Kivy-kv语言VKeyboard

Posted 2023-04-14

【中文标题】Kivy-kv语言VKeyboard

【英文标题】：Kivy- kv language VKeyboard

【发布时间】：2017-01-16 22:07:03

【问题描述】：

我想为我使用 Kivy 1.9.0 编写的应用添加 VKeyboard 小部件。我使用 Python 2.7.12。有没有办法通过 kv 语言将此小部件添加到应用程序？因为在尝试下面的方法时存在错误：'ValueError: No JSON object could be decoded'

        Button:
            background_color:1,0,0,0.5
            text:'Next word'
            size_hint:.5,.2
            font_size:25
            pos_hint:'center_x':.5
            on_press:root.word_dict()

        VKeyboard:
            layout:'layout.json'

layout.json

  "title":"KeyboardPinyin", "description":"Keyboard using for writing pinyin characters", "cols":5, "rows":3, "normal_1":[ ["ā","ā","ā",1], ["ē","ē","ē",1], ["ī","ī","ī",1], ["ō","ō","ō",1], ["ū","ū","ū",1] ], "normal_2": [ ["á","á","á",1], ["é","é","é",1], ["í","í","í",1], ["ó","ó","ó",1], ["ú","ú","ú",1] ], "normal_3": [ ["ǎ","ǎ","ǎ",1], ["ě","ě","ě",1], ["ǐ","ǐ","ǐ",1], ["ǒ","ǒ","ǒ",1], ["ǔ","ǔ","ǔ",1] ], "normal_4": [ ["à","à","à",1], ["è","è","è",1], ["ì","ì","ì",1], ["ò","ò","ò",1], ["ù","ù","ù",1] ] 

【问题讨论】：

听起来 layout.json 不是有效的 json ...确保您遵循他们的示例 .... 或至少发布 layout.json

有 layout.json: "title":"KeyboardPinyin", "description":"用于书写拼音字符的键盘", "cols":5, "rows":3, "normal_1" :[ ["ā","ā","ā",1], ["ē","ē","ē",1], ["ī","ī","ī",1], ["ō","ō","ō",1], ["ū","ū","ū",1] ], "normal_2": [ ["á","á","á" ,1], ["é","é","é",1], ["í","í","í",1], ["ó","ó","ó",1 ], ["ú","ú","ú",1] ], "normal_3": [ ["ǎ","ǎ","ǎ",1], ["ě","ě"," ě",1], ["ǐ","ǐ","ǐ",1], ["ǒ","ǒ","ǒ",1], ["ǔ","ǔ","ǔ" ,1] ], "normal_4": [ ["à","à","à",1], ["è","è","è",1], ["ì","ì" ,"ì",1], ["ò","ò","ò",1], ["ù","ù","ù",1]

【参考方案1】：

Traceback (most recent call last):
  File "C:/Users/joran/.PyCharm50/config/scratches/scratch_33", line 3, in <module>
    data = json.load(open(os.path.expanduser("~/layout1.json")))
  File "C:\Python27\lib\json\__init__.py", line 290, in load
    **kw)
  File "C:\Python27\lib\json\__init__.py", line 338, in loads
    return _default_decoder.decode(s)
  File "C:\Python27\lib\json\decoder.py", line 366, in decode
    obj, end = self.raw_decode(s, idx=_w(s, 0).end())
  File "C:\Python27\lib\json\decoder.py", line 382, in raw_decode
    obj, end = self.scan_once(s, idx)
UnicodeDecodeError: 'utf8' codec can't decode byte 0xe1 in position 0: unexpected end of data

您不能尝试使用 utf8 解码输入...您的 json 中有非 utf8 字符

您应该改用 unicode 表示 "\u00e0" 等（或者您必须以某种方式指定 json 的字符编码......我不确定您如何临时做到这一点）

【讨论】：

在unicode中写入字符后仍然出现问题。

什么意思？请为其他人发布您的解决方案，如果正确，请接受此解决方案

我刚刚用按钮制作了 GridLayout（而不是 VKeyboard），每个按钮都包含我需要的字符，并在按下时将该字符放入 TextInput。我知道这不是问题的“真正”解决方案，但它至少有效。