如何将联系人姓名、号码、contact_id 保存到 ArrayList / 联系人选择器

Posted 2023-04-15

【中文标题】如何将联系人姓名、号码、contact_id 保存到 ArrayList / 联系人选择器

【英文标题】：how to save contacts names , numbers , contact_id to ArrayList / contact picker

【发布时间】：2014-06-29 05:19:40

【问题描述】：

此活动正在运行，但我想将联系人信息（电话号码、姓名、联系人 ID）保存到 ArrayList 中。然后，我将使用 customadapter 在复选框中列出此数组列表以进行多选构造。我将在程序的后期使用联系信息。请帮助我你的想法。谢谢。

MainActivity.java

package com.javacodegeeks.android.androidphonecontactsexample;
import android.app.Activity;
import android.content.ContentResolver;
import android.database.Cursor;
import android.net.Uri;
import android.os.Bundle;
import android.provider.ContactsContract;
import android.widget.TextView;

public class MainActivity extends Activity 
    public TextView outputText;


    @Override
    public void onCreate(Bundle savedInstanceState) 
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
        outputText = (TextView) findViewById(R.id.textView1);
        fetchContacts();
    

    public void fetchContacts() 

        String phoneNumber = null;
        String email = null;
        //http://yazilimdevi.com/yazilimdevi/Makaleler-867-hashtable-vs--hashmap.aspx
        //http://***.com/questions/19974166/contacts-adding-in-arraylist-for-listview-error




        Uri CONTENT_URI = ContactsContract.Contacts.CONTENT_URI;
        String _ID = ContactsContract.Contacts._ID;
        String DISPLAY_NAME = ContactsContract.Contacts.DISPLAY_NAME;
        String HAS_PHONE_NUMBER = ContactsContract.Contacts.HAS_PHONE_NUMBER;

        Uri PhoneCONTENT_URI = ContactsContract.CommonDataKinds.Phone.CONTENT_URI;
        String Phone_CONTACT_ID = ContactsContract.CommonDataKinds.Phone.CONTACT_ID;
        String NUMBER = ContactsContract.CommonDataKinds.Phone.NUMBER;

        Uri EmailCONTENT_URI =  ContactsContract.CommonDataKinds.Email.CONTENT_URI;
        String EmailCONTACT_ID = ContactsContract.CommonDataKinds.Email.CONTACT_ID;
        String DATA = ContactsContract.CommonDataKinds.Email.DATA;


        StringBuffer output = new StringBuffer();

        ContentResolver contentResolver = getContentResolver();

        Cursor cursor = contentResolver.query(CONTENT_URI, null,null, null, null);  


        // Loop for every contact in the phone
        if (cursor.getCount() > 0) 



            while (cursor.moveToNext()) 



                String contact_id = cursor.getString(cursor.getColumnIndex( _ID ));
                String name = cursor.getString(cursor.getColumnIndex( DISPLAY_NAME ));

                int hasPhoneNumber = Integer.parseInt(cursor.getString(cursor.getColumnIndex( HAS_PHONE_NUMBER )));

                if (hasPhoneNumber > 0) 

                    output.append("\n First Name:" + name);


                    // Query and loop for every phone number of the contact
                    Cursor phoneCursor = contentResolver.query(PhoneCONTENT_URI, null, Phone_CONTACT_ID + " = ?", new String[]  contact_id , null);

                    while (phoneCursor.moveToNext()) 
                        phoneNumber = phoneCursor.getString(phoneCursor.getColumnIndex(NUMBER));
                        output.append("\n Phone number:" + phoneNumber);



                    

                    phoneCursor.close();

                    // Query and loop for every email of the contact
                    Cursor emailCursor = contentResolver.query(EmailCONTENT_URI,    null, EmailCONTACT_ID+ " = ?", new String[]  contact_id , null);

                    while (emailCursor.moveToNext()) 

                        email = emailCursor.getString(emailCursor.getColumnIndex(DATA));

                        output.append("\nEmail:" + email);


                    

                    emailCursor.close();
                

                output.append("\n");
            

            outputText.setText(output);
        
    

ma​​in.xml

<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
    xmlns:tools="http://schemas.android.com/tools"
    android:layout_
    android:layout_
    tools:context=".MainActivity" >

    <TextView
        android:id="@+id/textView"
        android:layout_
        android:layout_
        android:layout_alignParentLeft="true"
        android:layout_alignParentRight="true"
        android:layout_alignParentTop="true"
        android:layout_margin="10dp"
        android:textSize="20sp"
        android:gravity="center"
        android:text="@string/ContactsInformation" />

    <TextView
        android:id="@+id/textView1"
        android:layout_
        android:layout_
        android:layout_alignLeft="@+id/textView"
        android:layout_alignRight="@+id/textView"
        android:layout_below="@+id/textView"
        android:gravity="center"
        android:text="@string/TextView" />

    <ProgressBar
        android:id="@+id/progressBar1"
        style="?android:attr/progressBarStyleHorizontal"
        android:layout_
        android:layout_
        android:layout_above="@+id/textView1"
        android:layout_alignParentLeft="true"
        android:layout_alignParentRight="true" />

</RelativeLayout>

strings.xml

<?xml version="1.0" encoding="utf-8"?>
<resources>

    <string name="app_name">AndroidPhoneContactsExample</string>
    <string name="action_settings">Settings</string>
    <string name="hello_world">Hello world!</string>
    <string name="ContactsInformation">Contacts Information</string>
    <string name="TextView">TextView</string>
</resources>

【问题讨论】：

请求到站外资源的链接被认为是 Stack Overflow 的题外话。您尝试了什么，遇到了哪些具体问题？

对不起。我尝试了一些东西，但我删除了它们，因为有很多错误。之后我会再问一次，我在我的代码中发现了我的老问题。但我首先问了这个问题，也许有人可以从头开始指明方向。对不起我的英语：/我也看看这个链接，它与我的相似，但在那里找不到有用的答案：***.com/questions/12470363/…

我编辑了我的问题。现在，我需要使用 Arraylist 来保持联系。

【参考方案1】：

在顶部添加一个数组列表

ArrayList<String> arr = new ArrayList<String>();

然后改变你的while循环如下

 while (cursor.moveToNext()) 

            output = new StringBuffer();  //re initialize your StringBuffer again

            String contact_id = cursor.getString(cursor.getColumnIndex( _ID ));
            String name = cursor.getString(cursor.getColumnIndex( DISPLAY_NAME ));

            int hasPhoneNumber = Integer.parseInt(cursor.getString(cursor.getColumnIndex( HAS_PHONE_NUMBER )));

            if (hasPhoneNumber > 0) 

                output.append("\n First Name:" + name);


                // Query and loop for every phone number of the contact
                Cursor phoneCursor = contentResolver.query(PhoneCONTENT_URI, null, Phone_CONTACT_ID + " = ?", new String[]  contact_id , null);

                while (phoneCursor.moveToNext()) 
                    phoneNumber = phoneCursor.getString(phoneCursor.getColumnIndex(NUMBER));
                    output.append("\n Phone number:" + phoneNumber);



                

                phoneCursor.close();

                // Query and loop for every email of the contact
                Cursor emailCursor = contentResolver.query(EmailCONTENT_URI,    null, EmailCONTACT_ID+ " = ?", new String[]  contact_id , null);

                while (emailCursor.moveToNext()) 

                    email = emailCursor.getString(emailCursor.getColumnIndex(DATA));

                    output.append("\nEmail:" + email);


                

                emailCursor.close();
            

            output.append("\n");

            arr.add(output.toString());  //add contact here in your array list.
        

现在 arr 将包含所有联系人。

【讨论】：

非常感谢！另外我会问一个问题。这个 ArrayList 结构与“ ArrayList contact = ArrayList(); ”有什么区别？？我尝试使用“ArrayList contact = ArrayList();”但无法实现：/

根据您创建的数组列表。这意味着您需要一个自定义对象 Contacts ，这意味着您需要定义一个包含三个字段的类。姓名、电话、电子邮件。您将 valeus 分配给他们，然后您将存储在联系人数组列表中..:).

这个解决方案似乎花费了太多时间。我有近 900 个联系人，获取全部联系人需要将近 10 秒。