数组中每个类别的总和

Posted 2023-04-18

【中文标题】数组中每个类别的总和

【英文标题】：Total Sum for each category in an array

【发布时间】：2021-10-07 17:29:19

【问题描述】：

我有一个包含多个项目的数组。以下是我的数组结构：

列出 ListCateory (

[0] ListName 
    name = Salary;
    amount = 40000;
    date = 2020-05-01 16:00:00 +0000;
    Category = Main Incomes;
    Type = Income;
,
[1] ListName
    name = Diff;
    amount =1500;
    date = 2020-05-22 16:00:00 +0000;
    Category= Misc;
    Type = Expense;
,
[2] ListName
    name = Food;
    amount =100;
    date = 2020-05-18 16:00:00 +0000;
    Category = Grocery;
    Type = Expense;
,
[3] ListName
    name =  Food;
    amount = 600;
    date = 2020-05-24 16:00:00 +0000;
    Category= Grocery;
    Type = Expense;

[4] ListName
    name = Travel;
    amount =400;
    date = 2020-05-18 16:00:00 +0000;
    Category = Travel;
    Type = Expense;
,

)

下面的代码得到总收入和支出

` Long totalExpense = 0l; 长总收入 = 0l;

    for (int i = 0; i < cexpenses.size(); i++) 

        if (cexpenses.get(i).getType().contains("Income")  ) 
           totalIncome += cexpenses.get(i).getAmount();
         else  if (cexpenses.get(i).getType().equals("Expense")  ) 
            totalExpense += cexpenses.get(i).getAmount();
        
    

    
    System.out.println("Expense " + totalExpense);
    System.out.println("Income " + totalIncome);

但我无法获得每个类别的总金额。所需的输出是一个数组，其中包含每个类别的总数，如下所示：

[0] X-Array 
    category = Main Incomes;
    amount = XXXX;
;
[1] X-Array 
    category = Grocery;
    amount = XXXX;
 ;

' 任何帮助将不胜感激

【参考方案1】：

试试这个。

enum Category  MainIncomes, Misc, Grocery, Travel 
enum Type  Income, Expense 

record Item(String name, int amount, String date, Category category, Type type) 

public static void main(String[] args) 
    List<Item> list = List.of(
        new Item("Salary", 40000, "2020-05-01 16:00:00 +0000", Category.MainIncomes, Type.Income),
        new Item("Diff", 1500, "2020-05-22 16:00:00 +0000", Category.Misc, Type.Expense),
        new Item("Food", 100, "2020-05-18 16:00:00 +0000", Category.Grocery, Type.Expense),
        new Item("Food", 600, "2020-05-24 16:00:00 +0000", Category.Grocery, Type.Expense),
        new Item("Travel", 400, "2020-05-18 16:00:00 +0000", Category.Travel, Type.Expense));
    Map<Category, Integer> totalSum = list.stream()
        .collect(Collectors.groupingBy(Item::category,
            Collectors.summingInt(Item::amount)));
    System.out.println(totalSum);

输出：

Grocery=700, MainIncomes=40000, Misc=1500, Travel=400

您可以使用class Item 代替record Item。

public class Item 
    String name;
    int amount;
    String date;
    Category category;
    Type type;

    public Item(String name, int amount, String date, Category category, Type type) 
        this.name = name;
        this.amount = amount;
        this.date = date;
        this.category = category;
        this.type = type;
    

    public String name()  return name; 
    public int amount()  return amount; 
    public String date()  return date; 
    public Category category()  return category; 
    public Type type()  return type; 

【讨论】：

这是一种更简洁的解决方案，可以在不创建中间集合的情况下收集总金额。

【参考方案2】：

假设您有一份费用清单：

List<Expense> expenses = ...

首先，将它们按类别分组，如下所示：

Map<String, List<Expense>> expensesByCategory =
    expenses.stream().collect(Collectors.groupingBy(Expense::getCategory));

然后，您可以遍历每个类别并做任何您想做的事情，例如，计算每个类别的总和：

for (String category : expensesByCategory.keySet()) 
    List<Expense> categoryExpenses = expensesByCategory.get(category);
    System.out.println(sum(categoryExpenses));

【讨论】：

我收到错误错误：找不到符号 System.out.println(sum(categoryExpenses)); ^ 符号：方法 sum(List)

sum函数不存在，我离开了这个函数的实现，因为你已经有一个可以计算总和的代码