根据角色类型来自 3 个表的分层数据

Posted 2023-05-08

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【中文标题】根据角色类型来自 3 个表的分层数据【英文标题】：Hierarchical data from 3 tables according to the role type 【发布时间】：2013-10-04 07:35:00 【问题描述】：

以下是我的表格：

[用户管理员]

UserId Int, UserName Varchar(200),AddedBy Int

UserId     EmpName           AddedBy
1          admin             0
2          SubAdmin1         1
3          Vikas             2
4          Mohit             3
5          Atul              4
6          Vishal            2
7          Mani              3
8          Sunny             1

[销售大师]

SalesId Int, UserId Int (FK_UserMaster_UserId) , Price Int

SalesId  UserId    Price         StatusId
10        1        100         1 
11        2        200         1    
12        3        300         1
13        4        500         1
14        5        100             2
15        6        200             1
16        7        111             2
17        8        222             1

[销售产品]

SaleProductId Int, SaleId Int (FK_SaleMaster_SaleId) , Quantity Int

SaleProductId    SalesId   Quantity

  1                10       2
  2                11       2
  3                12       1
  4                13       1
  5                14       3
  6                15       2
  7                16       5
  8                17       1

[输出]

结果集应该有登录用户的销售额+他创建的用户和他们的子用户创建的更多用户。

以下 TotalSalesAmount 是：

[SalesMaster].Price * [SalesProducts].Quantity

例如：UserId: 1 的总销售额是 100*2+200*2+ 300*1 + 500*1 +100*3 + 200*2 +111*5 + 222*1= 2877

同样对于 UserId: 2 是 200*2+300*1 + 200*2 +500*1 + 111*5 +200*2= 2555

案例一：

如果 (admin)UserId=1 将登录，我们需要显示以下内容

UserId     TotalSalesAmount    OwnSaleAmount           AddedBy

  1          2877         200               0

  2          2555         400               1

  3          1355             300               2

  4          800          500           3

  5          100*3= 300       300           4

  6          200*2=200        200           2

  7          111*5= 555       555               3

  8          222*1= 222       222           1

案例 2：如果 (Vikas)UserId=3 将登录，我们需要显示以下内容

 UserId      TotalSalesAmount           OwnSaleAmount           AddedBy

  3          300*1 + 500*1 + 111*5= 1355            300                2

  4          500*1 + 100*3= 800                     500                3

  5          100*3= 300                         300            4

  7          111*5= 555                     555                3

我用过的表格脚本和数据在这里 http://test-admin.teamberry.biz/SalesScript.rar ,

运行此脚本后请执行以下查询 take UM.UserId=164, SM.statusID = 1 UserId=166 的 TotalSalesAmount 出错了，因为它的 TotalSaleAmount 应该与 ownSaleAmount 相同，即 444，因为 UserId=166 没有任何孩子。

with tblOwnSaleAmount as 
 ( 
      select UM.UserId,UM.EmpName,UM.AddedBy,cast(sum( SM.Price*SP.Quantity) as int) as OwnSaleAmount 
      from UserMaster UM
      left join SalesMaster SM on SM.UserId = UM.UserId  and SM.statusID = 1
      left join SalesProducts SP on SP.SalesId = SM.SalesId
      where UM.UserId = 164
      group by  UM.UserId ,UM.AddedBy,UM.EmpName 
      union all 
      select UM.UserId,UM.EmpName, UM.AddedBy, 
      case when SM.statusID = 1 then cast(( SM.Price*SP.Quantity ) as int)
      else 0 end as OwnSaleAmount
      from UserMaster UM
      join tblOwnSaleAmount on tblOwnSaleAmount.UserId = UM.AddedBy
      join SalesMaster SM on SM.UserId = UM.UserId 
      join SalesProducts SP on SP.SalesId = SM.SalesId 
 )
,  tbldistinctOwnSaleAmount as
 (
 select distinct UserId,EmpName, AddedBy,Isnull(OwnSaleAmount,0) as  OwnSaleAmount
 from tblOwnSaleAmount
 )
 ,

 tblTotalOwnSaleAmount as
 (
  select OSA.UserId,OSA.EmpName, OSA.AddedBy, sum( OSA.OwnSaleAmount ) as OwnSaleAmount
  from tbldistinctOwnSaleAmount OSA --inner join tbldistinctOwnSaleAmount A on OSA.AddedBy = A.UserID
  group by OSA.UserId ,OSA.AddedBy,OSA.EmpName
 )
 select OSA.* 
, TotalSalesAmount = isnull(
( 
    select sum( OSA1.OwnSaleAmount )
    from tblTotalOwnSaleAmount OSA1
    where OSA1.UserId > OSA.UserId 
), 0 )
+ OSA.OwnSaleAmount
 from tblTotalOwnSaleAmount OSA  
 order by OSA.UserId

【问题讨论】：

【参考方案1】：

如果我的理解有误，请更新：

对于用户 ID 3，您已使用 TotalSalesAmount = 300*1 + 500*1 + 111*5（不包括用户 ID 5 的销售金额，而用户 ID 4 的子用户又为用户 ID 3 创建了销售金额）。所以 TotalSalesAmount 对于用户 ID 3，应计算为：300*1 + 500*1 +300*1 + 111*5 = 1655 而不是 1355。

如果我的上述理解是正确的，你可以通过使用公用表表达式的递归能力得到想要的结果，然后计算出运行总计：

-- create a common table expression to get OwnSaleAmount for logged in user and all the users who are added 由当前用户和更多。

 with tblOwnSaleAmount as 
 ( 
      select UM.UserId, UM.AddedBy, ( SM.Price*SP.Quantity ) as OwnSaleAmount 
      from UserMaster UM
      join SalesMaster SM on SM.UserId = UM.UserId 
      join SalesProducts SP on SP.SaleId = SM.SalesId 
      where UM.UserId = 1 -- Userid of logged in user which will act as anchor member 
                          -- for later subqueries
      union all 

      select UM.UserId, UM.AddedBy, ( SM.Price*SP.Quantity ) as OwnSaleAmount  
      from UserMaster UM
      join tblOwnSaleAmount on tblOwnSaleAmount.UserId = UM.AddedBy
      join SalesMaster SM on SM.UserId = UM.UserId 
      join SalesProducts SP on SP.SaleId = SM.SalesId 

 )
 select OSA.* 
, TotalSalesAmount = isnull(
( 
    select sum( OSA1.OwnSaleAmount )
    from tblOwnSaleAmount OSA1
    where OSA1.AddedBy > = OSA.UserId                                                                   
), 0 )
+ OSA.OwnSaleAmount
 from tblOwnSaleAmount OSA
 order by OSA.UserId

编辑：更新查询：

 --1. Corrected joins in anchor query to fetch records for users who have no records in SalesMaster Table.
 --2. IS it another requirement that user entries with status id = 2 should not be considered?
 with tblOwnSaleAmount as 
 ( 
      select UM.UserId, UM.AddedBy, sum( SM.Price*SP.Quantity ) as OwnSaleAmount 
      from UserMaster UM
      left join SalesMaster SM on SM.UserId = UM.UserId -- Missed requirement1
      left join SalesProducts SP on SP.SaleId = SM.SalesId -- Missed requirement1
      where UM.UserId = 2 -- Userid of logged in user which will act as anchor member 
      group by  UM.UserId ,UM.AddedBy                  -- for later subqueries

      union all 

      select UM.UserId, UM.AddedBy, ( SM.Price*SP.Quantity ) as OwnSaleAmount  
      from UserMaster UM
      join tblOwnSaleAmount on tblOwnSaleAmount.UserId = UM.AddedBy
      join SalesMaster SM on SM.UserId = UM.UserId 
      join SalesProducts SP on SP.SaleId = SM.SalesId 

 ),
  tbldistinctOwnSaleAmount as
 (
 select distinct UserId, AddedBy, OwnSaleAmount 
 from tblOwnSaleAmount
 ) ,
 tblTotalOwnSaleAmount as
 (
  select OSA.UserId,OSA.AddedBy, sum( OSA.OwnSaleAmount ) as OwnSaleAmount
  from tbldistinctOwnSaleAmount OSA
  group by OSA.UserId ,OSA.AddedBy
 )
 select OSA.* 
, TotalSalesAmount = isnull(
( 
    select sum( OSA1.OwnSaleAmount )
    from tblTotalOwnSaleAmount OSA1
    where OSA1.UserId > OSA.UserId                                                                   
), 0 )
+ OSA.OwnSaleAmount
 from tblTotalOwnSaleAmount OSA
 order by OSA.UserId

希望对你有帮助！！！

[EDIT2]：更新了遗漏要求 2 的查询：

 --2. IS it another requirement that user entries with status id = 2 should not be considered? -- Yes!!!
 with tblOwnSaleAmount as 
 ( 
      select UM.UserId, UM.AddedBy, sum( SM.Price*SP.Quantity ) as OwnSaleAmount 
      from UserMaster UM
      left join SalesMaster SM on SM.UserId = UM.UserId  and SM.statusID = 1-- Missed requirement1 and 2
      left join SalesProducts SP on SP.SaleId = SM.SalesId -- Missed requirement1
      where UM.UserId = 2 -- Userid of logged in user which will act as anchor member 
      group by  UM.UserId ,UM.AddedBy                  -- for later subqueries

      union all 

      select UM.UserId, UM.AddedBy, 
      case when SM.statusID = 1 then ( SM.Price*SP.Quantity ) 
      else 0 end as OwnSaleAmount  --Missed Requirement 2.
      from UserMaster UM
      join tblOwnSaleAmount on tblOwnSaleAmount.UserId = UM.AddedBy
      join SalesMaster SM on SM.UserId = UM.UserId 
      join SalesProducts SP on SP.SaleId = SM.SalesId 

 ),
  tbldistinctOwnSaleAmount as
 (
 select distinct UserId, AddedBy, OwnSaleAmount 
 from tblOwnSaleAmount
 ) ,
 tblTotalOwnSaleAmount as
 (
  select OSA.UserId,OSA.AddedBy, sum( OSA.OwnSaleAmount ) as OwnSaleAmount
  from tbldistinctOwnSaleAmount OSA
  group by OSA.UserId ,OSA.AddedBy
 )
 select OSA.* 
, TotalSalesAmount = isnull(
( 
    select sum( OSA1.OwnSaleAmount )
    from tblTotalOwnSaleAmount OSA1
    where OSA1.UserId > OSA.UserId                                                                   
), 0 )
+ OSA.OwnSaleAmount
 from tblTotalOwnSaleAmount OSA
 order by OSA.UserId

要获得正确的结果，您需要更新锚表的 on 谓词，然后为进一步的递归表添加 case 语句。

【讨论】：

感谢您的宝贵反馈。它对我有用，除了我在查询中做了一点更改，我已将 Additionalby 更改为 UserId select OSA.* ， TotalSalesAmount = isnull( ( select sum( OSA1.OwnSaleAmount ) from tblOwnSaleAmount OSA1 where OSA1.UserId > = OSA.UserId - -ctm), 0) 请查看... 如果登录用户在 SalesMaster 表中没有记录，则查询返回零结果。此外，如果 SalesMaster 表具有相同 UserID 的多个条目，那么结果也是不正确的。提前致谢。嗨..刚刚看到您更新的要求。你还在寻找答案吗？好吧，我必须对你的 SQL 技能说“脱帽致敬”。是的，我仍在寻找查询。你能回答***.com/revisions/19362433/2 根据您的要求更新查询。不应该考虑状态 id = 2 的用户条目是另一个要求吗？

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