ORACLE SQL：填写缺失的日期

Posted 2023-05-09

【中文标题】ORACLE SQL：填写缺失的日期

【英文标题】：ORACLE SQL: Fill in missing dates

【发布时间】：2015-04-14 17:53:10

【问题描述】：

我有以下代码，它提供了三十天的生产日期和生产量。

select 
(case when trunc(so.revised_due_date) <= trunc(sysdate) 
    then trunc(sysdate) else trunc(so.revised_due_date) end) due_date, 
(case 
    when (case when sp.pr_typ in ('VV','VD') then 'DVD' when sp.pr_typ in ('RD','CD') 
    then 'CD' end) = 'CD' 
    and  (case when so.tec_criteria in ('PI','MC') 
    then 'XX' else so.tec_criteria end) = 'OF'
    then sum(so.revised_qty_due)
end) CD_OF_VOLUME
from shop_order so
left join scm_prodtyp sp
on so.prodtyp = sp.prodtyp
where so.order_type = 'MD' 
and so.plant = 'W' 
and so.status_code between '4' and '8' 
and trunc(so.revised_due_date) <= trunc(sysdate)+30
group by trunc(so.revised_due_date), so.tec_criteria, sp.pr_typ
order by trunc(so.revised_due_date)

我遇到的问题是没有计划生产的日期，该日期不会出现在报告中。有没有办法补缺日期。

即当前报告显示以下内容...

DUE_DATE    CD_OF_VOLUME 
14/04/2015     35,267.00 
15/04/2015     71,744.00 
16/04/2015     20,268.00 
17/04/2015     35,156.00 
18/04/2015     74,395.00 
19/04/2015      3,636.00 
21/04/2015      5,522.00
22/04/2015     15,502.00
04/05/2015     10,082.00

注意：缺少日期（20/04/2015、23/04/2015 至 03/05/2015）

范围始终是从 sysdate 开始的 30 天。 如何填写缺失的日期？ 您需要某种日历表吗？

谢谢

【问题讨论】：

是的，只需使用日历视图或子查询。看到这个问题：***.com/questions/8374959/…

【参考方案1】：

您可以从SYSDATE 获得 30 天的期限，如下所示（我假设您要包括 SYSDATE？）：

WITH mydates AS (
    SELECT TRUNC(SYSDATE) - 1 + LEVEL AS due_date FROM dual
   CONNECT BY LEVEL <= 31
)

然后使用上述方法对您的查询执行LEFT JOIN（将您的查询也放在 CTE 中也许不是一个坏主意）：

WITH mydates AS (
    SELECT TRUNC(SYSDATE) - 1 + LEVEL AS due_date FROM dual
   CONNECT BY LEVEL <= 31
), myorders AS (
    select 
    (case when trunc(so.revised_due_date) <= trunc(sysdate) 
        then trunc(sysdate) else trunc(so.revised_due_date) end) due_date, 
    (case 
        when (case when sp.pr_typ in ('VV','VD') then 'DVD' when sp.pr_typ in ('RD','CD') 
        then 'CD' end) = 'CD' 
        and  (case when so.tec_criteria in ('PI','MC') 
        then 'XX' else so.tec_criteria end) = 'OF'
        then sum(so.revised_qty_due)
    end) CD_OF_VOLUME
    from shop_order so
    left join scm_prodtyp sp
    on so.prodtyp = sp.prodtyp
    where so.order_type = 'MD' 
    and so.plant = 'W' 
    and so.status_code between '4' and '8' 
    and trunc(so.revised_due_date) <= trunc(sysdate)+30
    group by trunc(so.revised_due_date), so.tec_criteria, sp.pr_typ
    order by trunc(so.revised_due_date)
)
SELECT mydates.due_date, myorders.cd_of_volume
  FROM mydates LEFT JOIN myorders
    ON mydates.due_date = myorders.due_date;

如果您想在“缺失”日期上显示零而不是 NULL，请使用上面的 COALESCE(myorders.cd_of_volume, 0) AS cd_of_volume。

【参考方案2】：

您可以这样做： 用你需要的所有日子创建一个新表。

WITH DAYS AS
(SELECT TRUNC(SYSDATE) - ROWNUM DDD
 FROM ALL_OBJECTS
 WHERE ROWNUM < 365)
SELECT
  DAYS.DDD
FROM

  DAYS;

然后在两个表之间进行完全外连接：

select  DUE_DATE ,   CD_OF_VOLUME , DDD
from (
    select 
    (case when trunc(so.revised_due_date) <= trunc(sysdate) 
        then trunc(sysdate) else trunc(so.revised_due_date) end) due_date, 
    (case 
        when (case when sp.pr_typ in ('VV','VD') then 'DVD' when sp.pr_typ in ('RD','CD') 
        then 'CD' end) = 'CD' 
        and  (case when so.tec_criteria in ('PI','MC') 
        then 'XX' else so.tec_criteria end) = 'OF'
        then sum(so.revised_qty_due)
    end) CD_OF_VOLUME
    from shop_order so
    left join scm_prodtyp sp
    on so.prodtyp = sp.prodtyp
    where so.order_type = 'MD' 
    and so.plant = 'W' 
    and so.status_code between '4' and '8' 
    and trunc(so.revised_due_date) <= trunc(sysdate)+30
    group by trunc(so.revised_due_date), so.tec_criteria, sp.pr_typ
    order by trunc(so.revised_due_date)
)  full outer join   NEW_TABLE new on (    new .DDD =  DUE_DATE     )
  where new .DDD between   /* */   AND   /* */   /*   pick your own limit) */

【参考方案3】：

您可以使用connect by 和left join 获得gaps：

假设您的 架构 是：

create table tbl(DUE_DATE date, CD_OF_VOLUME float);
insert into tbl values(to_date('14/04/2015','DD/MM/YYYY'),35267.00);
insert into tbl values(to_date('15/04/2015','DD/MM/YYYY'),71744.00); 
insert into tbl values(to_date('16/04/2015','DD/MM/YYYY'),20268.00); 
insert into tbl values(to_date('17/04/2015','DD/MM/YYYY'),35156.00); 
insert into tbl values(to_date('18/04/2015','DD/MM/YYYY'),74395.00); 
insert into tbl values(to_date('19/04/2015','DD/MM/YYYY'),3636.00); 
insert into tbl values(to_date('21/04/2015','DD/MM/YYYY'),5522.00);
insert into tbl values(to_date('22/04/2015','DD/MM/YYYY'),15502.00);
insert into tbl values(to_date('04/05/2015','DD/MM/YYYY'),10082.00);

你可以说：

with cte as
(
  select (select min(DUE_DATE)-1 from tbl)+ level as dt
  from dual
  connect by level <= (select max(DUE_DATE)-min(DUE_DATE) from tbl)
)
select to_char(c.dt,'DD/MM/YYYY') gap,null volume 
from cte c
left join tbl t on c.dt=t.DUE_DATE
where t.DUE_DATE is null
order by c.dt

结果：

GAP         VOLUME
20/04/2015  (null)
23/04/2015  (null)
24/04/2015  (null)
25/04/2015  (null)
26/04/2015  (null)
27/04/2015  (null)
28/04/2015  (null)
29/04/2015  (null)
30/04/2015  (null)
01/05/2015  (null)
02/05/2015  (null)
03/05/2015  (null)

注意：您可以在原始查询中实现这一点，一种最简单的方法是包装您的查询并将其用作子查询，而不是上面代码中的 tbl - p.