我正在尝试使用意图导航到多个活动,但我遇到了运行时异常,我是 eclipse 的初学者,所以请指导我
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【中文标题】我正在尝试使用意图导航到多个活动,但我遇到了运行时异常,我是 eclipse 的初学者,所以请指导我【英文标题】:I am trying to navigate to multiple activities using intents and i am getting a run time exception, I am a beginner with eclipse , so please guide me 【发布时间】:2016-01-28 17:53:22 【问题描述】:MainActivity.java
public class MainActivity extends Activity
@Override
protected void onCreate(Bundle savedInstanceState)
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
final EditText txtUserName = (EditText)findViewById(R.id.editText1);
final EditText txtPassword = (EditText)findViewById(R.id.editText2);
Button btnLogin = (Button)findViewById(R.id.button1);
btnLogin.setOnClickListener(new OnClickListener()
@Override
public void onClick(View v)
String username = txtUserName.getText().toString();
String password = txtPassword.getText().toString();
String foo = new String("131031001");
String foo2 = new String("131031002");
String foo3 = new String("131031003");
String foo4 = new String("131031004");
String foo5 = new String("131031005");
try
if(username.length() > 0 && password.length() >0)
DBUserAdapter dbUser = new DBUserAdapter(MainActivity.this);
dbUser.open();
dbUser.AddUser();
if(dbUser.Login(username, password))
Toast.makeText(MainActivity.this,"Successfully Logged In", Toast.LENGTH_LONG).show();
if(username.equals(foo))
Intent nextActivity2 = new Intent(getApplicationContext(),SecondActivity.class);
nextActivity2.putExtra("Second",username);
startActivity(nextActivity2);
else if(username.equals(foo2))
Intent nextActivity3 = new Intent(getBaseContext(),ThirdActivity.class);
nextActivity3.putExtra("Third",username);
startActivity(nextActivity3);
else if(username.equals(foo3))
Intent nextActivity4 = new Intent(getBaseContext(),FourthActivity.class);
nextActivity4.putExtra("Fourth",username);
startActivity(nextActivity4);
else if(username.equals(foo4))
Intent nextActivity5 = new Intent(getBaseContext(),FifthActivity.class);
nextActivity5.putExtra("Fifth",username);
startActivity(nextActivity5);
else if(username.equals(foo5))
Intent nextActivity6 = new Intent(getBaseContext(),SixthActivity.class);
nextActivity6.putExtra("Sixth",username);
startActivity(nextActivity6);
else
Toast.makeText(MainActivity.this,"Result does not exist! Try later!!", Toast.LENGTH_LONG).show();
else
Toast.makeText(MainActivity.this,"Invalid Username/Password", Toast.LENGTH_LONG).show();
dbUser.close();
catch(Exception e)
Toast.makeText(MainActivity.this,e.getMessage(), Toast.LENGTH_LONG).show();
);
Button btreg = (Button)findViewById(R.id.button2);
btreg.setOnClickListener(new OnClickListener()
@Override
public void onClick(View v)
Intent nextActivity = new Intent(getApplicationContext(),Register.class);
startActivity(nextActivity);
);
SecondActivity.java
public class SecondActivity extends Activity
Intent intent = getIntent();
@Override
protected void onCreate(Bundle savedInstanceState)
super.onCreate(savedInstanceState);
setContentView(R.layout.second_activity);
所有其他活动的编码与上述类似。 这是我的日志。
10-28 14:53:10.688: E/androidRuntime(1196): Process: com.skcetresults, PID: 1196
10-28 14:53:10.688: E/AndroidRuntime(1196): java.lang.RuntimeException: Unable to start activity ComponentInfocom.skcetresults/com.skcetresults.SecondActivity: java.lang.NullPointerException
10-28 14:53:10.688: E/AndroidRuntime(1196): at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:2176)
10-28 14:53:10.688: E/AndroidRuntime(1196): at android.app.ActivityThread.handleLaunchActivity(ActivityThread.java:2226)
10-28 14:53:10.688: E/AndroidRuntime(1196): at android.app.ActivityThread.access$700(ActivityThread.java:135)
10-28 14:53:10.688: E/AndroidRuntime(1196): at android.app.ActivityThread$H.handleMessage(ActivityThread.java:1397)
10-28 14:53:10.688: E/AndroidRuntime(1196): at android.os.Handler.dispatchMessage(Handler.java:102)
10-28 14:53:10.688: E/AndroidRuntime(1196): at android.os.Looper.loop(Looper.java:137)
10-28 14:53:10.688: E/AndroidRuntime(1196): at android.app.ActivityThread.main(ActivityThread.java:4998)
10-28 14:53:10.688: E/AndroidRuntime(1196): at java.lang.reflect.Method.invokeNative(Native Method)
10-28 14:53:10.688: E/AndroidRuntime(1196): at java.lang.reflect.Method.invoke(Method.java:515)
10-28 14:53:10.688: E/AndroidRuntime(1196): at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:777)
10-28 14:53:10.688: E/AndroidRuntime(1196): at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:593)
10-28 14:53:10.688: E/AndroidRuntime(1196): at dalvik.system.NativeStart.main(Native Method)
10-28 14:53:10.688: E/AndroidRuntime(1196): Caused by: java.lang.NullPointerException
10-28 14:53:10.688: E/AndroidRuntime(1196): at com.skcetresults.SecondActivity.onCreate(SecondActivity.java:15)
10-28 14:53:10.688: E/AndroidRuntime(1196): at android.app.Activity.performCreate(Activity.java:5243)
10-28 14:53:10.688: E/AndroidRuntime(1196): at android.app.Instrumentation.callActivityOnCreate(Instrumentation.java:1087)
10-28 14:53:10.688: E/AndroidRuntime(1196): at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:2140)
10-28 14:53:10.688: E/AndroidRuntime(1196): ... 11 more
只有两个意图,代码运行良好,但是当我将值与字符串进行比较时,应用程序崩溃了,我不知道错误在哪里。
【问题讨论】:
将 Intent intent = getIntent(); 放入 onCreate() 方法中。 SecondActivity 中的第 15 行是什么? 【参考方案1】:使用 MainActivity.this 作为上下文,而不是 getBaseContext() 和 getApplicationContext(),可以在任何地方工作。
【讨论】:
【参考方案2】:你应该这样写
public class SecondActivity extends Activity
@Override
protected void onCreate(Bundle savedInstanceState)
super.onCreate(savedInstanceState);
setContentView(R.layout.second_activity);
Intent i = getIntent();
如果额外的数据是字符串,你可以像这样得到它:
String nameString = i.getStringExtra("nameExtra");
【讨论】:
感谢您的输入,但是当我更改为 MainActivity.this 而不是 getBaseContext() 和 getApplicationContext() 时应用程序开始工作【参考方案3】:您不能在 onCreate() 之前使用 getIntent(),此时根本没有可用的 Intent。
在您的代码中,我怀疑您正在尝试获取StringExtras from Intent
,但由于intent 为空,它正在抛出NullPointerException
。
在您的Second Activity
中,您可以在onCreate()
方法中使用getIntent()
。
public class SecondActivity extends Activity
Intent intent;
@Override
protected void onCreate(Bundle savedInstanceState)
super.onCreate(savedInstanceState);
setContentView(R.layout.second_activity);
intent = getIntent();
String userName = intent.getStringExtra("Second");
...
【讨论】:
感谢您的输入,但是当我更改为 MainActivity.this 而不是 getBaseContext() 和 getApplicationContext() 时应用程序开始工作【参考方案4】:使用少量代码检查,以确保您的意图行为正常。例如,您可以用if
语句包围您的getIntent
代码。对于调用哪个正确的方法,您必须四处逛逛,因为这取决于您希望您的应用程序做什么。幸运的是,当您写下一些 Android 资源时,Eclipse 会为您提供所有相关文档,例如Intent
。
【讨论】:
感谢您的输入,但是当我更改为 MainActivity.this 而不是 getBaseContext() 和 getApplicationContext() 时应用程序开始工作以上是关于我正在尝试使用意图导航到多个活动,但我遇到了运行时异常,我是 eclipse 的初学者,所以请指导我的主要内容,如果未能解决你的问题,请参考以下文章