Access 2010：查询表达式中的语法错误（缺少运算符）

Posted 2023-05-07

【中文标题】Access 2010：查询表达式中的语法错误（缺少运算符）

【英文标题】：Access 2010: Syntax error (missing operator) in query expression

【发布时间】：2012-06-01 14:48:43

【问题描述】：

我想在我的 sql 查询中包含三个表，但我收到一条错误消息。

我有这个 sql 代码：

 SELECT warehouse.expiry_date, pharmacy.expiry_date, drugs.active_substance, 
 drugs.strength, drugs.strength_type, drugs.dosage_form, drugs.minimum_quantity, 
 SUM(warehouse.in_quant)+SUM(pharmacy.in_quant)-SUM(warehouse.out_quant)-
 SUM(pharmacy.out_quant) AS Total_available_stock

 FROM drugs as a 
  INNER JOIN warehouse as b
    ON a.ID = b.drug_id 
  INNER JOIN pharmacy as c 
    ON b.drug_id = c.drug_id
 GROUP BY warehouse.expiry_date, pharmacy.expiry_date, drugs.active_substance, 
 drugs.strength, drugs.strength_type, drugs.dosage_form, drugs.minimum_quantity;

我得到了错误：

 Syntax error (missing operator) in query expression in 'a.ID = b.drug_id 
 INNER JOIN pharmacy as c
     on b.drug_id = c.drug_i'.

有什么帮助吗？

【参考方案1】：

在 Access 中，如果您有多个联接，则需要括号：

FROM (drugs as a 
  INNER JOIN warehouse as b
    ON a.ID = b.drug_id) 
  INNER JOIN pharmacy as c 
    ON b.drug_id = c.drug_id

【参考方案2】：

只是想补充一点，当您有超过 2 个内连接时，它会变得更加混乱。然后你需要在每个内连接的开头和结尾添加一个额外的括号（最后一个除外）

例子：

 FROM ((drugs as a 
  INNER JOIN warehouse as b
    ON a.ID = b.drug_id) 
  INNER JOIN pharmacy as c1 
    ON b.drug_id1 = c1.drug_id)
  INNER JOIN pharmacy as c2 
    ON b.drug_id2 = c2.drug_id