Jquery 代码

    $("button[name='submit_addPackresCategories']").click(function()
        var packres_categories_name;
        $("input[id='packres_categories_name']").each(function()
            packres_categories_name = this.value;
        );
        console.log(packres_categories_name);

        var packres_categories_description;
        $("textarea[id='packres_categories_description']").each(function()
            packres_categories_description = this.value;
        );
        console.log(packres_categories_description);

        var packres_categories_paxhead_day = ;
        $("input[id^='packres_categories_paxhead_day']").each(function()
            packres_categories_paxhead_day[this.id] = this.value;
        );
        console.log(packres_categories_paxhead_day);

        var packres_categories_paxhead_price = ;
        $("input[id^='packres_categories_paxhead_price']").each(function()
            packres_categories_paxhead_price[this.id] = this.value;
        );
        console.log(packres_categories_paxhead_price);

        var packres_categories_paxgroup_size = ;
        $("input[id^='packres_categories_paxgroup_size']").each(function()
            packres_categories_paxgroup_size[this.id] = this.value;
        );
        console.log(packres_categories_paxgroup_size);

        var packres_categories_paxgroup_consumable = ;
        $("input[id^='packres_categories_paxgroup_consumable']").each(function()
            packres_categories_paxgroup_consumable[this.id] = this.value;
        );
        console.log(packres_categories_paxgroup_consumable);

        $.ajax(
            url: "ajax/addPackresCategories.php",
            type: "post",
            data: 
                packres_categories_name: packres_categories_name,
                packres_categories_description: packres_categories_description,
                packres_categories_paxhead_day: packres_categories_paxhead_day,
                packres_categories_paxhead_price: packres_categories_paxhead_price,
                packres_categories_paxgroup_size: packres_categories_paxgroup_size,
                packres_categories_paxgroup_consumable: packres_categories_paxgroup_consumable
            
        )
        .done(function(response)
            if (JSON.parse(response)) 
                alert("Successfully Added New Package!");
            
            else 
                alert("Failed!");
            
        );
    );

这里是 ajax 的网址

<?php
    include_once("../db.php");
    include "admin_session.php";

    $packres_categories_name = $_POST["packres_categories_name"];
    $packres_categories_description = $_POST["packres_categories_description"];
    $packres_categories_paxhead = array_combine($_POST["packres_categories_paxhead_day"], $_POST["packres_categories_paxhead_price"]);
    $packres_categories_paxgroup = array_combine($_POST["packres_categories_paxgroup_size"], $_POST["packres_categories_paxgroup_consumable"])

    $sql_insertPackresNameDesc_packresCategories = "INSERT INTO packres_categories(packres_categories_name, packres_categories_description) VALUES('" . mysqli_real_escape_string($conn, $packres_categories_name) . "', '" . mysqli_real_escape_string($conn, $packres_categories_description) . "')";
    $query_sql_insertPackresNameDesc_packresCategories = $conn->query($sql_insertPackresNameDesc_packresCategories);
    $affectedRows_query_sql_insertPackresNameDesc_packresCategories = mysqli_affected_rows($conn); //will be used to verify if inserted properly on database later

    $packres_id = mysqli_insert_id($conn);//will be used later

    foreach ($packres_categories_paxhead as $key => $value) 
        $sql_insertPackresCategoriesPaxhead_packresCategoriesPaxHead = "INSERT INTO packres_categories_paxhead(packres_id, packres_categories_paxhead_day, packres_categories_paxhead_day) VALUES('" . mysqli_real_escape_string($conn, $packres_id) . "', '" . mysqli_real_escape_string($conn, $key) . "', '" . mysqli_real_escape_string($conn, $value) . "')";
        $query_sql_insertPackresCategoriesPaxhead_packresCategoriesPaxHead = $conn->query($insertPackresCategoriesPaxhead_packresCategoriesPaxHead);
        $affectedRows_query_sql_insertPackresCategoriesPaxhead_packresCategoriesPaxHead += mysqli_affected_rows($conn);
    

    foreach ($packres_categories_paxgroup as $key => $value) 
        $sql_insertPackresCategoriesPaxGroup_packresCategoriesPaxgroup = "INSERT INTO packres_categories_paxgroup(packres_id, packres_categories_paxgroup_size, packres_categories_paxgroup_consumable) VALUES('" . mysqli_real_escape_string($conn, $packres_id) . "', '" . mysqli_real_escape_string($conn, $key) . "', '" . mysqli_real_escape_string($conn, $value) . "')";
        $query_sql_insertPackresCategoriesPaxGroup_packresCategoriesPaxgroup = $conn->query($sql_insertPackresCategoriesPaxGroup_packresCategoriesPaxgroup);
        $affectedRows_query_sql_insertPackresCategoriesPaxGroup_packresCategoriesPaxgroup += mysqli_affected_rows($conn);
    

    $conn->close();

    if (($affectedRows_query_sql_insertPackresNameDesc_packresCategories != 0) && ($affectedRows_query_sql_insertPackresCategoriesPaxhead_packresCategoriesPaxHead != 0) && ($$affectedRows_query_sql_insertPackresCategoriesPaxGroup_packresCategoriesPaxgroup != 0)) 
        echo json_encode(true);
    
    else 
        echo json_encode(false);
    
?>

数据数组应正确插入数据库，但没有数据进入数据库。

在控制台抛出错误行

Uncaught SyntaxError: Unexpected token < in JSON at position 0
    at JSON.parse (<anonymous>)
    at Object.<anonymous> (master.js:70)
    at u (jquery.min.js:2)
    at Object.fireWith [as resolveWith] (jquery.min.js:2)
    at k (jquery.min.js:2)
    at XMLHttpRequest.<anonymous> (jquery.min.js:2)

【问题讨论】：

将对此进行调查。谢谢你:)

【参考方案1】：

json_encode()- 返回值的 JSON 表示。 你正在返回布尔值