我如何在 android 中显示从 listView 到第二个活动的相同数据，如果我点击 google，它会在第二个活动中显示 google

Posted 2023-04-19

【中文标题】我如何在 android 中显示从 listView 到第二个活动的相同数据，如果我点击 google，它会在第二个活动中显示 google

【英文标题】：How i can show same data from listView to second activity in android like, if i clicked on google , it show google on second activity

【发布时间】：2018-05-23 14:11:35

【问题描述】：

此代码使用 listView 中的 wamp 服务器从数据库中获取数据，但如果我单击第 1 行，它会在第二个活动上显示第 1 行，如果我单击 2，它会在第二个活动上显示第 2 行，我必须这样做，

import android.content.Intent;
import android.graphics.Color;
import android.os.AsyncTask;
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.view.View;
import android.widget.AdapterView;
import android.widget.ArrayAdapter;
import android.widget.ListView;
import android.widget.TextView;
import android.widget.Toast;

import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.net.HttpURLConnection;
import java.net.URL;

public class attendence extends AppCompatActivity 

    ListView listView;

    @Override
    protected void onCreate(Bundle savedInstanceState) 
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_attendence);

        String name = getIntent().getExtras().getString("username");
        getJSON("http://192.168.0.102/A/select.php" + "?username=" + name);
        listView = (ListView) findViewById(R.id.LV);

        // TextView txtname = (TextView) findViewById(R.id.txt_success_name);
        //
        // Intent intent = getIntent();
        // String loginName = intent.getStringExtra("username");
        // txtname.setText("Welcome, " +loginName);
    

    private void getJSON(final String urlWebService) 

        class GetJSON extends AsyncTask<Void, Void, String> 

            @Override
            protected void onPreExecute() 
                super.onPreExecute();
            

            @Override
            protected void onPostExecute(String s) 
                super.onPostExecute(s);
                Toast.makeText(getApplicationContext(), s, Toast.LENGTH_SHORT).show();
                try 

                    loadIntoListView(s);
                 catch (JSONException e) 

                    e.printStackTrace();
                
            

            @Override
            protected String doInBackground(Void... voids) 
                try 
                    URL url = new URL(urlWebService);
                    HttpURLConnection con = (HttpURLConnection) url.openConnection();
                    StringBuilder sb = new StringBuilder();
                    BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(con.getInputStream()));
                    String json;
                    while ((json = bufferedReader.readLine()) != null) 
                        sb.append(json + "\n");
                    
                    return sb.toString().trim();
                 catch (Exception e) 
                    return null;
                
            
        
        GetJSON getJSON = new GetJSON();
        getJSON.execute();

    

    //
    private void loadIntoListView(String json) throws JSONException 
        JSONObject object = new JSONObject(json);
        JSONArray jsonArray = object.getJSONArray("Result");
        String[] heroes = new String[jsonArray.length()];
        for (int i = 0; i < jsonArray.length(); i++) 
            JSONObject obj = jsonArray.getJSONObject(i);
            heroes[i] = obj.getString("ID") + " " + obj.getString("STATUS") + "  " + obj.getString("ATD_DATE");
            if (!obj.getString("STATUS").toString().equals("A")) 
                listView.setOnItemClickListener(new AdapterView.OnItemClickListener() 
                    @Override
                    public void onItemClick(AdapterView<?> parent, View view, int position, long id) 
                        Intent i = new Intent(attendence.this, atd_leave_form.class);
                        startActivity(i);
                    
                );
             else 

            

            // Toast.makeText(getApplication(),"GREEN",Toast.LENGTH_LONG).show();
            // listView.setBackgroundColor(Color.GREEN);
        
        ArrayAdapter<String> arrayAdapter = new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, heroes);
        listView.setAdapter(arrayAdapter);
    

我只想显示我在 android 的列表视图中单击的相同单个数据。 提前感谢您的帮助。

【参考方案1】：

通过使用意图，您必须在 onItemClick 方法中实现它

查看Passing Data between activities

你也可以在android site找到有用的信息