Microsoft Access/SQL 错误参数框

Posted 2023-04-19

【中文标题】Microsoft Access/SQL 错误参数框

【英文标题】：Microsoft Access/SQL Mistaken Parameter Box

【发布时间】：2014-05-05 16:30:40

【问题描述】：

我在 MS Access 2010 中工作，以便能够使用我们存储在专有数据库中的数据运行我自己的查询/报告。我将此查询编写为两个子查询，每个子查询都可以完美地独立运行。但是，当我一起运行它们时，我得到一个参数输入框，说我需要为 Query4.company_id 输入一个参数。我仔细检查了拼写错误，所以情况似乎并非如此。我认为我的子查询连接到我的主查询的方式一定有问题。我是一个新手，但很高兴得到您的任何建议！这是我的查询：

选择 dbo_Companies.company_id、dbo_Companies.company_name、dbo_Lease.lease_from_dt、dbo_Lease.lease_to_dt、dbo_Lease.lease_status、dbo_Lease.lease_description、dbo_Companies.company_status

从 dbo_Companies 左加入 dbo_Lease ON dbo_Companies.company_id = dbo_Lease.company_id

在哪里（（（dbo_Companies.company_id）在

(SELECT dbo_Companies.company_id

FROM (dbo_Companies INNER JOIN dbo_CompanyFacilities ON dbo_Companies.company_id = dbo_CompanyFacilities.company_id) INNER JOIN dbo_Facilities ON dbo_CompanyFacilities.facility_id = dbo_Facilities.facility_id

WHERE (((dbo_CompanyFacilities.facility_id)=11 或 (dbo_CompanyFacilities.facility_id)=13 或 (dbo_CompanyFacilities.facility_id)=14 或 (dbo_CompanyFacilities.facility_id)=15 或 (dbo_CompanyFacilities.facility_id)=21 或 (dbo_CompanyFacilities.facility_id)=28 或 (dbo_CompanyFacilities.facility_id)=24 或 (dbo_CompanyFacilities.facility_id)=27 或 (dbo_CompanyFacilities.facility_id)=31 或 (dbo_CompanyFacilities.facility_id)=32 或 (dbo_CompanyFacilities.facility_id)=33 或 (dbo_CompanyFacilities.facility_id)=37) AND (dbo_Companies.company_status = "Active") AND (((dbo_Companies.company_class_id)=1) OR ((dbo_Companies.company_class_id)= 14))))));

【参考方案1】：

试试这个：

SELECT 
  C.company_id, 
  C.company_name, 
  L.lease_from_dt, 
  L.lease_to_dt, 
  L.lease_status, 
  L.lease_description, 
  C.company_status

FROM dbo_Companies C 

LEFT JOIN dbo_Lease L 
  ON C.company_id = L.company_id

WHERE C.company_id IN

(SELECT C2.company_id

FROM dbo_Companies C2 
INNER JOIN dbo_CompanyFacilities CF 
  ON C2.company_id = CF.company_id 
INNER JOIN dbo_Facilities F 
  ON CF.facility_id = F.facility_id

WHERE 
  CF.facility_id IN (11, 13, 14, 15, 21, 28, 24, 27, 31, 32, 33, 37) 
  AND C2.company_status = "Active" 
  AND C2.company_class_id IN (1, 14)
);

要对此进行测试，请先运行第二个 SELECT 语句（括号内的那个）并查看是否得到任何结果。如果是这样，请运行整个代码块，看看是否仍然出现该错误。在对数据一无所知的情况下，它看起来应该可以正常运行。

【讨论】：

非常感谢您的回答！运行第二个 SELECT 语句时，MS Access 向我抛出了一个语法错误（缺少运算符），处理后半部分的 FROM 部分。我也会继续寻找和修补——你的指导真的很有帮助。