如何防止猜数字游戏中的重复猜测?
Posted
技术标签:
【中文标题】如何防止猜数字游戏中的重复猜测?【英文标题】:How do I prevent duplicate guesses in number guessing game? 【发布时间】:2021-08-15 16:17:32 【问题描述】:我创建了一个名为尝试收集用户猜到的数字的数组。当用户最终猜出正确的数字时,将尝试次数和猜中的数字告诉用户。我如何避免用户猜测他们已经猜到的数字?我知道每次猜测后我都必须检查数组,看看这个数字是否已经被猜到并且在数组中。 (如果guess 在数组中,显示消息“你已经猜到了,再试一次”)另外,我应该将该猜测添加到猜测数中还是不包括它,因为它是重复猜测?
let num = Math.floor(Math.random() * 20) + 1;
console.log(num);
let num_guess = 0
let tries = []
function do_guess()
let guess = Number(document.getElementById("guess").value);
let message = document.getElementById("message");
if (isNaN(guess))
message.innerhtml = 'That is not a number!';
else if (guess > 20)
message.innerHTML = 'That number is not in range, try again.';
num_guess++
tries.push(guess)
else if (guess > num)
message.innerHTML = "No, try a lower number.";
num_guess++
tries.push(guess)
else if (guess < num)
message.innerHTML = "No, try a higher number.";
num_guess++
tries.push(guess)
else if (guess == num)
num_guess++
tries.push(guess)
message.innerHTML = "You got it! It took you " + num_guess + " tries and your guesses were " + tries + ".";
【问题讨论】:
至于是否在猜测次数中包含重复猜测 - 这取决于您以及您希望游戏如何运行。您已将超出范围的值计数为猜测,所以..... 【参考方案1】:简单,使用Array.includes
:
[1, 2, 3].includes(1)
> true
[1, 2, 3].includes(4)
> false
关于是否要包含重复的猜测:由您决定。
【讨论】:
【参考方案2】:您可以使用includes 来检查一个元素是否存在于数组中。
includes() 方法判断一个数组是否包含某个 其条目之间的值,根据需要返回 true 或 false。
你需要在所有条件之前添加以下代码
if (tries.includes(guess))
message.innerHTML = "You guessed that already, try again";
let num = Math.floor(Math.random() * 20) + 1;
console.log(num);
let num_guess = 0;
let tries = [];
const guessContainer = document.getElementById("guess");
const check = document.getElementById("check");
let message = document.getElementById("message");
guessContainer.addEventListener("keyup", (e) =>
message.innerHTML = "";
);
function do_guess()
let guess = Number(guessContainer.value);
let isCorrect = false;
if (tries.includes(guess))
message.innerHTML = "You guessed that already, try again";
else if (isNaN(guess))
message.innerHTML = "That is not a number!";
else if (guess > 20)
message.innerHTML = "That number is not in range, try again.";
num_guess++;
tries.push(guess);
else if (guess > num)
message.innerHTML = "No, try a lower number.";
num_guess++;
tries.push(guess);
else if (guess < num)
message.innerHTML = "No, try a higher number.";
num_guess++;
tries.push(guess);
else if (guess == num)
isCorrect = true;
num_guess++;
tries.push(guess);
message.innerHTML =
"You got it! It took you " +
num_guess +
" tries and your guesses were " +
tries +
".";
if (isCorrect)
message.classList.add("right");
message.classList.remove("wrong");
else
message.classList.add("wrong");
message.classList.remove("right");
check.addEventListener("click", do_guess);
body
padding: 1rem;
button
background-color: indianred;
color: white;
border: none;
padding: .25rem .5rem;
border-radius: 4px;
text-transform: uppercase;
.wrong
color: tomato;
.right
color: green;
h5
margin-top: 1rem;
<input type="text" id="guess" />
<button id="check">check</button>
<h5 id="message"></h5>
【讨论】:
接受答案,如果它是你所期待的......【参考方案3】:试试这个:
var num = Math.floor(Math.random() * 20) + 1;
console.log(num);
var num_guess = 0;
var tries = [];
function go_guess()
let guess = Number(document.getElementById("guess").value);
let message = document.getElementById("message");
if(tries.includes(guess))
message.innerText = "You guessed that already, try again";
else
if (isNaN(guess))
message.innerHTML = 'That is not a number!';
else if (guess > 20)
message.innerHTML = 'That number is not in range, try again.';
num_guess++;
tries.push(guess);
else if (guess > num)
message.innerHTML = "No, try a lower number.";
num_guess++;
tries.push(guess);
else if (guess < num)
message.innerHTML = "No, try a higher number.";
num_guess++;
tries.push(guess);
else if (guess == num)
let _tries = `$tries[0]`;
for(let i = 1;i<tries.length;i++)
_tries += `, $tries[i]`;
num_guess++;
message.innerText = `You got it! It took you $num_guess tries and your guesses were $_tries.`;
;
);
【讨论】:
以上是关于如何防止猜数字游戏中的重复猜测?的主要内容,如果未能解决你的问题,请参考以下文章