如何根据另一个对象数组过滤一个对象数组？

Posted 2023-05-09

【中文标题】如何根据另一个对象数组过滤一个对象数组？

【英文标题】：How to filter an array of objects based on another array of objects?

【发布时间】：2019-09-30 08:06:49

【问题描述】：

我有两个对象数组，如下所示

conditions= [
          
            'condition': 'Expert',
            'value': 'All'
          ,
          
            'condition': 'Coach',
            'value': 'willaim'
          ,
          
            'condition': 'manager',
            'value': 'Brandy Lovings'
          ,
          
            'condition': 'site',
            'value': 'ALL'
          ,
          
            'condition': 'client',
            'value': 'ALL'
          
        ]

data=[

          "Date": "11/6/2018",
          "client": "Verizon",
          "Expert": "Ellison, Lauren",
          "Coach": "willaim",
          "manager": "Brandy Lovings",
          "site": "Sundance",
          "Metric": "STR"
        ,

          "Date": "11/6/2018",
          "client": "Amzaon",
          "Expert": "Ellison, Lauren",
          "Coach": "Dash Williamson",
          "manager": "David",
          "site": "abc",
          "Metric": "STR"
        
]

我想用条件数组过滤数据数组，比如如果条件数组中的条件属性包含专家，那么我需要根据data.Expert = conditions[Expert Conditionindex].value过滤数据数组然后我需要返回所有符合这个条件的数据。

另一件事是，如果 value: 'ALL' 则无需在该特定条件下进行过滤。

想要的输出是这样的

filteredData = [

              "Date": "11/6/2018",
              "client": "Verizon",
              "Expert": "Ellison, Lauren",
              "Coach": "willaim",
              "manager": "Brandy Lovings",
              "site": "Sundance",
              "Metric": "STR"
            
]

我该如何解决这个问题？

【参考方案1】：

您可以使用不带ALL 标志的条件子集进行过滤。

var conditions = [ condition: "Expert", value: "All" ,  condition: "Coach", value: "willaim" ,  condition: "manager", value: "Brandy Lovings" ,  condition: "site", value: "ALL" ,  condition: "client", value: "ALL" ],
    data = [ Date: "11/6/2018", client: "Verizon", Expert: "Ellison, Lauren", Coach: "willaim", manager: "Brandy Lovings", site: "Sundance", Metric: "STR" ,  Date: "11/6/2018", client: "Amzaon", Expert: "Ellison, Lauren", Coach: "Dash Williamson", manager: "David", site: "abc", Metric: "STR" ],
    filters = conditions.filter(( value ) => value.toUpperCase() !== 'ALL'),
    result = data.filter(o =>
        filters.every(( condition, value ) => o[condition] === value));
    
console.log(result);

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【参考方案2】：

这应该适合你：

    const conditionsObj=

    conditions.filter((value)=>value.toLowerCase()!=='all').forEach((condition)=>
          conditionsObj[condition.condition]=condition.value
        )



     const results=data.filter((item)=>
              let match=false;  
             Object.keys(conditionsObj).forEach((_key)=>
                if(conditionsObj[_key]===item[_key])
                  match=true;
                
              )
              return match;
            )

console.log(results)