访问联系人的联系电话

Posted 2023-04-15

【中文标题】访问联系人的联系电话

【英文标题】：access the contact number of a contact

【发布时间】：2011-07-11 02:35:44

【问题描述】：

我无法。 我从网上得到这个代码

Intent intent = new Intent(Intent.ACTION_PICK);           
            intent.setType(ContactsContract.Contacts.CONTENT_TYPE);           
            startActivityForResult(intent, PICK_CONTACT);           
            break;      
              
        



public void onActivityResult(int requestCode, int resultCode, Intent intent)      
    if (requestCode == PICK_CONTACT)   
                    
        Cursor cursor =  managedQuery(intent.getData(), null, null, null, null);       
        cursor.moveToNext();       
        String contactId = cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts._ID));        
        String  name = cursor.getString(cursor.getColumnIndexOrThrow(ContactsContract.Contacts.DISPLAY_NAME));         
        Toast.makeText(this, "Contect LIST  =  "+name, Toast.LENGTH_LONG).show();    

     

但它只显示联系人的姓名。 我想要联系人的电话号码。

【参考方案1】：

查看这篇文章，它有您正在寻找的答案：Read all contact's phone numbers in android

【讨论】：

上面的代码 sn-p 处理 Intent 而您发布的链接描述了有关使用 api 获取联系方式的详细信息。他们完全不同！

两者都使用从联系人查询返回的光标。您是否暗示由于查询是在 onActvityResult 中进行的，所以 Contact 的属性发生了变化？

谢谢！该链接也帮助我了解了其他一些事情。 :)

【参考方案2】：

修改你的代码sn-p

    Intent intent = new Intent(Intent.ACTION_PICK);                          
    intent.setType(ContactsContract.Contacts._ID);                          
    startActivityForResult(intent, PICK_CONTACT);                          
    break;                     
                         
             
     public void onActivityResult(int requestCode, int resultCode, Intent intent)  
              if (requestCode == PICK_CONTACT)         
     Cursor cursor =  managedQuery(Email.CONTENT_URI, null, Email.CONTACT_ID +  " = " + intent.getData(), null, null);                 
cursor.moveToNext();                 
    String contactId = cursor.getString(cursor.getColumnIndex(Email._ID));
    String  name = cursor.getString(cursor.getColumnIndexOrThrow(Email.DATA1));                   
    Toast.makeText(this, "Contect LIST  =  "+name, Toast.LENGTH_LONG).show();            
      

【讨论】：

谢谢！我感谢您的回复，但这对我没有帮助......它仍然显示联系人姓名而不是号码！

【参考方案3】：

// phone numbers

   int _contact_id=10111; // your contact id
   Cursor curPhone = null;

   // 1 = home ,2= personal(mobile), 3= work

   try 

       Uri URI_PHONE = ContactsContract.CommonDataKinds.Phone.CONTENT_URI;
       String[] PROJECTION_PHONE = new String[]
                            ContactsContract.CommonDataKinds.Phone.NUMBER,
                            ContactsContract.CommonDataKinds.Phone.LABEL,
                            ContactsContract.CommonDataKinds.Phone.TYPE;
      String SELECTION_PHONE = ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = ?";
      String[] SELECTION_ARRAY_PHONE = new String[]String.valueOf(_contact_id);

      curPhone = context.getContentResolver()
                 .query(URI_PHONE, PROJECTION_PHONE, SELECTION_PHONE, SELECTION_ARRAY_PHONE, null);

      if (curPhone.getCount() > 0) 

         curPhone.moveToFirst();
         int indexNumber = curPhone.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER);
         int labelIndex = curPhone.getColumnIndex(ContactsContract.CommonDataKinds.Phone.LABEL);
         int indexPhoneType = curPhone.getColumnIndex(ContactsContract.CommonDataKinds.Phone.TYPE);
          while (!curPhone.isAfterLast()) 
                   String contactNumber = curPhone.getString(indexNumber);
                   String labelName = "";
                   int labelType = curPhone.getInt(indexPhoneType);
                   if (labelType ==ContactsContract.CommonDataKinds.Phone.TYPE_CUSTOM) 
                          labelName = curPhone.getString(labelIndex);
                     
           android.util.Log.e("!_@)(@_Number:- ", contactNumber + "[" + labelType + "] " + labelName);
                   curPhone.moveToNext();
          
         else 
                    //    noPhones = true;
        
     catch (Exception e) 
       e.printStackTrace();
   finally 
       if (curPhone != null) 
           curPhone.close();
      
 

【参考方案4】：

要从您的联系人列表中获取所选联系人的联系人姓名、电话号码和电子邮件，然后只需添加此代码。

private Button btn;
private String TAG = "Contacts";
private static final int RESULT_PICK_CONTACT = 1;


btn.setOnClickListener(new View.OnClickListener()     
@Override
public void onClick(View v) 
selectSingleContact();

);

private void selectSingleContact()    
Intent contactPickerIntent = new     
Intent(Intent.ACTION_PICK,ContactsContract.CommonDataKinds.Phone.CONTENT_URI);
startActivityForResult(contactPickerIntent, RESULT_PICK_CONTACT);
    

@Override
public void onActivityResult(int requestCode, int resultCode, Intent data) 
// check whether the result is ok
if (resultCode == RESULT_OK) 
// Check for the request code, we might be usign multiple startActivityForResult
switch (requestCode) 
    case RESULT_PICK_CONTACT:
        contactPicked(data);
        break;
  
 else 
Log.e("ContactFragment", "Failed to pick contact");
   


private void contactPicked(Intent data) 

Uri uri = data.getData();
Log.i(TAG, "contactPicked() uri " + uri.toString());
Cursor cursor;
ContentResolver cr = getActivity().getContentResolver();

try 
    Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI, null, null, null, null);
if (null != cur && cur.getCount() > 0) 
    cur.moveToFirst();
    for (String column : cur.getColumnNames()) 
        Log.i(TAG, "contactPicked() Contacts column " + column + " : " + cur.getString(cur.getColumnIndex(column)));
    


if (cur.getCount() > 0) 
  //Query the content uri
    cursor = getActivity().getContentResolver().query(uri, null, null, null, null);

    if (null != cursor && cursor.getCount() > 0) 
        cursor.moveToFirst();
        for (String column : cursor.getColumnNames()) 
            Log.i(TAG, "contactPicked() uri column " + column + " : " + cursor.getString(cursor.getColumnIndex(column)));
        
    

    cursor.moveToFirst();
    id = cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts._ID));
    Log.i(TAG, "contactPicked() uri id " + id);
    String contact_id = cursor.getString(cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.CONTACT_ID));
    Log.i(TAG, "contactPicked() uri contact id " + contact_id);
    // column index of the contact name
    name = cursor.getString(cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));
    // column index of the phone number
    phoneNo = cursor.getString(cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
    //get Email id of selected contact....
    Log.e("ContactsFragment", "::>> " + id + name + phoneNo);

    Cursor cur1 = cr.query(ContactsContract.CommonDataKinds.Email.CONTENT_URI, null,
            ContactsContract.CommonDataKinds.Email.CONTACT_ID + " = ?", new String[]contact_id, null);

    if (null != cur1 && cur1.getCount() > 0) 
        cur1.moveToFirst();
        for (String column : cur1.getColumnNames()) 
            Log.i(TAG, "contactPicked() Email column " + column + " : " + cur1.getString(cur1.getColumnIndex(column)));
            email = cur1.getString(cur1.getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA));
        

       //HERE YOU GET name, phoneno & email of selected contact from contactlist.....
        Log.e("setcontactDetails","::>>" + name+"\nPhoneno:" + phoneNo+"\nEmail: " + email);
     else 
        Log.e("setcontactDetails","::>>" + name+"\nPhoneno:" + phoneNo+"\nEmail: " + email);
    
  
 catch (IndexOutOfBoundsException e) 
e.printStackTrace();
    

还为您的 AndroidManifest.xml 添加权限它适用于我，希望它也适用于您。